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{
"data": {
"question": {
"questionId": "725",
"questionFrontendId": "725",
"categoryTitle": "Algorithms",
"boundTopicId": 1901,
"title": "Split Linked List in Parts",
"titleSlug": "split-linked-list-in-parts",
"content": "<p>Given the <code>head</code> of a singly linked list and an integer <code>k</code>, split the linked list into <code>k</code> consecutive linked list parts.</p>\n\n<p>The length of each part should be as equal as possible: no two parts should have a size differing by more than one. This may lead to some parts being null.</p>\n\n<p>The parts should be in the order of occurrence in the input list, and parts occurring earlier should always have a size greater than or equal to parts occurring later.</p>\n\n<p>Return <em>an array of the </em><code>k</code><em> parts</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/13/split1-lc.jpg\" style=\"width: 400px; height: 134px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,3], k = 5\n<strong>Output:</strong> [[1],[2],[3],[],[]]\n<strong>Explanation:</strong>\nThe first element output[0] has output[0].val = 1, output[0].next = null.\nThe last element output[4] is null, but its string representation as a ListNode is [].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/13/split2-lc.jpg\" style=\"width: 600px; height: 60px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,3,4,5,6,7,8,9,10], k = 3\n<strong>Output:</strong> [[1,2,3,4],[5,6,7],[8,9,10]]\n<strong>Explanation:</strong>\nThe input has been split into consecutive parts with size difference at most 1, and earlier parts are a larger size than the later parts.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the list is in the range <code>[0, 1000]</code>.</li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n\t<li><code>1 &lt;= k &lt;= 50</code></li>\n</ul>\n",
"translatedTitle": "分隔链表",
"translatedContent": "<p>给你一个头结点为 <code>head</code> 的单链表和一个整数 <code>k</code> ,请你设计一个算法将链表分隔为 <code>k</code> 个连续的部分。</p>\n\n<p>每部分的长度应该尽可能的相等:任意两部分的长度差距不能超过 1 。这可能会导致有些部分为 null 。</p>\n\n<p>这 <code>k</code> 个部分应该按照在链表中出现的顺序排列,并且排在前面的部分的长度应该大于或等于排在后面的长度。</p>\n\n<p>返回一个由上述 <code>k</code> 部分组成的数组。</p>\n&nbsp;\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/13/split1-lc.jpg\" style=\"width: 400px; height: 134px;\" />\n<pre>\n<strong>输入:</strong>head = [1,2,3], k = 5\n<strong>输出:</strong>[[1],[2],[3],[],[]]\n<strong>解释:</strong>\n第一个元素 output[0] 为 output[0].val = 1 output[0].next = null 。\n最后一个元素 output[4] 为 null ,但它作为 ListNode 的字符串表示是 [] 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/13/split2-lc.jpg\" style=\"width: 600px; height: 60px;\" />\n<pre>\n<strong>输入:</strong>head = [1,2,3,4,5,6,7,8,9,10], k = 3\n<strong>输出:</strong>[[1,2,3,4],[5,6,7],[8,9,10]]\n<strong>解释:</strong>\n输入被分成了几个连续的部分并且每部分的长度相差不超过 1 。前面部分的长度大于等于后面部分的长度。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>链表中节点的数目在范围 <code>[0, 1000]</code></li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n\t<li><code>1 &lt;= k &lt;= 50</code></li>\n</ul>\n",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * ListNode *next;\n * ListNode() : val(0), next(nullptr) {}\n * ListNode(int x) : val(x), next(nullptr) {}\n * ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n vector<ListNode*> splitListToParts(ListNode* head, int k) {\n\n }\n};",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def splitListToParts(self, head, k):\n \"\"\"\n :type head: ListNode\n :type k: int\n :rtype: List[ListNode]\n \"\"\"\n ",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def splitListToParts(self, head: Optional[ListNode], k: int) -> List[Optional[ListNode]]:",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public int val;\n * public ListNode next;\n * public ListNode(int val=0, ListNode next=null) {\n * this.val = val;\n * this.next = next;\n * }\n * }\n */\npublic class Solution {\n public ListNode[] SplitListToParts(ListNode head, int k) {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @param {number} k\n * @return {ListNode[]}\n */\nvar splitListToParts = function(head, k) {\n\n};",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n * val: number\n * next: ListNode | null\n * constructor(val?: number, next?: ListNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n * }\n */\n\nfunction splitListToParts(head: ListNode | null, k: number): Array<ListNode | null> {\n \n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public var val: Int\n * public var next: ListNode?\n * public init() { self.val = 0; self.next = nil; }\n * public init(_ val: Int) { self.val = val; self.next = nil; }\n * public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n func splitListToParts(_ head: ListNode?, _ k: Int) -> [ListNode?] {\n\n }\n}",
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"code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n * var next: ListNode? = null\n * }\n */\nclass Solution {\n fun splitListToParts(head: ListNode?, k: Int): Array<ListNode?> {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n * int val;\n * ListNode? next;\n * ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n List<ListNode?> splitListToParts(ListNode? head, int k) {\n \n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n * Val int\n * Next *ListNode\n * }\n */\nfunc splitListToParts(head *ListNode, k int) []*ListNode {\n\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode\n# attr_accessor :val, :next\n# def initialize(val = 0, _next = nil)\n# @val = val\n# @next = _next\n# end\n# end\n# @param {ListNode} head\n# @param {Integer} k\n# @return {ListNode[]}\ndef split_list_to_parts(head, k)\n\nend",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n * var next: ListNode = _next\n * var x: Int = _x\n * }\n */\nobject Solution {\n def splitListToParts(head: ListNode, k: Int): Array[ListNode] = {\n\n }\n}",
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"code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n// pub val: i32,\n// pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n// #[inline]\n// fn new(val: i32) -> Self {\n// ListNode {\n// next: None,\n// val\n// }\n// }\n// }\nimpl Solution {\n pub fn split_list_to_parts(head: Option<Box<ListNode>>, k: i32) -> Vec<Option<Box<ListNode>>> {\n\n }\n}",
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"lang": "Racket",
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"code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n (list-node val #f))\n\n|#\n\n(define/contract (split-list-to-parts head k)\n (-> (or/c list-node? #f) exact-integer? (listof (or/c list-node? #f)))\n )",
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"code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%% next = null :: 'null' | #list_node{}}).\n\n-spec split_list_to_parts(Head :: #list_node{} | null, K :: integer()) -> [#list_node{} | null].\nsplit_list_to_parts(Head, K) ->\n .",
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"lang": "Elixir",
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"code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# next: ListNode.t() | nil\n# }\n# defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n @spec split_list_to_parts(head :: ListNode.t | nil, k :: integer) :: [ListNode.t | nil]\n def split_list_to_parts(head, k) do\n \n end\nend",
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