leetcode-problemset/leetcode-cn/originData/maximum-bags-with-full-capacity-of-rocks.json

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            "questionId": "2366",
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            "categoryTitle": "Algorithms",
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            "title": "Maximum Bags With Full Capacity of Rocks",
            "titleSlug": "maximum-bags-with-full-capacity-of-rocks",
            "content": "<p>You have <code>n</code> bags numbered from <code>0</code> to <code>n - 1</code>. You are given two <strong>0-indexed</strong> integer arrays <code>capacity</code> and <code>rocks</code>. The <code>i<sup>th</sup></code> bag can hold a maximum of <code>capacity[i]</code> rocks and currently contains <code>rocks[i]</code> rocks. You are also given an integer <code>additionalRocks</code>, the number of additional rocks you can place in <strong>any</strong> of the bags.</p>\n\n<p>Return<em> the <strong>maximum</strong> number of bags that could have full capacity after placing the additional rocks in some bags.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> capacity = [2,3,4,5], rocks = [1,2,4,4], additionalRocks = 2\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nPlace 1 rock in bag 0 and 1 rock in bag 1.\nThe number of rocks in each bag are now [2,3,4,4].\nBags 0, 1, and 2 have full capacity.\nThere are 3 bags at full capacity, so we return 3.\nIt can be shown that it is not possible to have more than 3 bags at full capacity.\nNote that there may be other ways of placing the rocks that result in an answer of 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> capacity = [10,2,2], rocks = [2,2,0], additionalRocks = 100\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nPlace 8 rocks in bag 0 and 2 rocks in bag 2.\nThe number of rocks in each bag are now [10,2,2].\nBags 0, 1, and 2 have full capacity.\nThere are 3 bags at full capacity, so we return 3.\nIt can be shown that it is not possible to have more than 3 bags at full capacity.\nNote that we did not use all of the additional rocks.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == capacity.length == rocks.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= capacity[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= rocks[i] &lt;= capacity[i]</code></li>\n\t<li><code>1 &lt;= additionalRocks &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "装满石头的背包的最大数量",
            "translatedContent": "<p>现有编号从&nbsp;<code>0</code> 到 <code>n - 1</code> 的 <code>n</code> 个背包。给你两个下标从 <strong>0</strong> 开始的整数数组 <code>capacity</code> 和 <code>rocks</code> 。第 <code>i</code> 个背包最大可以装 <code>capacity[i]</code> 块石头，当前已经装了 <code>rocks[i]</code> 块石头。另给你一个整数 <code>additionalRocks</code> ，表示<span class=\"text-only\" data-eleid=\"10\" style=\"white-space: pre;\">你可以放置的额外石头数量，石头可以往 </span><strong><span class=\"text-only\" data-eleid=\"11\" style=\"white-space: pre;\">任意</span></strong><span class=\"text-only\" data-eleid=\"12\" style=\"white-space: pre;\"> 背包中放置。</span></p>\n\n<p>请你将额外的石头放入一些背包中，并返回放置后装满石头的背包的 <strong>最大 </strong>数量<em>。</em></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>capacity = [2,3,4,5], rocks = [1,2,4,4], additionalRocks = 2\n<strong>输出：</strong>3\n<strong>解释：</strong>\n1 块石头放入背包 0 ，1 块石头放入背包 1 。\n每个背包中的石头总数是 [2,3,4,4] 。\n背包 0 、背包 1 和 背包 2 都装满石头。\n总计 3 个背包装满石头，所以返回 3 。\n可以证明不存在超过 3 个背包装满石头的情况。\n注意，可能存在其他放置石头的方案同样能够得到 3 这个结果。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>capacity = [10,2,2], rocks = [2,2,0], additionalRocks = 100\n<strong>输出：</strong>3\n<strong>解释：</strong>\n8 块石头放入背包 0 ，2 块石头放入背包 2 。\n每个背包中的石头总数是 [10,2,2] 。\n背包 0 、背包 1 和背包 2 都装满石头。\n总计 3 个背包装满石头，所以返回 3 。\n可以证明不存在超过 3 个背包装满石头的情况。\n注意，不必用完所有的额外石头。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == capacity.length == rocks.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= capacity[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= rocks[i] &lt;= capacity[i]</code></li>\n\t<li><code>1 &lt;= additionalRocks &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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