leetcode-problemset/leetcode-cn/originData/k-diff-pairs-in-an-array.json

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            "title": "K-diff Pairs in an Array",
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            "content": "<p>Given an array of integers <code>nums</code> and an integer <code>k</code>, return <em>the number of <b>unique</b> k-diff pairs in the array</em>.</p>\n\n<p>A <strong>k-diff</strong> pair is an integer pair <code>(nums[i], nums[j])</code>, where the following are true:</p>\n\n<ul>\n\t<li><code>0 &lt;= i, j &lt; nums.length</code></li>\n\t<li><code>i != j</code></li>\n\t<li><code>nums[i] - nums[j] == k</code></li>\n</ul>\n\n<p><strong>Notice</strong> that <code>|val|</code> denotes the absolute value of <code>val</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,4,1,5], k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> There are two 2-diff pairs in the array, (1, 3) and (3, 5).\nAlthough we have two 1s in the input, we should only return the number of <strong>unique</strong> pairs.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5], k = 1\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> There are four 1-diff pairs in the array, (1, 2), (2, 3), (3, 4) and (4, 5).\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,1,5,4], k = 0\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> There is one 0-diff pair in the array, (1, 1).\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>7</sup> &lt;= nums[i] &lt;= 10<sup>7</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>7</sup></code></li>\n</ul>\n",
            "translatedTitle": "数组中的 k-diff 数对",
            "translatedContent": "<p>给定一个整数数组和一个整数&nbsp;<code><strong>k</strong></code>，你需要在数组里找到<strong> 不同的&nbsp;</strong>k-diff 数对，并返回不同的 <strong>k-diff 数对</strong> 的数目。</p>\n\n<p>这里将&nbsp;<strong>k-diff</strong>&nbsp;数对定义为一个整数对 <code>(nums[i], nums[j])</code>，并满足下述全部条件：</p>\n\n<ul>\n\t<li><code>0 &lt;= i &lt; j &lt; nums.length</code></li>\n\t<li><code>|nums[i] - nums[j]| == k</code></li>\n</ul>\n\n<p><strong>注意</strong>，<code>|val|</code> 表示 <code>val</code> 的绝对值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3, 1, 4, 1, 5], k = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>数组中有两个 2-diff 数对, (1, 3) 和 (3, 5)。\n尽管数组中有两个1，但我们只应返回不同的数对的数量。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1, 2, 3, 4, 5], k = 1\n<strong>输出：</strong>4\n<strong>解释：</strong>数组中有四个 1-diff 数对, (1, 2), (2, 3), (3, 4) 和 (4, 5)。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1, 3, 1, 5, 4], k = 0\n<strong>输出：</strong>1\n<strong>解释：</strong>数组中只有一个 0-diff 数对，(1, 1)。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>7</sup> &lt;= nums[i] &lt;= 10<sup>7</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>7</sup></code></li>\n</ul>\n",
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