leetcode-problemset/leetcode-cn/originData/minimum-sum-of-values-by-dividing-array.json

{
    "data": {
        "question": {
            "questionId": "3364",
            "questionFrontendId": "3117",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2734243,
            "title": "Minimum Sum of Values by Dividing Array",
            "titleSlug": "minimum-sum-of-values-by-dividing-array",
            "content": "<p>You are given two arrays <code>nums</code> and <code>andValues</code> of length <code>n</code> and <code>m</code> respectively.</p>\n\n<p>The <strong>value</strong> of an array is equal to the <strong>last</strong> element of that array.</p>\n\n<p>You have to divide <code>nums</code> into <code>m</code> <strong>disjoint contiguous</strong> <span data-keyword=\"subarray-nonempty\">subarrays</span> such that for the <code>i<sup>th</sup></code> subarray <code>[l<sub>i</sub>, r<sub>i</sub>]</code>, the bitwise <code>AND</code> of the subarray elements is equal to <code>andValues[i]</code>, in other words, <code>nums[l<sub>i</sub>] &amp; nums[l<sub>i</sub> + 1] &amp; ... &amp; nums[r<sub>i</sub>] == andValues[i]</code> for all <code>1 &lt;= i &lt;= m</code>, where <code>&amp;</code> represents the bitwise <code>AND</code> operator.</p>\n\n<p>Return <em>the <strong>minimum</strong> possible sum of the <strong>values</strong> of the </em><code>m</code><em> subarrays </em><code>nums</code><em> is divided into</em>. <em>If it is not possible to divide </em><code>nums</code><em> into </em><code>m</code><em> subarrays satisfying these conditions, return</em> <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,4,3,3,2], andValues = [0,3,3,2]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">12</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The only possible way to divide <code>nums</code> is:</p>\n\n<ol>\n\t<li><code>[1,4]</code> as <code>1 &amp; 4 == 0</code>.</li>\n\t<li><code>[3]</code> as the bitwise <code>AND</code> of a single element subarray is that element itself.</li>\n\t<li><code>[3]</code> as the bitwise <code>AND</code> of a single element subarray is that element itself.</li>\n\t<li><code>[2]</code> as the bitwise <code>AND</code> of a single element subarray is that element itself.</li>\n</ol>\n\n<p>The sum of the values for these subarrays is <code>4 + 3 + 3 + 2 = 12</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,3,5,7,7,7,5], andValues = [0,7,5]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">17</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>There are three ways to divide <code>nums</code>:</p>\n\n<ol>\n\t<li><code>[[2,3,5],[7,7,7],[5]]</code> with the sum of the values <code>5 + 7 + 5 == 17</code>.</li>\n\t<li><code>[[2,3,5,7],[7,7],[5]]</code> with the sum of the values <code>7 + 7 + 5 == 19</code>.</li>\n\t<li><code>[[2,3,5,7,7],[7],[5]]</code> with the sum of the values <code>7 + 7 + 5 == 19</code>.</li>\n</ol>\n\n<p>The minimum possible sum of the values is <code>17</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3,4], andValues = [2]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The bitwise <code>AND</code> of the entire array <code>nums</code> is <code>0</code>. As there is no possible way to divide <code>nums</code> into a single subarray to have the bitwise <code>AND</code> of elements <code>2</code>, return <code>-1</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= m == andValues.length &lt;= min(n, 10)</code></li>\n\t<li><code>1 &lt;= nums[i] &lt; 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= andValues[j] &lt; 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "划分数组得到最小的值之和",
            "translatedContent": "<p>给你两个数组 <code>nums</code> 和 <code>andValues</code>，长度分别为 <code>n</code> 和 <code>m</code>。</p>\n\n<p>数组的 <strong>值 </strong>等于该数组的 <strong>最后一个 </strong>元素。</p>\n\n<p>你需要将 <code>nums</code> 划分为 <code>m</code> 个 <strong>不相交的连续 </strong>子数组，对于第 <code>i<sup>th</sup></code> 个子数组 <code>[l<sub>i</sub>, r<sub>i</sub>]</code>，子数组元素的按位<code>AND</code>运算结果等于 <code>andValues[i]</code>，换句话说，对所有的 <code>1 &lt;= i &lt;= m</code>，<code>nums[l<sub>i</sub>] &amp; nums[l<sub>i</sub> + 1] &amp; ... &amp; nums[r<sub>i</sub>] == andValues[i]</code> ，其中 <code>&amp;</code> 表示按位<code>AND</code>运算符。</p>\n\n<p>返回将 <code>nums</code> 划分为 <code>m</code> 个子数组所能得到的可能的 <strong>最小 </strong>子数组 <strong>值</strong> 之和。