leetcode-problemset/leetcode-cn/originData/decode-xored-array.json

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        "question": {
            "questionId": "1839",
            "questionFrontendId": "1720",
            "categoryTitle": "Algorithms",
            "boundTopicId": 549347,
            "title": "Decode XORed Array",
            "titleSlug": "decode-xored-array",
            "content": "<p>There is a <strong>hidden</strong> integer array <code>arr</code> that consists of <code>n</code> non-negative integers.</p>\n\n<p>It was encoded into another integer array <code>encoded</code> of length <code>n - 1</code>, such that <code>encoded[i] = arr[i] XOR arr[i + 1]</code>. For example, if <code>arr = [1,0,2,1]</code>, then <code>encoded = [1,2,3]</code>.</p>\n\n<p>You are given the <code>encoded</code> array. You are also given an integer <code>first</code>, that is the first element of <code>arr</code>, i.e. <code>arr[0]</code>.</p>\n\n<p>Return <em>the original array</em> <code>arr</code>. It can be proved that the answer exists and is unique.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> encoded = [1,2,3], first = 1\n<strong>Output:</strong> [1,0,2,1]\n<strong>Explanation:</strong> If arr = [1,0,2,1], then first = 1 and encoded = [1 XOR 0, 0 XOR 2, 2 XOR 1] = [1,2,3]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> encoded = [6,2,7,3], first = 4\n<strong>Output:</strong> [4,2,0,7,4]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>encoded.length == n - 1</code></li>\n\t<li><code>0 &lt;= encoded[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= first &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "解码异或后的数组",
            "translatedContent": "<p><strong>未知</strong> 整数数组 <code>arr</code> 由 <code>n</code> 个非负整数组成。</p>\n\n<p>经编码后变为长度为 <code>n - 1</code> 的另一个整数数组 <code>encoded</code> ，其中 <code>encoded[i] = arr[i] XOR arr[i + 1]</code> 。例如，<code>arr = [1,0,2,1]</code> 经编码后得到 <code>encoded = [1,2,3]</code> 。</p>\n\n<p>给你编码后的数组 <code>encoded</code> 和原数组 <code>arr</code> 的第一个元素 <code>first</code>（<code>arr[0]</code>）。</p>\n\n<p>请解码返回原数组 <code>arr</code> 。可以证明答案存在并且是唯一的。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>encoded = [1,2,3], first = 1\n<strong>输出：</strong>[1,0,2,1]\n<strong>解释：</strong>若 arr = [1,0,2,1] ，那么 first = 1 且 encoded = [1 XOR 0, 0 XOR 2, 2 XOR 1] = [1,2,3]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>encoded = [6,2,7,3], first = 4\n<strong>输出：</strong>[4,2,0,7,4]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 <= n <= 10<sup>4</sup></code></li>\n\t<li><code>encoded.length == n - 1</code></li>\n\t<li><code>0 <= encoded[i] <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= first <= 10<sup>5</sup></code></li>\n</ul>\n",
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                {
                    "name": "Bit Manipulation",
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                    "code": "class Solution {\npublic:\n    vector<int> decode(vector<int>& encoded, int first) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def decode(self, encoded, first):\n        \"\"\"\n        :type encoded: List[int]\n        :type first: int\n        :rtype: List[int]\n        \"\"\"",
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                    "code": "# @param {Integer[]} encoded\n# @param {Integer} first\n# @return {Integer[]}\ndef decode(encoded, first)\n\nend",
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            "hints": [
                "Since that encoded[i] = arr[i] XOR arr[i+1], then arr[i+1] = encoded[i] XOR arr[i].",
                "Iterate on i from beginning to end, and set arr[i+1] = encoded[i] XOR arr[i]."
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