mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
186 lines
26 KiB
JSON
186 lines
26 KiB
JSON
{
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"questionId": "108",
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"questionFrontendId": "108",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1223,
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"title": "Convert Sorted Array to Binary Search Tree",
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"titleSlug": "convert-sorted-array-to-binary-search-tree",
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"content": "<p>Given an integer array <code>nums</code> where the elements are sorted in <strong>ascending order</strong>, convert <em>it to a <strong>height-balanced</strong> binary search tree</em>.</p>\n\n<p>A <strong>height-balanced</strong> binary tree is a binary tree in which the depth of the two subtrees of every node never differs by more than one.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/18/btree1.jpg\" style=\"width: 302px; height: 222px;\" />\n<pre>\n<strong>Input:</strong> nums = [-10,-3,0,5,9]\n<strong>Output:</strong> [0,-3,9,-10,null,5]\n<strong>Explanation:</strong> [0,-10,5,null,-3,null,9] is also accepted:\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/18/btree2.jpg\" style=\"width: 302px; height: 222px;\" />\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/18/btree.jpg\" style=\"width: 342px; height: 142px;\" />\n<pre>\n<strong>Input:</strong> nums = [1,3]\n<strong>Output:</strong> [3,1]\n<strong>Explanation:</strong> [1,null,3] and [3,1] are both height-balanced BSTs.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n\t<li><code>nums</code> is sorted in a <strong>strictly increasing</strong> order.</li>\n</ul>\n",
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"translatedTitle": "将有序数组转换为二叉搜索树",
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"translatedContent": "<p>给你一个整数数组 <code>nums</code> ，其中元素已经按 <strong>升序</strong> 排列，请你将其转换为一棵 <strong>高度平衡</strong> 二叉搜索树。</p>\n\n<p><strong>高度平衡 </strong>二叉树是一棵满足「每个节点的左右两个子树的高度差的绝对值不超过 1 」的二叉树。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/18/btree1.jpg\" style=\"width: 302px; height: 222px;\" />\n<pre>\n<strong>输入：</strong>nums = [-10,-3,0,5,9]\n<strong>输出：</strong>[0,-3,9,-10,null,5]\n<strong>解释：</strong>[0,-10,5,null,-3,null,9] 也将被视为正确答案：\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/18/btree2.jpg\" style=\"width: 302px; height: 222px;\" />\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/18/btree.jpg\" style=\"width: 342px; height: 142px;\" />\n<pre>\n<strong>输入：</strong>nums = [1,3]\n<strong>输出：</strong>[3,1]\n<strong>解释：</strong>[1,null,3] 和 [3,1] 都是高度平衡二叉搜索树。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n\t<li><code>nums</code> 按 <strong>严格递增</strong> 顺序排列</li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode SortedArrayToBST(int[] nums) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {number[]} nums\n * @return {TreeNode}\n */\nvar sortedArrayToBST = function(nums) {\n\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {Integer[]} nums\n# @return {TreeNode}\ndef sorted_array_to_bst(nums)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func sortedArrayToBST(_ nums: [Int]) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def sortedArrayToBST(nums: Array[Int]): TreeNode = {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun sortedArrayToBST(nums: IntArray): TreeNode? {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn sorted_array_to_bst(nums: Vec<i32>) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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