如果无法完成这样的划分，则返回 <code>-1</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [1,4,3,3,2], andValues = [0,3,3,2]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">12</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>唯一可能的划分方法为：</p>\n\n<ol>\n\t<li><code>[1,4]</code> 因为 <code>1 &amp; 4 == 0</code></li>\n\t<li><code>[3]</code> 因为单元素子数组的按位 <code>AND</code> 结果就是该元素本身</li>\n\t<li><code>[3]</code> 因为单元素子数组的按位 <code>AND</code> 结果就是该元素本身</li>\n\t<li><code>[2]</code> 因为单元素子数组的按位 <code>AND</code> 结果就是该元素本身</li>\n</ol>\n\n<p>这些子数组的值之和为 <code>4 + 3 + 3 + 2 = 12</code></p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [2,3,5,7,7,7,5], andValues = [0,7,5]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">17</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>划分 <code>nums</code> 的三种方式为：</p>\n\n<ol>\n\t<li><code>[[2,3,5],[7,7,7],[5]]</code> 其中子数组的值之和为 <code>5 + 7 + 5 = 17</code></li>\n\t<li><code>[[2,3,5,7],[7,7],[5]]</code> 其中子数组的值之和为 <code>7 + 7 + 5 = 19</code></li>\n\t<li><code>[[2,3,5,7,7],[7],[5]]</code> 其中子数组的值之和为 <code>7 + 7 + 5 = 19</code></li>\n</ol>\n\n<p>子数组值之和的最小可能值为 <code>17</code></p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [1,2,3,4], andValues = [2]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>整个数组 <code>nums</code> 的按位 <code>AND</code> 结果为 <code>0</code>。由于无法将 <code>nums</code> 划分为单个子数组使得元素的按位 <code>AND</code> 结果为 <code>2</code>，因此返回 <code>-1</code>。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= m == andValues.length &lt;= min(n, 10)</code></li>\n\t<li><code>1 &lt;= nums[i] &lt; 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= andValues[j] &lt; 10<sup>5</sup></code></li>\n</ul>\n",
            "isPaidOnly": false,
            "difficulty": "Hard",
            "likes": 11,
            "dislikes": 0,
            "isLiked": null,
            "similarQuestions": "[]",
            "contributors": [],
            "langToValidPlayground": "{\"cpp\": true, \"java\": true, \"python\": true, \"python3\": true, \"mysql\": false, \"mssql\": false, \"oraclesql\": false, \"c\": false, \"csharp\": false, \"javascript\": false, \"typescript\": false, \"bash\": false, \"php\": false, \"swift\": false, \"kotlin\": false, \"dart\": false, \"golang\": false, \"ruby\": false, \"scala\": false, \"html\": false, \"pythonml\": false, \"rust\": false, \"racket\": false, \"erlang\": false, \"elixir\": false, \"pythondata\": false, \"react\": false, \"vanillajs\": false, \"postgresql\": false}",
            "topicTags": [
                {
                    "name": "Bit Manipulation",
                    "slug": "bit-manipulation",
                    "translatedName": "位运算",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Segment Tree",
                    "slug": "segment-tree",
                    "translatedName": "线段树",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Queue",
                    "slug": "queue",
                    "translatedName": "队列",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Array",
                    "slug": "array",
                    "translatedName": "数组",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Binary Search",
                    "slug": "binary-search",
                    "translatedName": "二分查找",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Dynamic Programming",
                    "slug": "dynamic-programming",
                    "translatedName": "动态规划",
                    "__typename": "TopicTagNode"
                }
            ],
            "companyTagStats": null,
            "codeSnippets": [
                {
                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    int minimumValueSum(vector<int>& nums, vector<int>& andValues) {\n        \n    }\n};",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Java",
                    "langSlug": "java",
                    "code": "class Solution {\n    public int minimumValueSum(int[] nums, int[] andValues) {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Python",
                    "langSlug": "python",
                    "code": "class Solution(object):\n    def minimumValueSum(self, nums, andValues):\n        \"\"\"\n        :type nums: List[int]\n        :type andValues: List[int]\n        :rtype: int\n        \"\"\"",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Python3",
                    "langSlug": "python3",
                    "code": "class Solution:\n    def minimumValueSum(self, nums: List[int], andValues: List[int]) -> int:",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "C",
                    "langSlug": "c",
                    "code": "int minimumValueSum(int* nums, int numsSize, int* andValues, int andValuesSize) {\n    \n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "C#",
                    "langSlug": "csharp",
