leetcode-problemset/leetcode-cn/originData/contains-duplicate.json

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            "categoryTitle": "Algorithms",
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            "title": "Contains Duplicate",
            "titleSlug": "contains-duplicate",
            "content": "<p>Given an integer array <code>nums</code>, return <code>true</code> if any value appears <strong>at least twice</strong> in the array, and return <code>false</code> if every element is distinct.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> nums = [1,2,3,1]\n<strong>Output:</strong> true\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> nums = [1,2,3,4]\n<strong>Output:</strong> false\n</pre><p><strong>Example 3:</strong></p>\n<pre><strong>Input:</strong> nums = [1,1,1,3,3,4,3,2,4,2]\n<strong>Output:</strong> true\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "存在重复元素",
            "translatedContent": "给你一个整数数组 <code>nums</code> 。如果任一值在数组中出现 <strong>至少两次</strong> ，返回 <code>true</code> ；如果数组中每个元素互不相同，返回 <code>false</code> 。\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,1]\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4]\n<strong>输出：</strong>false</pre>\n\n<p><strong>示例&nbsp;3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,1,3,3,4,3,2,4,2]\n<strong>输出：</strong>true</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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