mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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195 lines
24 KiB
JSON
195 lines
24 KiB
JSON
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"title": "Two Best Non-Overlapping Events",
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"content": "<p>You are given a <strong>0-indexed</strong> 2D integer array of <code>events</code> where <code>events[i] = [startTime<sub>i</sub>, endTime<sub>i</sub>, value<sub>i</sub>]</code>. The <code>i<sup>th</sup></code> event starts at <code>startTime<sub>i</sub></code><sub> </sub>and ends at <code>endTime<sub>i</sub></code>, and if you attend this event, you will receive a value of <code>value<sub>i</sub></code>. You can choose <strong>at most</strong> <strong>two</strong> <strong>non-overlapping</strong> events to attend such that the sum of their values is <strong>maximized</strong>.</p>\n\n<p>Return <em>this <strong>maximum</strong> sum.</em></p>\n\n<p>Note that the start time and end time is <strong>inclusive</strong>: that is, you cannot attend two events where one of them starts and the other ends at the same time. More specifically, if you attend an event with end time <code>t</code>, the next event must start at or after <code>t + 1</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture5.png\" style=\"width: 400px; height: 75px;\" />\n<pre>\n<strong>Input:</strong> events = [[1,3,2],[4,5,2],[2,4,3]]\n<strong>Output:</strong> 4\n<strong>Explanation: </strong>Choose the green events, 0 and 1 for a sum of 2 + 2 = 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"Example 1 Diagram\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture1.png\" style=\"width: 400px; height: 77px;\" />\n<pre>\n<strong>Input:</strong> events = [[1,3,2],[4,5,2],[1,5,5]]\n<strong>Output:</strong> 5\n<strong>Explanation: </strong>Choose event 2 for a sum of 5.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture3.png\" style=\"width: 400px; height: 66px;\" />\n<pre>\n<strong>Input:</strong> events = [[1,5,3],[1,5,1],[6,6,5]]\n<strong>Output:</strong> 8\n<strong>Explanation: </strong>Choose events 0 and 2 for a sum of 3 + 5 = 8.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= events.length <= 10<sup>5</sup></code></li>\n\t<li><code>events[i].length == 3</code></li>\n\t<li><code>1 <= startTime<sub>i</sub> <= endTime<sub>i</sub> <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= value<sub>i</sub> <= 10<sup>6</sup></code></li>\n</ul>\n",
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"translatedTitle": "两个最好的不重叠活动",
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"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的二维整数数组 <code>events</code> ,其中 <code>events[i] = [startTime<sub>i</sub>, endTime<sub>i</sub>, value<sub>i</sub>]</code> 。第 <code>i</code> 个活动开始于 <code>startTime<sub>i</sub></code> ,结束于 <code>endTime<sub>i</sub></code> ,如果你参加这个活动,那么你可以得到价值 <code>value<sub>i</sub></code> 。你 <strong>最多</strong> 可以参加 <strong>两个时间不重叠</strong> 活动,使得它们的价值之和 <strong>最大</strong> 。</p>\n\n<p>请你返回价值之和的 <strong>最大值</strong> 。</p>\n\n<p>注意,活动的开始时间和结束时间是 <strong>包括</strong> 在活动时间内的,也就是说,你不能参加两个活动且它们之一的开始时间等于另一个活动的结束时间。更具体的,如果你参加一个活动,且结束时间为 <code>t</code> ,那么下一个活动必须在 <code>t + 1</code> 或之后的时间开始。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture5.png\" style=\"width: 400px; height: 75px;\"></p>\n\n<pre><b>输入:</b>events = [[1,3,2],[4,5,2],[2,4,3]]\n<b>输出:</b>4\n<strong>解释:</strong>选择绿色的活动 0 和 1 ,价值之和为 2 + 2 = 4 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img alt=\"Example 1 Diagram\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture1.png\" style=\"width: 400px; height: 77px;\"></p>\n\n<pre><b>输入:</b>events = [[1,3,2],[4,5,2],[1,5,5]]\n<b>输出:</b>5\n<strong>解释:</strong>选择活动 2 ,价值和为 5 。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/09/21/picture3.png\" style=\"width: 400px; height: 66px;\"></p>\n\n<pre><b>输入:</b>events = [[1,5,3],[1,5,1],[6,6,5]]\n<b>输出:</b>8\n<strong>解释:</strong>选择活动 0 和 2 ,价值之和为 3 + 5 = 8 。</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 <= events.length <= 10<sup>5</sup></code></li>\n\t<li><code>events[i].length == 3</code></li>\n\t<li><code>1 <= startTime<sub>i</sub> <= endTime<sub>i</sub> <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= value<sub>i</sub> <= 10<sup>6</sup></code></li>\n</ul>\n",
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