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{
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"question": {
"questionId": "1170",
"questionFrontendId": "1092",
"categoryTitle": "Algorithms",
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"title": "Shortest Common Supersequence ",
"titleSlug": "shortest-common-supersequence",
"content": "<p>Given two strings <code>str1</code> and <code>str2</code>, return <em>the shortest string that has both </em><code>str1</code><em> and </em><code>str2</code><em> as <strong>subsequences</strong></em>. If there are multiple valid strings, return <strong>any</strong> of them.</p>\n\n<p>A string <code>s</code> is a <strong>subsequence</strong> of string <code>t</code> if deleting some number of characters from <code>t</code> (possibly <code>0</code>) results in the string <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;abac&quot;, str2 = &quot;cab&quot;\n<strong>Output:</strong> &quot;cabac&quot;\n<strong>Explanation:</strong> \nstr1 = &quot;abac&quot; is a subsequence of &quot;cabac&quot; because we can delete the first &quot;c&quot;.\nstr2 = &quot;cab&quot; is a subsequence of &quot;cabac&quot; because we can delete the last &quot;ac&quot;.\nThe answer provided is the shortest such string that satisfies these properties.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;aaaaaaaa&quot;, str2 = &quot;aaaaaaaa&quot;\n<strong>Output:</strong> &quot;aaaaaaaa&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>\n\t<li><code>str1</code> and <code>str2</code> consist of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "最短公共超序列",
"translatedContent": "<p>给你两个字符串&nbsp;<code>str1</code> 和&nbsp;<code>str2</code>,返回同时以&nbsp;<code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;作为 <strong>子序列</strong> 的最短字符串。如果答案不止一个,则可以返回满足条件的 <strong>任意一个</strong> 答案。</p>\n\n<p>如果从字符串 <code>t</code> 中删除一些字符(也可能不删除),可以得到字符串 <code>s</code> ,那么 <code>s</code> 就是 t 的一个子序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>str1 = \"abac\", str2 = \"cab\"\n<strong>输出:</strong>\"cabac\"\n<strong>解释:</strong>\nstr1 = \"abac\" 是 \"cabac\" 的一个子串,因为我们可以删去 \"cabac\" 的第一个 \"c\"得到 \"abac\"。 \nstr2 = \"cab\" 是 \"cabac\" 的一个子串,因为我们可以删去 \"cabac\" 末尾的 \"ac\" 得到 \"cab\"。\n最终我们给出的答案是满足上述属性的最短字符串。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>str1 = \"aaaaaaaa\", str2 = \"aaaaaaaa\"\n<strong>输出:</strong>\"aaaaaaaa\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>\n\t<li><code>str1</code> 和&nbsp;<code>str2</code>&nbsp;都由小写英文字母组成。</li>\n</ul>\n",
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"code": "class Solution(object):\n def shortestCommonSupersequence(self, str1, str2):\n \"\"\"\n :type str1: str\n :type str2: str\n :rtype: str\n \"\"\"",
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"code": "-spec shortest_common_supersequence(Str1 :: unicode:unicode_binary(), Str2 :: unicode:unicode_binary()) -> unicode:unicode_binary().\nshortest_common_supersequence(Str1, Str2) ->\n .",
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"code": "defmodule Solution do\n @spec shortest_common_supersequence(str1 :: String.t, str2 :: String.t) :: String.t\n def shortest_common_supersequence(str1, str2) do\n \n end\nend",
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"hints": [
"We can find the length of the longest common subsequence between str1[i:] and str2[j:] (for all (i, j)) by using dynamic programming.",
"We can use this information to recover the shortest common supersequence."
],
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"sampleTestCase": "\"abac\"\n\"cab\"",
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