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"question": {
"questionId": "3403",
"questionFrontendId": "3144",
"categoryTitle": "Algorithms",
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"title": "Minimum Substring Partition of Equal Character Frequency",
"titleSlug": "minimum-substring-partition-of-equal-character-frequency",
"content": "<p>Given a string <code>s</code>, you need to partition it into one or more <strong>balanced</strong> <span data-keyword=\"substring\">substrings</span>. For example, if <code>s == &quot;ababcc&quot;</code> then <code>(&quot;abab&quot;, &quot;c&quot;, &quot;c&quot;)</code>, <code>(&quot;ab&quot;, &quot;abc&quot;, &quot;c&quot;)</code>, and <code>(&quot;ababcc&quot;)</code> are all valid partitions, but <code>(&quot;a&quot;, <strong>&quot;bab&quot;</strong>, &quot;cc&quot;)</code>, <code>(<strong>&quot;aba&quot;</strong>, &quot;bc&quot;, &quot;c&quot;)</code>, and <code>(&quot;ab&quot;, <strong>&quot;abcc&quot;</strong>)</code> are not. The unbalanced substrings are bolded.</p>\n\n<p>Return the <strong>minimum</strong> number of substrings that you can partition <code>s</code> into.</p>\n\n<p><strong>Note:</strong> A <strong>balanced</strong> string is a string where each character in the string occurs the same number of times.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;fabccddg&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>We can partition the string <code>s</code> into 3 substrings in one of the following ways: <code>(&quot;fab, &quot;ccdd&quot;, &quot;g&quot;)</code>, or <code>(&quot;fabc&quot;, &quot;cd&quot;, &quot;dg&quot;)</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;abababaccddb&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>We can partition the string <code>s</code> into 2 substrings like so: <code>(&quot;abab&quot;, &quot;abaccddb&quot;)</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> consists only of English lowercase letters.</li>\n</ul>\n",
"translatedTitle": "分割字符频率相等的最少子字符串",
"translatedContent": "<p>给你一个字符串&nbsp;<code>s</code>&nbsp;,你需要将它分割成一个或者更多的&nbsp;<strong>平衡</strong>&nbsp;子字符串。比方说,<code>s == \"ababcc\"</code>&nbsp;那么&nbsp;<code>(\"abab\", \"c\", \"c\")</code>&nbsp;<code>(\"ab\", \"abc\", \"c\")</code>&nbsp;和&nbsp;<code>(\"ababcc\")</code>&nbsp;都是合法分割,但是&nbsp;<code>(\"a\", <strong>\"bab\"</strong>, \"cc\")</code>&nbsp;<code>(<strong>\"aba\"</strong>, \"bc\", \"c\")</code>&nbsp;和&nbsp;<code>(\"ab\", <strong>\"abcc\"</strong>)</code>&nbsp;不是,不平衡的子字符串用粗体表示。</p>\n\n<p>请你返回 <code>s</code>&nbsp;<strong>最少</strong> 能分割成多少个平衡子字符串。</p>\n\n<p><b>注意:</b>一个 <strong>平衡</strong>&nbsp;字符串指的是字符串中所有字符出现的次数都相同。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>s = \"fabccddg\"</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>3</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>我们可以将 <code>s</code>&nbsp;分割成 3 个子字符串:<code>(\"fab, \"ccdd\", \"g\")</code>&nbsp;或者&nbsp;<code>(\"fabc\", \"cd\", \"dg\")</code>&nbsp;。</p>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>s = \"abababaccddb\"</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>2</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p>我们可以将&nbsp;<code>s</code>&nbsp;分割成 2 个子字符串:<code>(\"abab\", \"abaccddb\")</code>&nbsp;。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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"<code>dp[i]</code> can be calculated as the <code>min(dp[j])</code> over all <code>j</code> such that <code>j < i</code> and <code>word[j+1…i]</code> is valid."
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