leetcode-problemset/leetcode-cn/originData/minimum-operations-to-make-median-of-array-equal-to-k.json

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            "questionId": "3387",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Operations to Make Median of Array Equal to K",
            "titleSlug": "minimum-operations-to-make-median-of-array-equal-to-k",
            "content": "<p>You are given an integer array <code>nums</code> and a <strong>non-negative</strong> integer <code>k</code>. In one operation, you can increase or decrease any element by 1.</p>\n\n<p>Return the <strong>minimum</strong> number of operations needed to make the <strong><span data-keyword=\"median-array\">median</span></strong> of <code>nums</code> <em>equal</em> to <code>k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,5,6,8,5], k = 4</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>We can subtract one from <code>nums[1]</code> and <code>nums[4]</code> to obtain <code>[2, 4, 6, 8, 4]</code>. The median of the resulting array is equal to <code>k</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,5,6,8,5], k = 7</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>We can add one to <code>nums[1]</code> twice and add one to <code>nums[2]</code> once to obtain <code>[2, 7, 7, 8, 5]</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3,4,5,6], k = 4</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The median of the array is already equal to <code>k</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "使数组中位数等于 K 的最少操作数",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code>&nbsp;和一个 <strong>非负</strong>&nbsp;整数&nbsp;<code>k</code>&nbsp;。</p>\n\n<p>一次操作中，你可以选择任一下标&nbsp;<code>i</code>&nbsp;，然后将&nbsp;<code>nums[i]</code>&nbsp;加&nbsp;<code>1</code>&nbsp;或者减&nbsp;<code>1</code>&nbsp;。</p>\n\n<p>请你返回将 <code>nums</code>&nbsp;<strong>中位数</strong>&nbsp;变为 <code>k</code>&nbsp;所需要的 <strong>最少</strong>&nbsp;操作次数。</p>\n\n<p>一个数组的 <strong>中位数</strong>&nbsp;指的是数组按 <strong>非递减</strong> 顺序排序后最中间的元素。如果数组长度为偶数，我们选择中间两个数的较大值为中位数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [2,5,6,8,5], k = 4</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>2</span></p>\n\n<p><b>解释：</b>我们将&nbsp;<code>nums[1]</code> 和&nbsp;<code>nums[4]</code>&nbsp;减 <code>1</code>&nbsp;得到&nbsp;<code>[2, 4, 6, 8, 4]</code>&nbsp;。现在数组的中位数等于&nbsp;<code>k</code>&nbsp;。所以答案为 2 。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [2,5,6,8,5], k = 7</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>3</span></p>\n\n<p><b>解释：</b>我们将&nbsp;<code>nums[1]</code>&nbsp;增加 1 两次，并且将&nbsp;<code>nums[2]</code>&nbsp;增加 1 一次，得到&nbsp;<code>[2, 7, 7, 8, 5]</code>&nbsp;。结果数组的中位数等于&nbsp;<code>k</code>&nbsp;。所以答案为 3 。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,2,3,4,5,6], k = 4</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>0</span></p>\n\n<p><b>解释：</b>数组中位数已经等于 <code>k</code>&nbsp;了，所以不需要进行任何操作。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                "Sort <code>nums</code> in non-descending order.",
                "For all the smaller values on the left side of the median, change them to <code>k</code> if they are larger than <code>k</code>.",
                "For all the larger values on the right side of the median, change them to <code>k</code> if they are smaller than <code>k</code>."
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