leetcode-problemset/leetcode-cn/originData/maximum-absolute-sum-of-any-subarray.json

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        "question": {
            "questionId": "1849",
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            "title": "Maximum Absolute Sum of Any Subarray",
            "titleSlug": "maximum-absolute-sum-of-any-subarray",
            "content": "<p>You are given an integer array <code>nums</code>. The <strong>absolute sum</strong> of a subarray <code>[nums<sub>l</sub>, nums<sub>l+1</sub>, ..., nums<sub>r-1</sub>, nums<sub>r</sub>]</code> is <code>abs(nums<sub>l</sub> + nums<sub>l+1</sub> + ... + nums<sub>r-1</sub> + nums<sub>r</sub>)</code>.</p>\n\n<p>Return <em>the <strong>maximum</strong> absolute sum of any <strong>(possibly empty)</strong> subarray of </em><code>nums</code>.</p>\n\n<p>Note that <code>abs(x)</code> is defined as follows:</p>\n\n<ul>\n\t<li>If <code>x</code> is a negative integer, then <code>abs(x) = -x</code>.</li>\n\t<li>If <code>x</code> is a non-negative integer, then <code>abs(x) = x</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,-3,2,3,-4]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,-5,1,-4,3,-2]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "任意子数组和的绝对值的最大值",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> 。一个子数组 <code>[nums<sub>l</sub>, nums<sub>l+1</sub>, ..., nums<sub>r-1</sub>, nums<sub>r</sub>]</code> 的 <strong>和的绝对值</strong> 为 <code>abs(nums<sub>l</sub> + nums<sub>l+1</sub> + ... + nums<sub>r-1</sub> + nums<sub>r</sub>)</code> 。</p>\n\n<p>请你找出 <code>nums</code> 中 <strong>和的绝对值</strong> 最大的任意子数组（<b>可能为空</b>），并返回该 <strong>最大值</strong> 。</p>\n\n<p><code>abs(x)</code> 定义如下：</p>\n\n<ul>\n\t<li>如果 <code>x</code> 是负整数，那么 <code>abs(x) = -x</code> 。</li>\n\t<li>如果 <code>x</code> 是非负整数，那么 <code>abs(x) = x</code> 。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,-3,2,3,-4]\n<b>输出：</b>5\n<b>解释：</b>子数组 [2,3] 和的绝对值最大，为 abs(2+3) = abs(5) = 5 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [2,-5,1,-4,3,-2]\n<b>输出：</b>8\n<b>解释：</b>子数组 [-5,1,-4] 和的绝对值最大，为 abs(-5+1-4) = abs(-8) = 8 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n</ul>\n",
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            "hints": [
                "What if we asked for maximum sum, not absolute sum?",
                "It's a standard problem that can be solved by Kadane's algorithm.",
                "The key idea is the max absolute sum will be either the max sum or the min sum.",
                "So just run kadane twice, once calculating the max sum and once calculating the min sum."
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