                    "code": "public class Solution {\n    public int MinimumValueSum(int[] nums, int[] andValues) {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "JavaScript",
                    "langSlug": "javascript",
                    "code": "/**\n * @param {number[]} nums\n * @param {number[]} andValues\n * @return {number}\n */\nvar minimumValueSum = function(nums, andValues) {\n\n};",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "TypeScript",
                    "langSlug": "typescript",
                    "code": "function minimumValueSum(nums: number[], andValues: number[]): number {\n    \n};",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "PHP",
                    "langSlug": "php",
                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @param Integer[] $andValues\n     * @return Integer\n     */\n    function minimumValueSum($nums, $andValues) {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Swift",
                    "langSlug": "swift",
                    "code": "class Solution {\n    func minimumValueSum(_ nums: [Int], _ andValues: [Int]) -> Int {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Kotlin",
                    "langSlug": "kotlin",
                    "code": "class Solution {\n    fun minimumValueSum(nums: IntArray, andValues: IntArray): Int {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Dart",
                    "langSlug": "dart",
                    "code": "class Solution {\n  int minimumValueSum(List<int> nums, List<int> andValues) {\n    \n  }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Go",
                    "langSlug": "golang",
                    "code": "func minimumValueSum(nums []int, andValues []int) int {\n\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Ruby",
                    "langSlug": "ruby",
                    "code": "# @param {Integer[]} nums\n# @param {Integer[]} and_values\n# @return {Integer}\ndef minimum_value_sum(nums, and_values)\n\nend",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Scala",
                    "langSlug": "scala",
                    "code": "object Solution {\n    def minimumValueSum(nums: Array[Int], andValues: Array[Int]): Int = {\n        \n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Rust",
                    "langSlug": "rust",
                    "code": "impl Solution {\n    pub fn minimum_value_sum(nums: Vec<i32>, and_values: Vec<i32>) -> i32 {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Racket",
                    "langSlug": "racket",
                    "code": "(define/contract (minimum-value-sum nums andValues)\n  (-> (listof exact-integer?) (listof exact-integer?) exact-integer?)\n  )",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Erlang",
                    "langSlug": "erlang",
                    "code": "-spec minimum_value_sum(Nums :: [integer()], AndValues :: [integer()]) -> integer().\nminimum_value_sum(Nums, AndValues) ->\n  .",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Elixir",
                    "langSlug": "elixir",
                    "code": "defmodule Solution do\n  @spec minimum_value_sum(nums :: [integer], and_values :: [integer]) :: integer\n  def minimum_value_sum(nums, and_values) do\n    \n  end\nend",
                    "__typename": "CodeSnippetNode"
                }
            ],
            "stats": "{\"totalAccepted\": \"2.1K\", \"totalSubmission\": \"5.9K\", \"totalAcceptedRaw\": 2069, \"totalSubmissionRaw\": 5865, \"acRate\": \"35.3%\"}",
            "hints": [
                "Let <code>dp[i][j]</code> be the optimal answer to split  <code>nums[0..(i - 1)]</code> into the first <code>j</code> andValues.",
                "<code>dp[i][j] = min(dp[(i - z)][j - 1]) + nums[i - 1]</code> over all <code>x <= z <= y</code> and <code>dp[0][0] = 0</code>, where <code>x</code> and <code>y</code> are the longest and shortest subarrays ending with <code>nums[i - 1]</code> and the bitwise-and of all the values in it is <code>andValues[j - 1]</code>.",
                "The answer is <code>dp[n][m]</code>.",
                "To calculate <code>x</code> and <code>y</code>, we can use binary search (or sliding window). Note that the more values we have, the smaller the <code>AND</code> value is.",
                "To calculate the result, we need to support RMQ (range minimum query). Segment tree is one way to do it in <code>O(log(n))</code>. But we can use Monotonic Queue since the ranges are indeed “sliding to right” which can be reduced to the classical minimum value in sliding window problem, for a <code>O(n)</code> solution."
