leetcode-problemset/leetcode-cn/originData/you-le-yuan-de-you-lan-ji-hua.json

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            "questionId": "1000085",
            "questionFrontendId": "LCP 16",
            "categoryTitle": "Algorithms",
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            "title": "游乐园的游览计划",
            "titleSlug": "you-le-yuan-de-you-lan-ji-hua",
            "content": "English description is not available for the problem. Please switch to Chinese.",
            "translatedTitle": "游乐园的游览计划",
            "translatedContent": "<p>又到了一年一度的春游时间，小吴计划去游乐场游玩 1 天，游乐场总共有 <code>N</code> 个游乐项目，编号从 <code>0</code> 到 <code>N-1</code>。小吴给每个游乐项目定义了一个非负整数值 <code>value[i]</code> 表示自己的喜爱值。两个游乐项目之间会有双向路径相连，整个游乐场总共有 <code>M</code> 条双向路径，保存在二维数组&nbsp;<code>edges</code>中。 小吴计划选择一个游乐项目 <code>A</code> 作为这一天游玩的重点项目。上午小吴准备游玩重点项目 <code>A</code> 以及与项目 <code>A</code> 相邻的两个项目 <code>B</code>、<code>C</code> （项目<code>A</code>、<code>B</code>与<code>C</code>要求是不同的项目，且项目<code>B</code>与项目<code>C</code>要求相邻），并返回 <code>A</code> ，即存在一条 <code>A-B-C-A</code> 的路径。 下午，小吴决定再游玩重点项目 <code>A</code>以及与<code>A</code>相邻的两个项目 <code>B&#39;</code>、<code>C&#39;</code>，（项目<code>A</code>、<code>B&#39;</code>与<code>C&#39;</code>要求是不同的项目，且项目<code>B&#39;</code>与项目<code>C&#39;</code>要求相邻），并返回 <code>A</code> ，即存在一条 <code>A-B&#39;-C&#39;-A</code> 的路径。下午游玩项目 <code>B&#39;</code>、<code>C&#39;</code> 可与上午游玩项目<code>B</code>、<code>C</code>存在重复项目。 小吴希望提前安排好游玩路径，使得喜爱值之和最大。请你返回满足游玩路径选取条件的最大喜爱值之和，如果没有这样的路径，返回 <code>0</code>。 注意：一天中重复游玩同一个项目并不能重复增加喜爱值了。例如：上下午游玩路径分别是 <code>A-B-C-A</code>与<code>A-C-D-A</code> 那么只能获得 <code>value[A] + value[B] + value[C] + value[D]</code> 的总和。</p>\n\n<p><strong>示例 1：</strong></p>\n\n<blockquote>\n<p>输入：<code>edges = [[0,1],[1,2],[0,2]], value = [1,2,3]</code></p>\n\n<p>输出：<code>6</code></p>\n\n<p>解释：喜爱值之和最高的方案之一是 0-&gt;1-&gt;2-&gt;0 与 0-&gt;2-&gt;1-&gt;0 。重复游玩同一点不重复计入喜爱值，返回1+2+3=6</p>\n</blockquote>\n\n<p><strong>示例 2：</strong></p>\n\n<blockquote>\n<p>输入：<code>edges = [[0,2],[2,1]], value = [1,2,5]</code></p>\n\n<p>输出：<code>0</code></p>\n\n<p>解释：无满足要求的游玩路径，返回 0</p>\n</blockquote>\n\n<p><strong>示例 3：</strong></p>\n\n<blockquote>\n<p>输入：<code>edges = [[0,1],[0,2],[0,3],[0,4],[0,5],[1,3],[2,4],[2,5],[3,4],[3,5],[4,5]], value = [7,8,6,8,9,7]</code></p>\n\n<p>输出：<code>39</code></p>\n\n<p>解释：喜爱值之和最高的方案之一是 3-&gt;0-&gt;1-&gt;3 与 3-&gt;4-&gt;5-&gt;3 。喜爱值最高为 7+8+8+9+7=39</p>\n</blockquote>\n\n<p><strong>限制：</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= value.length &lt;= 10000</code></li>\n\t<li><code>1 &lt;=&nbsp;edges.length &lt;= 10000</code></li>\n\t<li><code>0 &lt;= edges[i][0],edges[i][1] &lt;&nbsp;value.length</code></li>\n\t<li><code>0 &lt;= value[i] &lt;= 10000</code></li>\n\t<li><code>edges中没有重复的边</code></li>\n\t<li><code>edges[i][0] != edges[i][1]</code></li>\n</ul>\n",
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