leetcode-problemset/leetcode-cn/originData/minimum-cost-to-set-cooking-time.json

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        "question": {
            "questionId": "2266",
            "questionFrontendId": "2162",
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            "title": "Minimum Cost to Set Cooking Time",
            "titleSlug": "minimum-cost-to-set-cooking-time",
            "content": "<p>A generic microwave supports cooking times for:</p>\n\n<ul>\n\t<li>at least <code>1</code> second.</li>\n\t<li>at most <code>99</code> minutes and <code>99</code> seconds.</li>\n</ul>\n\n<p>To set the cooking time, you push <strong>at most four digits</strong>. The microwave normalizes what you push as four digits by <strong>prepending zeroes</strong>. It interprets the <strong>first</strong> two digits as the minutes and the <strong>last</strong> two digits as the seconds. It then <strong>adds</strong> them up as the cooking time. For example,</p>\n\n<ul>\n\t<li>You push <code>9</code> <code>5</code> <code>4</code> (three digits). It is normalized as <code>0954</code> and interpreted as <code>9</code> minutes and <code>54</code> seconds.</li>\n\t<li>You push <code>0</code> <code>0</code> <code>0</code> <code>8</code> (four digits). It is interpreted as <code>0</code> minutes and <code>8</code> seconds.</li>\n\t<li>You push <code>8</code> <code>0</code> <code>9</code> <code>0</code>. It is interpreted as <code>80</code> minutes and <code>90</code> seconds.</li>\n\t<li>You push <code>8</code> <code>1</code> <code>3</code> <code>0</code>. It is interpreted as <code>81</code> minutes and <code>30</code> seconds.</li>\n</ul>\n\n<p>You are given integers <code>startAt</code>, <code>moveCost</code>, <code>pushCost</code>, and <code>targetSeconds</code>. <strong>Initially</strong>, your finger is on the digit <code>startAt</code>. Moving the finger above <strong>any specific digit</strong> costs <code>moveCost</code> units of fatigue. Pushing the digit below the finger <strong>once</strong> costs <code>pushCost</code> units of fatigue.</p>\n\n<p>There can be multiple ways to set the microwave to cook for <code>targetSeconds</code> seconds but you are interested in the way with the minimum cost.</p>\n\n<p>Return <em>the <strong>minimum cost</strong> to set</em> <code>targetSeconds</code> <em>seconds of cooking time</em>.</p>\n\n<p>Remember that one minute consists of <code>60</code> seconds.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/30/1.png\" style=\"width: 506px; height: 210px;\" />\n<pre>\n<strong>Input:</strong> startAt = 1, moveCost = 2, pushCost = 1, targetSeconds = 600\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The following are the possible ways to set the cooking time.\n- 1 0 0 0, interpreted as 10 minutes and 0 seconds.\n&nbsp; The finger is already on digit 1, pushes 1 (with cost 1), moves to 0 (with cost 2), pushes 0 (with cost 1), pushes 0 (with cost 1), and pushes 0 (with cost 1).\n&nbsp; The cost is: 1 + 2 + 1 + 1 + 1 = 6. This is the minimum cost.\n- 0 9 6 0, interpreted as 9 minutes and 60 seconds. That is also 600 seconds.\n&nbsp; The finger moves to 0 (with cost 2), pushes 0 (with cost 1), moves to 9 (with cost 2), pushes 9 (with cost 1), moves to 6 (with cost 2), pushes 6 (with cost 1), moves to 0 (with cost 2), and pushes 0 (with cost 1).\n&nbsp; The cost is: 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 = 12.\n- 9 6 0, normalized as 0960 and interpreted as 9 minutes and 60 seconds.\n&nbsp; The finger moves to 9 (with cost 2), pushes 9 (with cost 1), moves to 6 (with cost 2), pushes 6 (with cost 1), moves to 0 (with cost 2), and pushes 0 (with cost 1).\n&nbsp; The cost is: 2 + 1 + 2 + 1 + 2 + 1 = 9.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/30/2.png\" style=\"width: 505px; height: 73px;\" />\n<pre>\n<strong>Input:</strong> startAt = 0, moveCost = 1, pushCost = 2, targetSeconds = 76\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The optimal way is to push two digits: 7 6, interpreted as 76 seconds.\nThe finger moves to 7 (with cost 1), pushes 7 (with cost 2), moves to 6 (with cost 1), and pushes 6 (with cost 2). The total cost is: 1 + 2 + 1 + 2 = 6\nNote other possible ways are 0076, 076, 0116, and 116, but none of them produces the minimum cost.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= startAt &lt;= 9</code></li>\n\t<li><code>1 &lt;= moveCost, pushCost &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= targetSeconds &lt;= 6039</code></li>\n</ul>\n",
