leetcode-problemset/leetcode-cn/originData/find-latest-group-of-size-m.json

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            "title": "Find Latest Group of Size M",
            "titleSlug": "find-latest-group-of-size-m",
            "content": "<p>Given an array <code>arr</code> that represents a permutation of numbers from <code>1</code> to <code>n</code>.</p>\n\n<p>You have a binary string of size <code>n</code> that initially has all its bits set to zero. At each step <code>i</code> (assuming both the binary string and <code>arr</code> are 1-indexed) from <code>1</code> to <code>n</code>, the bit at position <code>arr[i]</code> is set to <code>1</code>.</p>\n\n<p>You are also given an integer <code>m</code>. Find the latest step at which there exists a group of ones of length <code>m</code>. A group of ones is a contiguous substring of <code>1</code>&#39;s such that it cannot be extended in either direction.</p>\n\n<p>Return <em>the latest step at which there exists a group of ones of length <strong>exactly</strong></em> <code>m</code>. <em>If no such group exists, return</em> <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [3,5,1,2,4], m = 1\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> \nStep 1: &quot;00<u>1</u>00&quot;, groups: [&quot;1&quot;]\nStep 2: &quot;0010<u>1</u>&quot;, groups: [&quot;1&quot;, &quot;1&quot;]\nStep 3: &quot;<u>1</u>0101&quot;, groups: [&quot;1&quot;, &quot;1&quot;, &quot;1&quot;]\nStep 4: &quot;1<u>1</u>101&quot;, groups: [&quot;111&quot;, &quot;1&quot;]\nStep 5: &quot;111<u>1</u>1&quot;, groups: [&quot;11111&quot;]\nThe latest step at which there exists a group of size 1 is step 4.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [3,1,5,4,2], m = 2\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> \nStep 1: &quot;00<u>1</u>00&quot;, groups: [&quot;1&quot;]\nStep 2: &quot;<u>1</u>0100&quot;, groups: [&quot;1&quot;, &quot;1&quot;]\nStep 3: &quot;1010<u>1</u>&quot;, groups: [&quot;1&quot;, &quot;1&quot;, &quot;1&quot;]\nStep 4: &quot;101<u>1</u>1&quot;, groups: [&quot;1&quot;, &quot;111&quot;]\nStep 5: &quot;1<u>1</u>111&quot;, groups: [&quot;11111&quot;]\nNo group of size 2 exists during any step.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == arr.length</code></li>\n\t<li><code>1 &lt;= m &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= arr[i] &lt;= n</code></li>\n\t<li>All integers in <code>arr</code> are <strong>distinct</strong>.</li>\n</ul>\n",
            "translatedTitle": "查找大小为 M 的最新分组",
            "translatedContent": "<p>给你一个数组 <code>arr</code> ，该数组表示一个从 <code>1</code> 到 <code>n</code> 的数字排列。有一个长度为 <code>n</code> 的二进制字符串，该字符串上的所有位最初都设置为 <code>0</code> 。</p>\n\n<p>在从 <code>1</code> 到 <code>n</code> 的每个步骤 <code>i</code> 中（假设二进制字符串和 <code>arr</code> 都是从 <code>1</code> 开始索引的情况下），二进制字符串上位于位置 <code>arr[i]</code> 的位将会设为 <code>1</code> 。</p>\n\n<p>给你一个整数 <code>m</code> ，请你找出二进制字符串上存在长度为 <code>m</code> 的一组 <code>1</code> 的最后步骤。一组 <code>1</code> 是一个连续的、由 <code>1</code> 组成的子串，且左右两边不再有可以延伸的 <code>1</code> 。</p>\n\n<p>返回存在长度 <strong>恰好</strong> 为 <code>m</code> 的 <strong>一组 <code>1</code>&nbsp;</strong> 的最后步骤。如果不存在这样的步骤，请返回 <code>-1</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>arr = [3,5,1,2,4], m = 1\n<strong>输出：</strong>4\n<strong>解释：\n</strong>步骤 1：&quot;00<strong>1</strong>00&quot;，由 1 构成的组：[&quot;1&quot;]\n步骤 2：&quot;0010<strong>1</strong>&quot;，由 1 构成的组：[&quot;1&quot;, &quot;1&quot;]\n步骤 3：&quot;<strong>1</strong>0101&quot;，由 1 构成的组：[&quot;1&quot;, &quot;1&quot;, &quot;1&quot;]\n步骤 4：&quot;1<strong>1</strong>101&quot;，由 1 构成的组：[&quot;111&quot;, &quot;1&quot;]\n步骤 5：&quot;111<strong>1</strong>1&quot;，由 1 构成的组：[&quot;11111&quot;]\n存在长度为 1 的一组 1 的最后步骤是步骤 4 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>arr = [3,1,5,4,2], m = 2\n<strong>输出：</strong>-1\n<strong>解释：\n</strong>步骤 1：&quot;00<strong>1</strong>00&quot;，由 1 构成的组：[&quot;1&quot;]\n步骤 2：&quot;<strong>1</strong>0100&quot;，由 1 构成的组：[&quot;1&quot;, &quot;1&quot;]\n步骤 3：&quot;1010<strong>1</strong>&quot;，由 1 构成的组：[&quot;1&quot;, &quot;1&quot;, &quot;1&quot;]\n步骤 4：&quot;101<strong>1</strong>1&quot;，由 1 构成的组：[&quot;1&quot;, &quot;111&quot;]\n步骤 5：&quot;1<strong>1</strong>111&quot;，由 1 构成的组：[&quot;11111&quot;]\n不管是哪一步骤都无法形成长度为 2 的一组 1 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>arr = [1], m = 1\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>arr = [2,1], m = 2\n<strong>输出：</strong>2\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == arr.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10^5</code></li>\n\t<li><code>1 &lt;= arr[i] &lt;= n</code></li>\n\t<li><code>arr</code> 中的所有整数 <strong>互不相同</strong></li>\n\t<li><code>1 &lt;= m&nbsp;&lt;= arr.length</code></li>\n</ul>\n",
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                "Since the problem asks for the latest step, can you start the searching from the end of arr?",
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