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"question": {
"questionId": "1424",
"questionFrontendId": "1298",
"categoryTitle": "Algorithms",
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"title": "Maximum Candies You Can Get from Boxes",
"titleSlug": "maximum-candies-you-can-get-from-boxes",
"content": "<p>You have <code>n</code> boxes labeled from <code>0</code> to <code>n - 1</code>. You are given four arrays: <code>status</code>, <code>candies</code>, <code>keys</code>, and <code>containedBoxes</code> where:</p>\n\n<ul>\n\t<li><code>status[i]</code> is <code>1</code> if the <code>i<sup>th</sup></code> box is open and <code>0</code> if the <code>i<sup>th</sup></code> box is closed,</li>\n\t<li><code>candies[i]</code> is the number of candies in the <code>i<sup>th</sup></code> box,</li>\n\t<li><code>keys[i]</code> is a list of the labels of the boxes you can open after opening the <code>i<sup>th</sup></code> box.</li>\n\t<li><code>containedBoxes[i]</code> is a list of the boxes you found inside the <code>i<sup>th</sup></code> box.</li>\n</ul>\n\n<p>You are given an integer array <code>initialBoxes</code> that contains the labels of the boxes you initially have. You can take all the candies in <strong>any open box</strong> and you can use the keys in it to open new boxes and you also can use the boxes you find in it.</p>\n\n<p>Return <em>the maximum number of candies you can get following the rules above</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> status = [1,0,1,0], candies = [7,5,4,100], keys = [[],[],[1],[]], containedBoxes = [[1,2],[3],[],[]], initialBoxes = [0]\n<strong>Output:</strong> 16\n<strong>Explanation:</strong> You will be initially given box 0. You will find 7 candies in it and boxes 1 and 2.\nBox 1 is closed and you do not have a key for it so you will open box 2. You will find 4 candies and a key to box 1 in box 2.\nIn box 1, you will find 5 candies and box 3 but you will not find a key to box 3 so box 3 will remain closed.\nTotal number of candies collected = 7 + 4 + 5 = 16 candy.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> status = [1,0,0,0,0,0], candies = [1,1,1,1,1,1], keys = [[1,2,3,4,5],[],[],[],[],[]], containedBoxes = [[1,2,3,4,5],[],[],[],[],[]], initialBoxes = [0]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> You have initially box 0. Opening it you can find boxes 1,2,3,4 and 5 and their keys.\nThe total number of candies will be 6.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == status.length == candies.length == keys.length == containedBoxes.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>status[i]</code> is either <code>0</code> or <code>1</code>.</li>\n\t<li><code>1 &lt;= candies[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= keys[i].length &lt;= n</code></li>\n\t<li><code>0 &lt;= keys[i][j] &lt; n</code></li>\n\t<li>All values of <code>keys[i]</code> are <strong>unique</strong>.</li>\n\t<li><code>0 &lt;= containedBoxes[i].length &lt;= n</code></li>\n\t<li><code>0 &lt;= containedBoxes[i][j] &lt; n</code></li>\n\t<li>All values of <code>containedBoxes[i]</code> are unique.</li>\n\t<li>Each box is contained in one box at most.</li>\n\t<li><code>0 &lt;= initialBoxes.length &lt;= n</code></li>\n\t<li><code>0 &lt;= initialBoxes[i] &lt; n</code></li>\n</ul>\n",
