mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
26 KiB
JSON
180 lines
26 KiB
JSON
{
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"question": {
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"questionId": "94",
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"questionFrontendId": "94",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1116,
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"title": "Binary Tree Inorder Traversal",
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"titleSlug": "binary-tree-inorder-traversal",
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"content": "<p>Given the <code>root</code> of a binary tree, return <em>the inorder traversal of its nodes' values</em>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg\" style=\"width: 125px; height: 200px;\" />\n<pre>\n<strong>Input:</strong> root = [1,null,2,3]\n<strong>Output:</strong> [1,3,2]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = []\n<strong>Output:</strong> []\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [1]\n<strong>Output:</strong> [1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[0, 100]</code>.</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n</ul>\n\n<p> </p>\n<strong>Follow up:</strong> Recursive solution is trivial, could you do it iteratively?",
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"translatedTitle": "二叉树的中序遍历",
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"translatedContent": "<p>给定一个二叉树的根节点 <code>root</code> ，返回 <em>它的 <strong>中序</strong> 遍历</em> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg\" style=\"height: 200px; width: 125px;\" />\n<pre>\n<strong>输入：</strong>root = [1,null,2,3]\n<strong>输出：</strong>[1,3,2]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = []\n<strong>输出：</strong>[]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [1]\n<strong>输出：</strong>[1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目在范围 <code>[0, 100]</code> 内</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶:</strong> 递归算法很简单，你可以通过迭代算法完成吗？</p>\n",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun inorderTraversal(root: TreeNode?): List<Int> {\n\n }\n}",
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