            ],
            "solution": null,
            "status": null,
            "sampleTestCase": "[1,4,3,3,2]\n[0,3,3,2]",
            "metaData": "{\n  \"name\": \"minimumValueSum\",\n  \"params\": [\n    {\n      \"name\": \"nums\",\n      \"type\": \"integer[]\"\n    },\n    {\n      \"type\": \"integer[]\",\n      \"name\": \"andValues\"\n    }\n  ],\n  \"return\": {\n    \"type\": \"integer\"\n  }\n}",
            "judgerAvailable": true,
            "judgeType": "large",
            "mysqlSchemas": [],
            "enableRunCode": true,
            "envInfo": "{\"cpp\":[\"C++\",\"<p>\\u7248\\u672c\\uff1a<code>clang 17<\\/code> \\u91c7\\u7528\\u6700\\u65b0C++ 20\\u6807\\u51c6\\uff0c\\u5e76\\u4f7f\\u7528 GCC 11 \\u63d0\\u4f9b\\u7684 <code>libstdc++<\\/code>\\u3002<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528<code>-O2<\\/code>\\u7ea7\\u4f18\\u5316\\u3002<a href=\\\"https:\\/\\/github.com\\/google\\/sanitizers\\/wiki\\/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b<code>out-of-bounds<\\/code>\\u548c<code>use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\"<p>\\u7248\\u672c\\uff1a<code>OpenJDK 21<\\/code>\\u3002\\u4f7f\\u7528\\u7f16\\u8bd1\\u53c2\\u6570 <code>--enable-preview --release 21<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\"<p>\\u7248\\u672c\\uff1a <code>Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1a<a href=\\\"https:\\/\\/docs.python.org\\/2\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/2\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/2\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u6ce8\\u610f Python 2.7 <a href=\\\"https:\\/\\/www.python.org\\/dev\\/peps\\/pep-0373\\/\\\" target=\\\"_blank\\\">\\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\"<p>\\u7248\\u672c\\uff1a<code>GCC 11<\\/code>\\uff0c\\u91c7\\u7528GNU11\\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528<code>-O2<\\/code>\\u7ea7\\u4f18\\u5316\\u3002 <a href=\\\"https:\\/\\/github.com\\/google\\/sanitizers\\/wiki\\/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer<\\/a>\\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b<code>out-of-bounds<\\/code>\\u548c<code>use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n    HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n<p><b>2. \\u5728\\u54c8\\u5e0c\\u8868\\u4e2d\\u67e5\\u627e\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n    struct hash_entry *s;\\r\\n    HASH_FIND_INT(users, &user_id, s);\\r\\n    return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n<p><b>3. \\u4ece\\u54c8\\u5e0c\\u8868\\u4e2d\\u5220\\u9664\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n    HASH_DEL(users, user);  \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"<p><a href=\\\"https:\\/\\/learn.microsoft.com\\/en-us\\/dotnet\\/csharp\\/whats-new\\/csharp-12\\\" target=\\\"_blank\\\">C# 12<\\/a> \\u8fd0\\u884c\\u5728 .NET 8 \\u4e0a<\\/p>\"],\"javascript\":[\"JavaScript\",\"<p>\\u7248\\u672c\\uff1a<code>Node.js 20.10.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5728\\u6267\\u884c\\u65f6\\u5c06\\u5e26\\u4e0a <code>--harmony<\\/code> \\u6807\\u8bb0\\u6765\\u5f00\\u542f <a href=\\\"http:\\/\\/node.green\\/\\\" target=\\\"_blank\\\">\\u65b0\\u7248ES6\\u7279\\u6027<\\/a>\\u3002<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a> \\u548c <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a>\\u3002<\\/p>\"],\"ruby\":[\"Ruby\",\"<p>\\u4f7f\\u7528<code>Ruby 3.2<\\/code>\\u6267\\u884c<\\/p>\\r\\n\\r\\n<p>\\u4e00\\u4e9b\\u5e38\\u7528\\u7684\\u6570\\u636e\\u7ed3\\u6784\\u5df2\\u5728 Algorithms \\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\"<p>\\u7248\\u672c\\uff1a<code>Swift 5.9<\\/code><\\/p>\\r\\n\\r\\n<p>\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/apple\\/swift-algorithms\\/tree\\/1.2.0\\\" target=\\\"_blank\\\">swift-algorithms 1.2.0<\\/a> \\u548c <a href=\\\"https:\\/\\/github.com\\/apple\\/swift-collections\\/tree\\/1.1.0\\\" target=\\\"_blank\\\">swift-collections 1.1.0<\\/a><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 <a href=\\\"https:\\/\\/swift.org\\/download\\/\\\" target=\\\"_blank\\\">Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\"<p>\\u7248\\u672c\\uff1a<code>Go 1.21<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u548c <a href=\\\"https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha\\\" target=\\\"_blank\\\">https:\\/\\/pkg.go.dev\\/github.com\\/emirpasic\\/gods\\/v2@v2.0.0-alpha<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.11<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.74.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a> \\u548c <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.11<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.15 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"]}",
            "book": null,
            "isSubscribed": false,
            "isDailyQuestion": false,
            "dailyRecordStatus": null,
            "editorType": "CKEDITOR",
            "ugcQuestionId": null,
            "style": "LEETCODE",
            "exampleTestcases": "[1,4,3,3,2]\n[0,3,3,2]\n[2,3,5,7,7,7,5]\n[0,7,5]\n[1,2,3,4]\n[2]",
            "__typename": "QuestionNode"
        }
    }
}