"translatedTitle": "你能从盒子里获得的最大糖果数",
"translatedContent": "<p>给你&nbsp;<code>n</code>&nbsp;个盒子,每个盒子的格式为&nbsp;<code>[status, candies, keys, containedBoxes]</code>&nbsp;,其中:</p>\n\n<ul>\n\t<li>状态字&nbsp;<code>status[i]</code>:整数,如果&nbsp;<code>box[i]</code>&nbsp;是开的,那么是 <strong>1&nbsp;</strong>,否则是 <strong>0&nbsp;</strong>。</li>\n\t<li>糖果数&nbsp;<code>candies[i]</code>: 整数,表示&nbsp;<code>box[i]</code> 中糖果的数目。</li>\n\t<li>钥匙&nbsp;<code>keys[i]</code>:数组,表示你打开&nbsp;<code>box[i]</code>&nbsp;后,可以得到一些盒子的钥匙,每个元素分别为该钥匙对应盒子的下标。</li>\n\t<li>内含的盒子&nbsp;<code>containedBoxes[i]</code>:整数,表示放在&nbsp;<code>box[i]</code>&nbsp;里的盒子所对应的下标。</li>\n</ul>\n\n<p>给你一个&nbsp;<code>initialBoxes</code> 数组,表示你现在得到的盒子,你可以获得里面的糖果,也可以用盒子里的钥匙打开新的盒子,还可以继续探索从这个盒子里找到的其他盒子。</p>\n\n<p>请你按照上述规则,返回可以获得糖果的 <strong>最大数目&nbsp;</strong>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>status = [1,0,1,0], candies = [7,5,4,100], keys = [[],[],[1],[]], containedBoxes = [[1,2],[3],[],[]], initialBoxes = [0]\n<strong>输出:</strong>16\n<strong>解释:\n</strong>一开始你有盒子 0 。你将获得它里面的 7 个糖果和盒子 1 和 2。\n盒子 1 目前状态是关闭的,而且你还没有对应它的钥匙。所以你将会打开盒子 2 ,并得到里面的 4 个糖果和盒子 1 的钥匙。\n在盒子 1 中,你会获得 5 个糖果和盒子 3 ,但是你没法获得盒子 3 的钥匙所以盒子 3 会保持关闭状态。\n你总共可以获得的糖果数目 = 7 + 4 + 5 = 16 个。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><strong>输入:</strong>status = [1,0,0,0,0,0], candies = [1,1,1,1,1,1], keys = [[1,2,3,4,5],[],[],[],[],[]], containedBoxes = [[1,2,3,4,5],[],[],[],[],[]], initialBoxes = [0]\n<strong>输出:</strong>6\n<strong>解释:\n</strong>你一开始拥有盒子 0 。打开它你可以找到盒子 1,2,3,4,5 和它们对应的钥匙。\n打开这些盒子你将获得所有盒子的糖果所以总糖果数为 6 个。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre><strong>输入:</strong>status = [1,1,1], candies = [100,1,100], keys = [[],[0,2],[]], containedBoxes = [[],[],[]], initialBoxes = [1]\n<strong>输出:</strong>1\n</pre>\n\n<p><strong>示例 4</strong></p>\n\n<pre><strong>输入:</strong>status = [1], candies = [100], keys = [[]], containedBoxes = [[]], initialBoxes = []\n<strong>输出:</strong>0\n</pre>\n\n<p><strong>示例 5</strong></p>\n\n<pre><strong>输入:</strong>status = [1,1,1], candies = [2,3,2], keys = [[],[],[]], containedBoxes = [[],[],[]], initialBoxes = [2,1,0]\n<strong>输出:</strong>7\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= status.length &lt;= 1000</code></li>\n\t<li><code>status.length == candies.length == keys.length == containedBoxes.length == n</code></li>\n\t<li><code>status[i]</code> 要么是&nbsp;<code>0</code>&nbsp;要么是&nbsp;<code>1</code> 。</li>\n\t<li><code>1 &lt;= candies[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= keys[i].length &lt;= status.length</code></li>\n\t<li><code>0 &lt;= keys[i][j] &lt; status.length</code></li>\n\t<li><code>keys[i]</code>&nbsp;中的值都是互不相同的。</li>\n\t<li><code>0 &lt;= containedBoxes[i].length &lt;= status.length</code></li>\n\t<li><code>0 &lt;= containedBoxes[i][j] &lt; status.length</code></li>\n\t<li><code>containedBoxes[i]</code>&nbsp;中的值都是互不相同的。</li>\n\t<li>每个盒子最多被一个盒子包含。</li>\n\t<li><code>0 &lt;= initialBoxes.length&nbsp;&lt;= status.length</code></li>\n\t<li><code>0 &lt;= initialBoxes[i] &lt; status.length</code></li>\n</ul>\n",
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