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leetcode-problemset/leetcode-cn/originData/minimum-window-substring.json
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"question": {
"questionId": "76",
"questionFrontendId": "76",
"categoryTitle": "Algorithms",
"boundTopicId": 1463,
"title": "Minimum Window Substring",
"titleSlug": "minimum-window-substring",
"content": "<p>Given two strings <code>s</code> and <code>t</code> of lengths <code>m</code> and <code>n</code> respectively, return <em>the <strong>minimum window</strong></em> <span data-keyword=\"substring-nonempty\"><strong><em>substring</em></strong></span><em> of </em><code>s</code><em> such that every character in </em><code>t</code><em> (<strong>including duplicates</strong>) is included in the window</em>. If there is no such substring, return <em>the empty string </em><code>&quot;&quot;</code>.</p>\n\n<p>The testcases will be generated such that the answer is <strong>unique</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ADOBECODEBANC&quot;, t = &quot;ABC&quot;\n<strong>Output:</strong> &quot;BANC&quot;\n<strong>Explanation:</strong> The minimum window substring &quot;BANC&quot; includes &#39;A&#39;, &#39;B&#39;, and &#39;C&#39; from string t.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, t = &quot;a&quot;\n<strong>Output:</strong> &quot;a&quot;\n<strong>Explanation:</strong> The entire string s is the minimum window.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, t = &quot;aa&quot;\n<strong>Output:</strong> &quot;&quot;\n<strong>Explanation:</strong> Both &#39;a&#39;s from t must be included in the window.\nSince the largest window of s only has one &#39;a&#39;, return empty string.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == s.length</code></li>\n\t<li><code>n == t.length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of uppercase and lowercase English letters.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Could you find an algorithm that runs in <code>O(m + n)</code> time?</p>\n",
"translatedTitle": "最小覆盖子串",
"translatedContent": "<p>给你一个字符串 <code>s</code> 、一个字符串 <code>t</code> 。返回 <code>s</code> 中涵盖 <code>t</code> 所有字符的最小子串。如果 <code>s</code> 中不存在涵盖 <code>t</code> 所有字符的子串,则返回空字符串 <code>\"\"</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>注意:</strong></p>\n\n<ul>\n\t<li>对于 <code>t</code> 中重复字符,我们寻找的子字符串中该字符数量必须不少于 <code>t</code> 中该字符数量。</li>\n\t<li>如果 <code>s</code> 中存在这样的子串,我们保证它是唯一的答案。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"ADOBECODEBANC\", t = \"ABC\"\n<strong>输出:</strong>\"BANC\"\n<strong>解释:</strong>最小覆盖子串 \"BANC\" 包含来自字符串 t 的 'A'、'B' 和 'C'。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"a\", t = \"a\"\n<strong>输出:</strong>\"a\"\n<strong>解释:</strong>整个字符串 s 是最小覆盖子串。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong> s = \"a\", t = \"aa\"\n<strong>输出:</strong> \"\"\n<strong>解释:</strong> t 中两个字符 'a' 均应包含在 s 的子串中,\n因此没有符合条件的子字符串返回空字符串。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code><sup>m == s.length</sup></code></li>\n\t<li><code><sup>n == t.length</sup></code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和 <code>t</code> 由英文字母组成</li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>进阶:</strong>你能设计一个在 <code>o(m+n)</code> 时间内解决此问题的算法吗?",
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"Use two pointers to create a window of letters in s, which would have all the characters from t.",
"Expand the right pointer until all the characters of t are covered.",
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