leetcode-problemset/leetcode-cn/originData/invalid-transactions.json

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        "question": {
            "questionId": "1272",
            "questionFrontendId": "1169",
            "categoryTitle": "Algorithms",
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            "title": "Invalid Transactions",
            "titleSlug": "invalid-transactions",
            "content": "<p>A transaction is possibly invalid if:</p>\n\n<ul>\n\t<li>the amount exceeds <code>$1000</code>, or;</li>\n\t<li>if it occurs within (and including) <code>60</code> minutes of another transaction with the <strong>same name</strong> in a <strong>different city</strong>.</li>\n</ul>\n\n<p>You are given an array of strings <code>transaction</code> where <code>transactions[i]</code> consists of comma-separated values representing the name, time (in minutes), amount, and city of the transaction.</p>\n\n<p>Return a list of <code>transactions</code> that are possibly invalid. You may return the answer in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> transactions = [&quot;alice,20,800,mtv&quot;,&quot;alice,50,100,beijing&quot;]\n<strong>Output:</strong> [&quot;alice,20,800,mtv&quot;,&quot;alice,50,100,beijing&quot;]\n<strong>Explanation:</strong> The first transaction is invalid because the second transaction occurs within a difference of 60 minutes, have the same name and is in a different city. Similarly the second one is invalid too.</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> transactions = [&quot;alice,20,800,mtv&quot;,&quot;alice,50,1200,mtv&quot;]\n<strong>Output:</strong> [&quot;alice,50,1200,mtv&quot;]\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> transactions = [&quot;alice,20,800,mtv&quot;,&quot;bob,50,1200,mtv&quot;]\n<strong>Output:</strong> [&quot;bob,50,1200,mtv&quot;]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>transactions.length &lt;= 1000</code></li>\n\t<li>Each <code>transactions[i]</code> takes the form <code>&quot;{name},{time},{amount},{city}&quot;</code></li>\n\t<li>Each <code>{name}</code> and <code>{city}</code> consist of lowercase English letters, and have lengths between <code>1</code> and <code>10</code>.</li>\n\t<li>Each <code>{time}</code> consist of digits, and represent an integer between <code>0</code> and <code>1000</code>.</li>\n\t<li>Each <code>{amount}</code> consist of digits, and represent an integer between <code>0</code> and <code>2000</code>.</li>\n</ul>\n",
            "translatedTitle": "查询无效交易",
            "translatedContent": "<p>如果出现下述两种情况，交易 <strong>可能无效</strong>：</p>\n\n<ul>\n\t<li>交易金额超过<meta charset=\"UTF-8\" />&nbsp;<code>$1000</code></li>\n\t<li>或者，它和&nbsp;<strong>另一个城市</strong>&nbsp;中 <strong>同名</strong> 的另一笔交易相隔不超过 <code>60</code> 分钟（包含 60 分钟整）</li>\n</ul>\n\n<p>给定字符串数组交易清单<meta charset=\"UTF-8\" />&nbsp;<code>transaction</code>&nbsp;。每个交易字符串&nbsp;<code>transactions[i]</code>&nbsp;由一些用逗号分隔的值组成，这些值分别表示交易的名称，时间（以分钟计），金额以及城市。</p>\n\n<p>返回&nbsp;<code>transactions</code>，返回可能无效的交易列表。你可以按 <strong>任何顺序</strong> 返回答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>transactions = [\"alice,20,800,mtv\",\"alice,50,100,beijing\"]\n<strong>输出：</strong>[\"alice,20,800,mtv\",\"alice,50,100,beijing\"]\n<strong>解释：</strong>第一笔交易是无效的，因为第二笔交易和它间隔不超过 60 分钟、名称相同且发生在不同的城市。同样，第二笔交易也是无效的。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>transactions = [\"alice,20,800,mtv\",\"alice,50,1200,mtv\"]\n<strong>输出：</strong>[\"alice,50,1200,mtv\"]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>transactions = [\"alice,20,800,mtv\",\"bob,50,1200,mtv\"]\n<strong>输出：</strong>[\"bob,50,1200,mtv\"]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>transactions.length &lt;= 1000</code></li>\n\t<li>每笔交易&nbsp;<code>transactions[i]</code>&nbsp;按&nbsp;<code>\"{name},{time},{amount},{city}\"</code>&nbsp;的格式进行记录</li>\n\t<li>每个交易名称&nbsp;<code>{name}</code>&nbsp;和城市&nbsp;<code>{city}</code>&nbsp;都由小写英文字母组成，长度在&nbsp;<code>1</code>&nbsp;到&nbsp;<code>10</code>&nbsp;之间</li>\n\t<li>每个交易时间&nbsp;<code>{time}</code>&nbsp;由一些数字组成，表示一个&nbsp;<code>0</code>&nbsp;到&nbsp;<code>1000</code>&nbsp;之间的整数</li>\n\t<li>每笔交易金额&nbsp;<code>{amount}</code>&nbsp;由一些数字组成，表示一个&nbsp;<code>0</code> 到&nbsp;<code>2000</code>&nbsp;之间的整数</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<string> invalidTransactions(vector<string>& transactions) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def invalidTransactions(self, transactions):\n        \"\"\"\n        :type transactions: List[str]\n        :rtype: List[str]\n        \"\"\"",
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                    "code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar ** invalidTransactions(char ** transactions, int transactionsSize, int* returnSize){\n\n}",
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                    "code": "public class Solution {\n    public IList<string> InvalidTransactions(string[] transactions) {\n\n    }\n}",
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                    "code": "/**\n * @param {string[]} transactions\n * @return {string[]}\n */\nvar invalidTransactions = function(transactions) {\n\n};",
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                    "code": "# @param {String[]} transactions\n# @return {String[]}\ndef invalid_transactions(transactions)\n\nend",
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                    "code": "impl Solution {\n    pub fn invalid_transactions(transactions: Vec<String>) -> Vec<String> {\n\n    }\n}",
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                    "code": "class Solution {\n\n    /**\n     * @param String[] $transactions\n     * @return String[]\n     */\n    function invalidTransactions($transactions) {\n\n    }\n}",
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            "hints": [
                "Split each string into four arrays.",
                "For each transaction check if it's invalid, you can do this with just a loop with help of the four arrays generated on step 1.",
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