mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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182 lines
22 KiB
JSON
182 lines
22 KiB
JSON
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"title": "Maximum Sum Obtained of Any Permutation",
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"content": "<p>We have an array of integers, <code>nums</code>, and an array of <code>requests</code> where <code>requests[i] = [start<sub>i</sub>, end<sub>i</sub>]</code>. The <code>i<sup>th</sup></code> request asks for the sum of <code>nums[start<sub>i</sub>] + nums[start<sub>i</sub> + 1] + ... + nums[end<sub>i</sub> - 1] + nums[end<sub>i</sub>]</code>. Both <code>start<sub>i</sub></code> and <code>end<sub>i</sub></code> are <em>0-indexed</em>.</p>\n\n<p>Return <em>the maximum total sum of all requests <strong>among all permutations</strong> of</em> <code>nums</code>.</p>\n\n<p>Since the answer may be too large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5], requests = [[1,3],[0,1]]\n<strong>Output:</strong> 19\n<strong>Explanation:</strong> One permutation of nums is [2,1,3,4,5] with the following result: \nrequests[0] -> nums[1] + nums[2] + nums[3] = 1 + 3 + 4 = 8\nrequests[1] -> nums[0] + nums[1] = 2 + 1 = 3\nTotal sum: 8 + 3 = 11.\nA permutation with a higher total sum is [3,5,4,2,1] with the following result:\nrequests[0] -> nums[1] + nums[2] + nums[3] = 5 + 4 + 2 = 11\nrequests[1] -> nums[0] + nums[1] = 3 + 5 = 8\nTotal sum: 11 + 8 = 19, which is the best that you can do.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5,6], requests = [[0,1]]\n<strong>Output:</strong> 11\n<strong>Explanation:</strong> A permutation with the max total sum is [6,5,4,3,2,1] with request sums [11].</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5,10], requests = [[0,2],[1,3],[1,1]]\n<strong>Output:</strong> 47\n<strong>Explanation:</strong> A permutation with the max total sum is [4,10,5,3,2,1] with request sums [19,18,10].</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= requests.length <= 10<sup>5</sup></code></li>\n\t<li><code>requests[i].length == 2</code></li>\n\t<li><code>0 <= start<sub>i</sub> <= end<sub>i</sub> < n</code></li>\n</ul>\n",
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"translatedTitle": "所有排列中的最大和",
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"translatedContent": "<p>有一个整数数组 <code>nums</code> ,和一个查询数组 <code>requests</code> ,其中 <code>requests[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> 。第 <code>i</code> 个查询求 <code>nums[start<sub>i</sub>] + nums[start<sub>i</sub> + 1] + ... + nums[end<sub>i</sub> - 1] + nums[end<sub>i</sub>]</code> 的结果 ,<code>start<sub>i</sub></code> 和 <code>end<sub>i</sub></code> 数组索引都是 <strong>从 0 开始</strong> 的。</p>\n\n<p>你可以任意排列 <code>nums</code> 中的数字,请你返回所有查询结果之和的最大值。</p>\n\n<p>由于答案可能会很大,请你将它对 <code>10<sup>9</sup> + 7</code> <strong>取余</strong> 后返回。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>nums = [1,2,3,4,5], requests = [[1,3],[0,1]]\n<strong>输出:</strong>19\n<strong>解释:</strong>一个可行的 nums 排列为 [2,1,3,4,5],并有如下结果:\nrequests[0] -> nums[1] + nums[2] + nums[3] = 1 + 3 + 4 = 8\nrequests[1] -> nums[0] + nums[1] = 2 + 1 = 3\n总和为:8 + 3 = 11。\n一个总和更大的排列为 [3,5,4,2,1],并有如下结果:\nrequests[0] -> nums[1] + nums[2] + nums[3] = 5 + 4 + 2 = 11\nrequests[1] -> nums[0] + nums[1] = 3 + 5 = 8\n总和为: 11 + 8 = 19,这个方案是所有排列中查询之和最大的结果。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>nums = [1,2,3,4,5,6], requests = [[0,1]]\n<strong>输出:</strong>11\n<strong>解释:</strong>一个总和最大的排列为 [6,5,4,3,2,1] ,查询和为 [11]。</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong>nums = [1,2,3,4,5,10], requests = [[0,2],[1,3],[1,1]]\n<strong>输出:</strong>47\n<strong>解释:</strong>一个和最大的排列为 [4,10,5,3,2,1] ,查询结果分别为 [19,18,10]。</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= requests.length <= 10<sup>5</sup></code></li>\n\t<li><code>requests[i].length == 2</code></li>\n\t<li><code>0 <= start<sub>i</sub> <= end<sub>i</sub> < n</code></li>\n</ul>\n",
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