leetcode-problemset/leetcode-cn/originData/number-of-bit-changes-to-make-two-integers-equal.json

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        "question": {
            "questionId": "3508",
            "questionFrontendId": "3226",
            "categoryTitle": "Algorithms",
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            "title": "Number of Bit Changes to Make Two Integers Equal",
            "titleSlug": "number-of-bit-changes-to-make-two-integers-equal",
            "content": "<p>You are given two positive integers <code>n</code> and <code>k</code>.</p>\n\n<p>You can choose <strong>any</strong> bit in the <strong>binary representation</strong> of <code>n</code> that is equal to 1 and change it to 0.</p>\n\n<p>Return the <em>number of changes</em> needed to make <code>n</code> equal to <code>k</code>. If it is impossible, return -1.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 13, k = 4</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong><br />\nInitially, the binary representations of <code>n</code> and <code>k</code> are <code>n = (1101)<sub>2</sub></code> and <code>k = (0100)<sub>2</sub></code>.<br />\nWe can change the first and fourth bits of <code>n</code>. The resulting integer is <code>n = (<u><strong>0</strong></u>10<u><strong>0</strong></u>)<sub>2</sub> = k</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 21, k = 21</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong><br />\n<code>n</code> and <code>k</code> are already equal, so no changes are needed.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 14, k = 13</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>Explanation:</strong><br />\nIt is not possible to make <code>n</code> equal to <code>k</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n, k &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "使两个整数相等的位更改次数",
            "translatedContent": "<p>给你两个正整数 <code>n</code> 和 <code>k</code>。</p>\n\n<p>你可以选择 <code>n</code> 的 <strong>二进制表示</strong> 中任意一个值为 1 的位，并将其改为 0。</p>\n\n<p>返回使得 <code>n</code> 等于 <code>k</code> 所需要的更改次数。如果无法实现，返回 -1。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 13, k = 4</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>解释：</strong><br />\n最初，<code>n</code> 和 <code>k</code> 的二进制表示分别为 <code>n = (1101)<sub>2</sub></code> 和 <code>k = (0100)<sub>2</sub></code>，</p>\n\n<p>我们可以改变 <code>n</code> 的第一位和第四位。结果整数为 <code>n = (<u><strong>0</strong></u>10<u><strong>0</strong></u>)<sub>2</sub> = k</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 21, k = 21</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong><br />\n<code>n</code> 和 <code>k</code> 已经相等，因此不需要更改。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 14, k = 13</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>解释：</strong><br />\n无法使 <code>n</code> 等于 <code>k</code>。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n, k &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                "Find the binary representations of <code>n</code> and <code>k</code>.",
                "Any bit that is equal to 1 in <code>n</code> and equal to 0 in <code>k</code> needs to be changed."
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