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leetcode-problemset/leetcode-cn/originData/minimum-recolors-to-get-k-consecutive-black-blocks.json
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"question": {
"questionId": "2463",
"questionFrontendId": "2379",
"categoryTitle": "Algorithms",
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"title": "Minimum Recolors to Get K Consecutive Black Blocks",
"titleSlug": "minimum-recolors-to-get-k-consecutive-black-blocks",
"content": "<p>You are given a <strong>0-indexed</strong> string <code>blocks</code> of length <code>n</code>, where <code>blocks[i]</code> is either <code>&#39;W&#39;</code> or <code>&#39;B&#39;</code>, representing the color of the <code>i<sup>th</sup></code> block. The characters <code>&#39;W&#39;</code> and <code>&#39;B&#39;</code> denote the colors white and black, respectively.</p>\n\n<p>You are also given an integer <code>k</code>, which is the desired number of <strong>consecutive</strong> black blocks.</p>\n\n<p>In one operation, you can <strong>recolor</strong> a white block such that it becomes a black block.</p>\n\n<p>Return<em> the <strong>minimum</strong> number of operations needed such that there is at least <strong>one</strong> occurrence of </em><code>k</code><em> consecutive black blocks.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> blocks = &quot;WBBWWBBWBW&quot;, k = 7\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nOne way to achieve 7 consecutive black blocks is to recolor the 0th, 3rd, and 4th blocks\nso that blocks = &quot;BBBBBBBWBW&quot;. \nIt can be shown that there is no way to achieve 7 consecutive black blocks in less than 3 operations.\nTherefore, we return 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> blocks = &quot;WBWBBBW&quot;, k = 2\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nNo changes need to be made, since 2 consecutive black blocks already exist.\nTherefore, we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == blocks.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>blocks[i]</code> is either <code>&#39;W&#39;</code> or <code>&#39;B&#39;</code>.</li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
"translatedTitle": "得到 K 个黑块的最少涂色次数",
"translatedContent": "<p>给你一个长度为 <code>n</code>&nbsp;下标从 <strong>0</strong>&nbsp;开始的字符串&nbsp;<code>blocks</code>&nbsp;<code>blocks[i]</code>&nbsp;要么是&nbsp;<code>'W'</code>&nbsp;要么是&nbsp;<code>'B'</code>&nbsp;,表示第&nbsp;<code>i</code>&nbsp;块的颜色。字符&nbsp;<code>'W'</code> 和&nbsp;<code>'B'</code>&nbsp;分别表示白色和黑色。</p>\n\n<p>给你一个整数&nbsp;<code>k</code>&nbsp;,表示想要&nbsp;<strong>连续</strong>&nbsp;黑色块的数目。</p>\n\n<p>每一次操作中,你可以选择一个白色块将它 <strong>涂成</strong>&nbsp;黑色块。</p>\n\n<p>请你返回至少出现 <strong>一次</strong>&nbsp;连续 <code>k</code>&nbsp;个黑色块的 <strong>最少</strong>&nbsp;操作次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>blocks = \"WBBWWBBWBW\", k = 7\n<b>输出:</b>3\n<strong>解释:</strong>\n一种得到 7 个连续黑色块的方法是把第 0 3 和 4 个块涂成黑色。\n得到 blocks = \"BBBBBBBWBW\" 。\n可以证明无法用少于 3 次操作得到 7 个连续的黑块。\n所以我们返回 3 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<b>输入:</b>blocks = \"WBWBBBW\", k = 2\n<b>输出:</b>0\n<strong>解释:</strong>\n不需要任何操作因为已经有 2 个连续的黑块。\n所以我们返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示:</b></p>\n\n<ul>\n\t<li><code>n == blocks.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>blocks[i]</code>&nbsp;要么是&nbsp;<code>'W'</code>&nbsp;,要么是&nbsp;<code>'B'</code> 。</li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
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"Iterate through all possible consecutive substrings of k characters.",
"Find the number of changes for each substring to make all blocks black, and return the minimum of these."
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