mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
189 lines
21 KiB
JSON
189 lines
21 KiB
JSON
{
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"boundTopicId": 1342,
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"title": "Contains Duplicate III",
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"content": "<p>Given an integer array <code>nums</code> and two integers <code>k</code> and <code>t</code>, return <code>true</code> if there are <strong>two distinct indices</strong> <code>i</code> and <code>j</code> in the array such that <code>abs(nums[i] - nums[j]) <= t</code> and <code>abs(i - j) <= k</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> nums = [1,2,3,1], k = 3, t = 0\n<strong>Output:</strong> true\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> nums = [1,0,1,1], k = 1, t = 2\n<strong>Output:</strong> true\n</pre><p><strong>Example 3:</strong></p>\n<pre><strong>Input:</strong> nums = [1,5,9,1,5,9], k = 2, t = 3\n<strong>Output:</strong> false\n</pre>\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>0 <= k <= 10<sup>4</sup></code></li>\n\t<li><code>0 <= t <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"translatedTitle": "存在重复元素 III",
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"translatedContent": "<p>给你一个整数数组 <code>nums</code> 和两个整数 <code>k</code> 和 <code>t</code> 。请你判断是否存在 <b>两个不同下标</b> <code>i</code> 和 <code>j</code>，使得 <code>abs(nums[i] - nums[j]) <= t</code> ，同时又满足 <code>abs(i - j) <= k</code><em> </em>。</p>\n\n<p>如果存在则返回 <code>true</code>，不存在返回 <code>false</code>。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,1], k<em> </em>= 3, t = 0\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,0,1,1], k<em> </em>=<em> </em>1, t = 2\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,5,9,1,5,9], k = 2, t = 3\n<strong>输出：</strong>false</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= nums.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>0 <= k <= 10<sup>4</sup></code></li>\n\t<li><code>0 <= t <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"Time complexity O(n logk) - This will give an indication that sorting is involved for k elements.",
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"Use already existing state to evaluate next state - Like, a set of k sorted numbers are only needed to be tracked. When we are processing the next number in array, then we can utilize the existing sorted state and it is not necessary to sort next overlapping set of k numbers again."
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