leetcode-problemset/leetcode-cn/originData/restore-the-array-from-adjacent-pairs.json

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        "question": {
            "questionId": "1866",
            "questionFrontendId": "1743",
            "categoryTitle": "Algorithms",
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            "title": "Restore the Array From Adjacent Pairs",
            "titleSlug": "restore-the-array-from-adjacent-pairs",
            "content": "<p>There is an integer array <code>nums</code> that consists of <code>n</code> <strong>unique </strong>elements, but you have forgotten it. However, you do remember every pair of adjacent elements in <code>nums</code>.</p>\n\n<p>You are given a 2D integer array <code>adjacentPairs</code> of size <code>n - 1</code> where each <code>adjacentPairs[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> indicates that the elements <code>u<sub>i</sub></code> and <code>v<sub>i</sub></code> are adjacent in <code>nums</code>.</p>\n\n<p>It is guaranteed that every adjacent pair of elements <code>nums[i]</code> and <code>nums[i+1]</code> will exist in <code>adjacentPairs</code>, either as <code>[nums[i], nums[i+1]]</code> or <code>[nums[i+1], nums[i]]</code>. The pairs can appear <strong>in any order</strong>.</p>\n\n<p>Return <em>the original array </em><code>nums</code><em>. If there are multiple solutions, return <strong>any of them</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> adjacentPairs = [[2,1],[3,4],[3,2]]\n<strong>Output:</strong> [1,2,3,4]\n<strong>Explanation:</strong> This array has all its adjacent pairs in adjacentPairs.\nNotice that adjacentPairs[i] may not be in left-to-right order.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> adjacentPairs = [[4,-2],[1,4],[-3,1]]\n<strong>Output:</strong> [-2,4,1,-3]\n<strong>Explanation:</strong> There can be negative numbers.\nAnother solution is [-3,1,4,-2], which would also be accepted.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> adjacentPairs = [[100000,-100000]]\n<strong>Output:</strong> [100000,-100000]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>nums.length == n</code></li>\n\t<li><code>adjacentPairs.length == n - 1</code></li>\n\t<li><code>adjacentPairs[i].length == 2</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> &lt;= nums[i], u<sub>i</sub>, v<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li>There exists some <code>nums</code> that has <code>adjacentPairs</code> as its pairs.</li>\n</ul>\n",
            "translatedTitle": "从相邻元素对还原数组",
            "translatedContent": "<p>存在一个由 <code>n</code> 个不同元素组成的整数数组 <code>nums</code> ，但你已经记不清具体内容。好在你还记得 <code>nums</code> 中的每一对相邻元素。</p>\n\n<p>给你一个二维整数数组 <code>adjacentPairs</code> ，大小为 <code>n - 1</code> ，其中每个 <code>adjacentPairs[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> 表示元素 <code>u<sub>i</sub></code> 和 <code>v<sub>i</sub></code> 在 <code>nums</code> 中相邻。</p>\n\n<p>题目数据保证所有由元素 <code>nums[i]</code> 和 <code>nums[i+1]</code> 组成的相邻元素对都存在于 <code>adjacentPairs</code> 中，存在形式可能是 <code>[nums[i], nums[i+1]]</code> ，也可能是 <code>[nums[i+1], nums[i]]</code> 。这些相邻元素对可以 <strong>按任意顺序</strong> 出现。</p>\n\n<p>返回 <strong>原始数组</strong><em> </em><code>nums</code><em> </em>。如果存在多种解答，返回 <strong>其中任意一个</strong> 即可。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>adjacentPairs = [[2,1],[3,4],[3,2]]\n<strong>输出：</strong>[1,2,3,4]\n<strong>解释：</strong>数组的所有相邻元素对都在 adjacentPairs 中。\n特别要注意的是，adjacentPairs[i] 只表示两个元素相邻，并不保证其 左-右 顺序。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>adjacentPairs = [[4,-2],[1,4],[-3,1]]\n<strong>输出：</strong>[-2,4,1,-3]\n<strong>解释：</strong>数组中可能存在负数。\n另一种解答是 [-3,1,4,-2] ，也会被视作正确答案。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>adjacentPairs = [[100000,-100000]]\n<strong>输出：</strong>[100000,-100000]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>nums.length == n</code></li>\n\t<li><code>adjacentPairs.length == n - 1</code></li>\n\t<li><code>adjacentPairs[i].length == 2</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= nums[i], u<sub>i</sub>, v<sub>i</sub> <= 10<sup>5</sup></code></li>\n\t<li>题目数据保证存在一些以 <code>adjacentPairs</code> 作为元素对的数组 <code>nums</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<int> restoreArray(vector<vector<int>>& adjacentPairs) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def restoreArray(self, adjacentPairs):\n        \"\"\"\n        :type adjacentPairs: List[List[int]]\n        :rtype: List[int]\n        \"\"\"",
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                "Find the first element of nums - it will only appear once in adjacentPairs.",
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