leetcode-problemset/leetcode-cn/originData/range-addition-ii.json

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            "title": "Range Addition II",
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            "content": "<p>You are given an <code>m x n</code> matrix <code>M</code> initialized with all <code>0</code>&#39;s and an array of operations <code>ops</code>, where <code>ops[i] = [a<sub>i</sub>, b<sub>i</sub>]</code> means <code>M[x][y]</code> should be incremented by one for all <code>0 &lt;= x &lt; a<sub>i</sub></code> and <code>0 &lt;= y &lt; b<sub>i</sub></code>.</p>\n\n<p>Count and return <em>the number of maximum integers in the matrix after performing all the operations</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/02/ex1.jpg\" style=\"width: 750px; height: 176px;\" />\n<pre>\n<strong>Input:</strong> m = 3, n = 3, ops = [[2,2],[3,3]]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The maximum integer in M is 2, and there are four of it in M. So return 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> m = 3, n = 3, ops = [[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]]\n<strong>Output:</strong> 4\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> m = 3, n = 3, ops = []\n<strong>Output:</strong> 9\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= m, n &lt;= 4 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= ops.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>ops[i].length == 2</code></li>\n\t<li><code>1 &lt;= a<sub>i</sub> &lt;= m</code></li>\n\t<li><code>1 &lt;= b<sub>i</sub> &lt;= n</code></li>\n</ul>\n",
            "translatedTitle": "范围求和 II",
            "translatedContent": "<p>给你一个 <code>m x&nbsp;n</code> 的矩阵&nbsp;<code>M</code><strong>&nbsp;</strong>，初始化时所有的 <code>0</code> 和一个操作数组 <code>op</code> ，其中 <code>ops[i] = [ai, bi]</code> 意味着当所有的 <code>0 &lt;= x &lt; ai</code> 和 <code>0 &lt;= y &lt; bi</code> 时， <code>M[x][y]</code> 应该加 1。</p>\n\n<p>在&nbsp;<em>执行完所有操作后</em>&nbsp;，计算并返回&nbsp;<em>矩阵中最大整数的个数</em>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/02/ex1.jpg\" style=\"height: 176px; width: 750px;\" /></p>\n\n<pre>\n<strong>输入:</strong> m = 3, n = 3，ops = [[2,2],[3,3]]\n<strong>输出:</strong> 4\n<strong>解释:</strong> M 中最大的整数是 2, 而且 M 中有4个值为2的元素。因此返回 4。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> m = 3, n = 3, ops = [[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]]\n<strong>输出:</strong> 4\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong> m = 3, n = 3, ops = []\n<strong>输出:</strong> 9\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<p><meta charset=\"UTF-8\" /></p>\n\n<ul>\n\t<li><code>1 &lt;= m, n &lt;= 4 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= ops.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>ops[i].length == 2</code></li>\n\t<li><code>1 &lt;= a<sub>i</sub>&nbsp;&lt;= m</code></li>\n\t<li><code>1 &lt;= b<sub>i</sub>&nbsp;&lt;= n</code></li>\n</ul>\n",
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