leetcode-problemset/leetcode-cn/originData/merge-in-between-linked-lists.json

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        "question": {
            "questionId": "1765",
            "questionFrontendId": "1669",
            "categoryTitle": "Algorithms",
            "boundTopicId": 499815,
            "title": "Merge In Between Linked Lists",
            "titleSlug": "merge-in-between-linked-lists",
            "content": "<p>You are given two linked lists: <code>list1</code> and <code>list2</code> of sizes <code>n</code> and <code>m</code> respectively.</p>\n\n<p>Remove <code>list1</code>&#39;s nodes from the <code>a<sup>th</sup></code> node to the <code>b<sup>th</sup></code> node, and put <code>list2</code> in their place.</p>\n\n<p>The blue edges and nodes in the following figure indicate the result:</p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/05/fig1.png\" style=\"height: 130px; width: 504px;\" />\n<p><em>Build the result list and return its head.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/05/merge_linked_list_ex1.png\" style=\"width: 406px; height: 140px;\" />\n<pre>\n<strong>Input:</strong> list1 = [0,1,2,3,4,5], a = 3, b = 4, list2 = [1000000,1000001,1000002]\n<strong>Output:</strong> [0,1,2,1000000,1000001,1000002,5]\n<strong>Explanation:</strong> We remove the nodes 3 and 4 and put the entire list2 in their place. The blue edges and nodes in the above figure indicate the result.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/05/merge_linked_list_ex2.png\" style=\"width: 463px; height: 140px;\" />\n<pre>\n<strong>Input:</strong> list1 = [0,1,2,3,4,5,6], a = 2, b = 5, list2 = [1000000,1000001,1000002,1000003,1000004]\n<strong>Output:</strong> [0,1,1000000,1000001,1000002,1000003,1000004,6]\n<strong>Explanation:</strong> The blue edges and nodes in the above figure indicate the result.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= list1.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= a &lt;= b &lt; list1.length - 1</code></li>\n\t<li><code>1 &lt;= list2.length &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "合并两个链表",
            "translatedContent": "<p>给你两个链表&nbsp;<code>list1</code> 和&nbsp;<code>list2</code>&nbsp;，它们包含的元素分别为&nbsp;<code>n</code> 个和&nbsp;<code>m</code> 个。</p>\n\n<p>请你将&nbsp;<code>list1</code>&nbsp;中下标从 <code>a</code> 到 <code>b</code> 的全部节点都删除，并将<code>list2</code>&nbsp;接在被删除节点的位置。</p>\n\n<p>下图中蓝色边和节点展示了操作后的结果：</p>\n<img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/28/fig1.png\" style=\"height: 130px; width: 504px;\" />\n<p>请你返回结果链表的头指针。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/28/merge_linked_list_ex1.png\" style=\"width: 406px; height: 140px;\" /></p>\n\n<pre>\n<b>输入：</b>list1 = [0,1,2,3,4,5], a = 3, b = 4, list2 = [1000000,1000001,1000002]\n<b>输出：</b>[0,1,2,1000000,1000001,1000002,5]\n<b>解释：</b>我们删除 list1 中下标为 3 和 4 的两个节点，并将 list2 接在该位置。上图中蓝色的边和节点为答案链表。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/28/merge_linked_list_ex2.png\" style=\"width: 463px; height: 140px;\" />\n<pre>\n<b>输入：</b>list1 = [0,1,2,3,4,5,6], a = 2, b = 5, list2 = [1000000,1000001,1000002,1000003,1000004]\n<b>输出：</b>[0,1,1000000,1000001,1000002,1000003,1000004,6]\n<b>解释：</b>上图中蓝色的边和节点为答案链表。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= list1.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= a &lt;= b &lt; list1.length - 1</code></li>\n\t<li><code>1 &lt;= list2.length &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    ListNode* mergeInBetween(ListNode* list1, int a, int b, ListNode* list2) {\n        \n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public ListNode mergeInBetween(ListNode list1, int a, int b, ListNode list2) {\n        \n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def mergeInBetween(self, list1, a, b, list2):\n        \"\"\"\n        :type list1: ListNode\n        :type a: int\n        :type b: int\n        :type list2: ListNode\n        :rtype: ListNode\n        \"\"\"\n        ",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\n\n\nstruct ListNode* mergeInBetween(struct ListNode* list1, int a, int b, struct ListNode* list2){\n\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public ListNode MergeInBetween(ListNode list1, int a, int b, ListNode list2) {\n        \n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init() { self.val = 0; self.next = nil; }\n *     public init(_ val: Int) { self.val = val; self.next = nil; }\n *     public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n    func mergeInBetween(_ list1: ListNode?, _ a: Int, _ b: Int, _ list2: ListNode?) -> ListNode? {\n        \n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc mergeInBetween(list1 *ListNode, a int, b int, list2 *ListNode) *ListNode {\n    \n}",
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                "Check which edges need to be changed.",
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