leetcode-problemset/leetcode-cn/originData/construct-string-with-repeat-limit.json

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        "question": {
            "questionId": "2300",
            "questionFrontendId": "2182",
            "categoryTitle": "Algorithms",
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            "title": "Construct String With Repeat Limit",
            "titleSlug": "construct-string-with-repeat-limit",
            "content": "<p>You are given a string <code>s</code> and an integer <code>repeatLimit</code>. Construct a new string <code>repeatLimitedString</code> using the characters of <code>s</code> such that no letter appears <strong>more than</strong> <code>repeatLimit</code> times <strong>in a row</strong>. You do <strong>not</strong> have to use all characters from <code>s</code>.</p>\n\n<p>Return <em>the <strong>lexicographically largest</strong> </em><code>repeatLimitedString</code> <em>possible</em>.</p>\n\n<p>A string <code>a</code> is <strong>lexicographically larger</strong> than a string <code>b</code> if in the first position where <code>a</code> and <code>b</code> differ, string <code>a</code> has a letter that appears later in the alphabet than the corresponding letter in <code>b</code>. If the first <code>min(a.length, b.length)</code> characters do not differ, then the longer string is the lexicographically larger one.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;cczazcc&quot;, repeatLimit = 3\n<strong>Output:</strong> &quot;zzcccac&quot;\n<strong>Explanation:</strong> We use all of the characters from s to construct the repeatLimitedString &quot;zzcccac&quot;.\nThe letter &#39;a&#39; appears at most 1 time in a row.\nThe letter &#39;c&#39; appears at most 3 times in a row.\nThe letter &#39;z&#39; appears at most 2 times in a row.\nHence, no letter appears more than repeatLimit times in a row and the string is a valid repeatLimitedString.\nThe string is the lexicographically largest repeatLimitedString possible so we return &quot;zzcccac&quot;.\nNote that the string &quot;zzcccca&quot; is lexicographically larger but the letter &#39;c&#39; appears more than 3 times in a row, so it is not a valid repeatLimitedString.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aababab&quot;, repeatLimit = 2\n<strong>Output:</strong> &quot;bbabaa&quot;\n<strong>Explanation:</strong> We use only some of the characters from s to construct the repeatLimitedString &quot;bbabaa&quot;. \nThe letter &#39;a&#39; appears at most 2 times in a row.\nThe letter &#39;b&#39; appears at most 2 times in a row.\nHence, no letter appears more than repeatLimit times in a row and the string is a valid repeatLimitedString.\nThe string is the lexicographically largest repeatLimitedString possible so we return &quot;bbabaa&quot;.\nNote that the string &quot;bbabaaa&quot; is lexicographically larger but the letter &#39;a&#39; appears more than 2 times in a row, so it is not a valid repeatLimitedString.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= repeatLimit &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "构造限制重复的字符串",
            "translatedContent": "<p>给你一个字符串 <code>s</code> 和一个整数 <code>repeatLimit</code> ，用 <code>s</code> 中的字符构造一个新字符串 <code>repeatLimitedString</code> ，使任何字母 <strong>连续</strong> 出现的次数都不超过 <code>repeatLimit</code> 次。你不必使用 <code>s</code> 中的全部字符。</p>\n\n<p>返回 <strong>字典序最大的</strong><em> </em><code>repeatLimitedString</code> 。</p>\n\n<p>如果在字符串 <code>a</code> 和 <code>b</code> 不同的第一个位置，字符串 <code>a</code> 中的字母在字母表中出现时间比字符串 <code>b</code> 对应的字母晚，则认为字符串 <code>a</code> 比字符串 <code>b</code> <strong>字典序更大</strong> 。如果字符串中前 <code>min(a.length, b.length)</code> 个字符都相同，那么较长的字符串字典序更大。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = \"cczazcc\", repeatLimit = 3\n<strong>输出：</strong>\"zzcccac\"\n<strong>解释：</strong>使用 s 中的所有字符来构造 repeatLimitedString \"zzcccac\"。\n字母 'a' 连续出现至多 1 次。\n字母 'c' 连续出现至多 3 次。\n字母 'z' 连续出现至多 2 次。\n因此，没有字母连续出现超过 repeatLimit 次，字符串是一个有效的 repeatLimitedString 。\n该字符串是字典序最大的 repeatLimitedString ，所以返回 \"zzcccac\" 。\n注意，尽管 \"zzcccca\" 字典序更大，但字母 'c' 连续出现超过 3 次，所以它不是一个有效的 repeatLimitedString 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = \"aababab\", repeatLimit = 2\n<strong>输出：</strong>\"bbabaa\"\n<strong>解释：</strong>\n使用 s 中的一些字符来构造 repeatLimitedString \"bbabaa\"。 \n字母 'a' 连续出现至多 2 次。 \n字母 'b' 连续出现至多 2 次。 \n因此，没有字母连续出现超过 repeatLimit 次，字符串是一个有效的 repeatLimitedString 。 \n该字符串是字典序最大的 repeatLimitedString ，所以返回 \"bbabaa\" 。 \n注意，尽管 \"bbabaaa\" 字典序更大，但字母 'a' 连续出现超过 2 次，所以它不是一个有效的 repeatLimitedString 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= repeatLimit &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 由小写英文字母组成</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    string repeatLimitedString(string s, int repeatLimit) {\n        \n    }\n};",
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                    "code": "/**\n * @param {string} s\n * @param {number} repeatLimit\n * @return {string}\n */\nvar repeatLimitedString = function(s, repeatLimit) {\n\n};",
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                "Start constructing the string in descending order of characters.",
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