leetcode-problemset/leetcode-cn/originData/super-egg-drop.json

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            "title": "Super Egg Drop",
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            "content": "<p>You are given <code>k</code> identical eggs and you have access to a building with <code>n</code> floors labeled from <code>1</code> to <code>n</code>.</p>\n\n<p>You know that there exists a floor <code>f</code> where <code>0 &lt;= f &lt;= n</code> such that any egg dropped at a floor <strong>higher</strong> than <code>f</code> will <strong>break</strong>, and any egg dropped <strong>at or below</strong> floor <code>f</code> will <strong>not break</strong>.</p>\n\n<p>Each move, you may take an unbroken egg and drop it from any floor <code>x</code> (where <code>1 &lt;= x &lt;= n</code>). If the egg breaks, you can no longer use it. However, if the egg does not break, you may <strong>reuse</strong> it in future moves.</p>\n\n<p>Return <em>the <strong>minimum number of moves</strong> that you need to determine <strong>with certainty</strong> what the value of </em><code>f</code> is.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> k = 1, n = 2\n<strong>Output:</strong> 2\n<strong>Explanation: </strong>\nDrop the egg from floor 1. If it breaks, we know that f = 0.\nOtherwise, drop the egg from floor 2. If it breaks, we know that f = 1.\nIf it does not break, then we know f = 2.\nHence, we need at minimum 2 moves to determine with certainty what the value of f is.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> k = 2, n = 6\n<strong>Output:</strong> 3\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> k = 3, n = 14\n<strong>Output:</strong> 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= 100</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "鸡蛋掉落",
            "translatedContent": "<p>给你 <code>k</code> 枚相同的鸡蛋，并可以使用一栋从第 <code>1</code> 层到第 <code>n</code> 层共有 <code>n</code> 层楼的建筑。</p>\n\n<p>已知存在楼层 <code>f</code> ，满足 <code>0 <= f <= n</code> ，任何从<strong> 高于</strong> <code>f</code> 的楼层落下的鸡蛋都会碎，从 <code>f</code> 楼层或比它低的楼层落下的鸡蛋都不会破。</p>\n\n<p>每次操作，你可以取一枚没有碎的鸡蛋并把它从任一楼层 <code>x</code> 扔下（满足 <code>1 <= x <= n</code>）。如果鸡蛋碎了，你就不能再次使用它。如果某枚鸡蛋扔下后没有摔碎，则可以在之后的操作中 <strong>重复使用</strong> 这枚鸡蛋。</p>\n\n<p>请你计算并返回要确定 <code>f</code> <strong>确切的值</strong> 的 <strong>最小操作次数</strong> 是多少？</p>\n \n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>k = 1, n = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>\n鸡蛋从 1 楼掉落。如果它碎了，肯定能得出 f = 0 。 \n否则，鸡蛋从 2 楼掉落。如果它碎了，肯定能得出 f = 1 。 \n如果它没碎，那么肯定能得出 f = 2 。 \n因此，在最坏的情况下我们需要移动 2 次以确定 f 是多少。 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>k = 2, n = 6\n<strong>输出：</strong>3\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>k = 3, n = 14\n<strong>输出：</strong>4\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= k <= 100</code></li>\n\t<li><code>1 <= n <= 10<sup>4</sup></code></li>\n</ul>\n",
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