mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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171 lines
22 KiB
JSON
171 lines
22 KiB
JSON
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"categoryTitle": "Algorithms",
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"title": "Kth Smallest Product of Two Sorted Arrays",
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"content": "Given two <strong>sorted 0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code> as well as an integer <code>k</code>, return <em>the </em><code>k<sup>th</sup></code><em> (<strong>1-based</strong>) smallest product of </em><code>nums1[i] * nums2[j]</code><em> where </em><code>0 <= i < nums1.length</code><em> and </em><code>0 <= j < nums2.length</code>.\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,5], nums2 = [3,4], k = 2\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> The 2 smallest products are:\n- nums1[0] * nums2[0] = 2 * 3 = 6\n- nums1[0] * nums2[1] = 2 * 4 = 8\nThe 2<sup>nd</sup> smallest product is 8.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [-4,-2,0,3], nums2 = [2,4], k = 6\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The 6 smallest products are:\n- nums1[0] * nums2[1] = (-4) * 4 = -16\n- nums1[0] * nums2[0] = (-4) * 2 = -8\n- nums1[1] * nums2[1] = (-2) * 4 = -8\n- nums1[1] * nums2[0] = (-2) * 2 = -4\n- nums1[2] * nums2[0] = 0 * 2 = 0\n- nums1[2] * nums2[1] = 0 * 4 = 0\nThe 6<sup>th</sup> smallest product is 0.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [-2,-1,0,1,2], nums2 = [-3,-1,2,4,5], k = 3\n<strong>Output:</strong> -6\n<strong>Explanation:</strong> The 3 smallest products are:\n- nums1[0] * nums2[4] = (-2) * 5 = -10\n- nums1[0] * nums2[3] = (-2) * 4 = -8\n- nums1[4] * nums2[0] = 2 * (-3) = -6\nThe 3<sup>rd</sup> smallest product is -6.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums1.length, nums2.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= nums1[i], nums2[j] <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= k <= nums1.length * nums2.length</code></li>\n\t<li><code>nums1</code> and <code>nums2</code> are sorted.</li>\n</ul>\n",
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"translatedTitle": "两个有序数组的第 K 小乘积",
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"translatedContent": "给你两个 <strong>从小到大排好序</strong> 且下标从 <strong>0</strong> 开始的整数数组 <code>nums1</code> 和 <code>nums2</code> 以及一个整数 <code>k</code> ,请你返回第<em> </em><code>k</code> (从 <strong>1</strong> 开始编号)小的 <code>nums1[i] * nums2[j]</code><em> </em>的乘积,其中<em> </em><code>0 <= i < nums1.length</code><em> </em>且<em> </em><code>0 <= j < nums2.length</code> 。\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><b>输入:</b>nums1 = [2,5], nums2 = [3,4], k = 2\n<b>输出:</b>8\n<b>解释:</b>第 2 小的乘积计算如下:\n- nums1[0] * nums2[0] = 2 * 3 = 6\n- nums1[0] * nums2[1] = 2 * 4 = 8\n第 2 小的乘积为 8 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><b>输入:</b>nums1 = [-4,-2,0,3], nums2 = [2,4], k = 6\n<b>输出:</b>0\n<strong>解释:</strong>第 6 小的乘积计算如下:\n- nums1[0] * nums2[1] = (-4) * 4 = -16\n- nums1[0] * nums2[0] = (-4) * 2 = -8\n- nums1[1] * nums2[1] = (-2) * 4 = -8\n- nums1[1] * nums2[0] = (-2) * 2 = -4\n- nums1[2] * nums2[0] = 0 * 2 = 0\n- nums1[2] * nums2[1] = 0 * 4 = 0\n第 6 小的乘积为 0 。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><b>输入:</b>nums1 = [-2,-1,0,1,2], nums2 = [-3,-1,2,4,5], k = 3\n<b>输出:</b>-6\n<b>解释:</b>第 3 小的乘积计算如下:\n- nums1[0] * nums2[4] = (-2) * 5 = -10\n- nums1[0] * nums2[3] = (-2) * 4 = -8\n- nums1[4] * nums2[0] = 2 * (-3) = -6\n第 3 小的乘积为 -6 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums1.length, nums2.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= nums1[i], nums2[j] <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= k <= nums1.length * nums2.length</code></li>\n\t<li><code>nums1</code> 和 <code>nums2</code> 都是从小到大排好序的。</li>\n</ul>\n",
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