            "translatedTitle": "设置时间的最少代价",
            "translatedContent": "<p>常见的微波炉可以设置加热时间，且加热时间满足以下条件：</p>\n\n<ul>\n\t<li>至少为 <code>1</code>&nbsp;秒钟。</li>\n\t<li>至多为&nbsp;<code>99</code>&nbsp;分&nbsp;<code>99</code>&nbsp;秒。</li>\n</ul>\n\n<p>你可以 <strong>最多</strong>&nbsp;输入&nbsp;<strong>4 个数字</strong>&nbsp;来设置加热时间。如果你输入的位数不足 4 位，微波炉会自动加 <strong>前缀</strong>&nbsp;<strong>0</strong>&nbsp;来补足 4 位。微波炉会将设置好的四位数中，<strong>前</strong>&nbsp;两位当作分钟数，<strong>后</strong>&nbsp;两位当作秒数。它们所表示的总时间就是加热时间。比方说：</p>\n\n<ul>\n\t<li>你输入&nbsp;<code>9</code> <code>5</code> <code>4</code>&nbsp;（三个数字），被自动补足为&nbsp;<code>0954</code>&nbsp;，并表示&nbsp;<code>9</code>&nbsp;分&nbsp;<code>54</code>&nbsp;秒。</li>\n\t<li>你输入&nbsp;<code>0</code> <code>0</code> <code>0</code> <code>8</code>&nbsp;（四个数字），表示&nbsp;<code>0</code>&nbsp;分&nbsp;<code>8</code>&nbsp;秒。</li>\n\t<li>你输入&nbsp;<code>8</code> <code>0</code> <code>9</code> <code>0</code>&nbsp;，表示&nbsp;<code>80</code>&nbsp;分&nbsp;<code>90</code>&nbsp;秒。</li>\n\t<li>你输入&nbsp;<code>8</code> <code>1</code> <code>3</code> <code>0</code>&nbsp;，表示&nbsp;<code>81</code>&nbsp;分&nbsp;<code>30</code>&nbsp;秒。</li>\n</ul>\n\n<p>给你整数&nbsp;<code>startAt</code>&nbsp;，<code>moveCost</code>&nbsp;，<code>pushCost</code>&nbsp;和&nbsp;<code>targetSeconds</code>&nbsp;。<strong>一开始</strong>，你的手指在数字&nbsp;<code>startAt</code>&nbsp;处。将手指移到<strong>&nbsp;任何其他数字</strong>&nbsp;，需要花费&nbsp;<code>moveCost</code>&nbsp;的单位代价。<strong>每</strong>&nbsp;输入你手指所在位置的数字一次，需要花费&nbsp;<code>pushCost</code>&nbsp;的单位代价。</p>\n\n<p>要设置&nbsp;<code>targetSeconds</code>&nbsp;秒的加热时间，可能会有多种设置方法。你想要知道这些方法中，总代价最小为多少。</p>\n\n<p>请你能返回设置&nbsp;<code>targetSeconds</code>&nbsp;秒钟加热时间需要花费的最少代价。</p>\n\n<p>请记住，虽然微波炉的秒数最多可以设置到 <code>99</code>&nbsp;秒，但一分钟等于&nbsp;<code>60</code>&nbsp;秒。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/30/1.png\" style=\"width: 506px; height: 210px;\"></p>\n\n<pre><b>输入：</b>startAt = 1, moveCost = 2, pushCost = 1, targetSeconds = 600\n<b>输出：</b>6\n<b>解释：</b>以下为设置加热时间的所有方法。\n- 1 0 0 0 ，表示 10 分 0 秒。\n&nbsp; 手指一开始就在数字 1 处，输入 1 （代价为 1），移到 0 处（代价为 2），输入 0（代价为 1），输入 0（代价为 1），输入 0（代价为 1）。\n&nbsp; 总代价为：1 + 2 + 1 + 1 + 1 = 6 。这是所有方案中的最小代价。\n- 0 9 6 0，表示 9 分 60 秒。它也表示 600 秒。\n&nbsp; 手指移到 0 处（代价为 2），输入 0 （代价为 1），移到 9 处（代价为 2），输入 9（代价为 1），移到 6 处（代价为 2），输入 6（代价为 1），移到 0 处（代价为 2），输入 0（代价为 1）。\n&nbsp; 总代价为：2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 = 12 。\n- 9 6 0，微波炉自动补全为 0960 ，表示 9 分 60 秒。\n&nbsp; 手指移到 9 处（代价为 2），输入 9 （代价为 1），移到 6 处（代价为 2），输入 6（代价为 1），移到 0 处（代价为 2），输入 0（代价为 1）。\n&nbsp; 总代价为：2 + 1 + 2 + 1 + 2 + 1 = 9 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/30/2.png\" style=\"width: 505px; height: 73px;\"></p>\n\n<pre><b>输入：</b>startAt = 0, moveCost = 1, pushCost = 2, targetSeconds = 76\n<b>输出：</b>6\n<b>解释：</b>最优方案为输入两个数字 7 6，表示 76 秒。\n手指移到 7 处（代价为 1），输入 7 （代价为 2），移到 6 处（代价为 1），输入 6（代价为 2）。总代价为：1 + 2 + 1 + 2 = 6\n其他可行方案为 0076 ，076 ，0116 和 116 ，但是它们的代价都比 6 大。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= startAt &lt;= 9</code></li>\n\t<li><code>1 &lt;= moveCost, pushCost &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= targetSeconds &lt;= 6039</code></li>\n</ul>\n",
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                "Define a separate function Cost(mm, ss) where 0 <= mm <= 99 and 0 <= ss <= 99. This function should calculate the cost of setting the cocking time to mm minutes and ss seconds",
                "The range of the minutes is small (i.e., [0, 99]), how can you use that?",
                "For every mm in [0, 99], calculate the needed ss to make mm:ss equal to targetSeconds and minimize the cost of setting the cocking time to mm:ss",
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