leetcode-problemset/leetcode-cn/originData/ryfUiz.json

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        "question": {
            "questionId": "1000569",
            "questionFrontendId": "LCP 81",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2258738,
            "title": "与非的谜题",
            "titleSlug": "ryfUiz",
            "content": "English description is not available for the problem. Please switch to Chinese.",
            "translatedTitle": "与非的谜题",
            "translatedContent": "在永恒之森中，封存着有关万灵之树线索的卷轴，只要探险队通过最后的考验，便可以获取前往万灵之树的线索。\n\n探险队需要从一段不断变化的谜题数组中找到最终的密码，初始的谜题为长度为 `n` 的数组 `arr`（下标从 0 开始），数组中的数字代表了 `k` 位二进制数。\n破解谜题的过程中，需要使用 `与非（NAND）` 运算方式，`operations[i] = [type,x,y]` 表示第 `i` 次进行的谜题操作信息：\n- 若 `type = 0`，表示修改操作，将谜题数组中下标 `x` 的数字变化为 `y`；\n- 若 `type = 1`，表示运算操作，将数字 `y` 进行 `x*n` 次「与非」操作，第 `i` 次与非操作为 `y = y NAND arr[i%n]`；\n    > 运算操作结果即：`y NAND arr[0%n] NAND arr[1%n] NAND arr[2%n] ... NAND arr[(x*n-1)%n]`\n\n最后，将所有运算操作的结果按顺序逐一进行 `异或（XOR）`运算，从而得到最终解开封印的密码。请返回最终解开封印的密码。\n\n**注意:**\n- 「与非」（NAND）的操作为：先进行 `与` 操作，后进行 `非` 操作。\n    > 例如：两个三位二进制数`2`和`3`，其与非结果为 `NOT ((010) AND (011)) = (101) = 5`\n\n**示例 1：**\n> 输入: \n> `k = 3`\n> `arr = [1,2]`\n> `operations = [[1,2,3],[0,0,3],[1,2,2]]`\n>\n> 输出: `2`\n>\n> 解释：\n> 初始的谜题数组为 [1,2]，二进制位数为 3，\n> 第 0 次进行运算操作，将数字 3(011) 进行 2\\*2 次「与非」运算，\n> 运算操作结果为 `3 NAND 1 NAND 2 NAND 1 NAND 2 = 5`\n> 第 1 次进行修改操作，谜题数组的第 `0` 个数字变化为 `3`，谜题变成 `[3,2]`\n> 第 2 次进行运算操作，将数字 2(010) 进行 2\\*2 次「与非」运算，\n> 运算操作结果为 `2 NAND 3 NAND 2 NAND 3 NAND 2 = 7`\n> 所有运算操作结果进行「异或」运算为 `5 XOR 7 = 2`\n> 因此得到的最终密码为 `2`。\n\n**示例 2：**\n> 输入:\n> `k = 4`\n> `arr = [4,6,4,7,10,9,11]`\n> `operations = [[1,5,7],[1,7,14],[0,6,7],[1,6,5]]`\n> 输出: `9`\n> 解释: \n> 初始的谜题数组为 [4,6,4,7,10,9,11],\n> 第 0 次进行运算操作，运算操作结果为 5；\n> 第 1 次进行运算操作，运算操作结果为 5；\n> 第 2 次进行修改操作，修改后谜题数组为 [4, 6, 4, 7, 10, 9, 7]；\n> 第 3 次进行运算操作，运算操作结果为 9；\n> 所有运算操作结果进行「异或」运算为 `5 XOR 5 XOR 9 = 9`；\n> 因此得到的最终密码为 `9`。\n\n**提示:**\n- `1 <= arr.length, operations.length <= 10^4`\n- `1 <= k <= 30`\n- `0 <= arr[i] < 2^k`\n- 若 `type = 0`，`0 <= x < arr.length` 且 `0 <= y < 2^k`\n- 若 `type = 1`，`1 <= x < 10^9` 且 `0 <= y < 2^k`\n- 保证存在 `type = 1` 的操作\n",
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