leetcode-problemset/leetcode-cn/originData/minimum-number-of-k-consecutive-bit-flips.json

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            "title": "Minimum Number of K Consecutive Bit Flips",
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            "content": "<p>You are given a binary array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>A <strong>k-bit flip</strong> is choosing a <strong>subarray</strong> of length <code>k</code> from <code>nums</code> and simultaneously changing every <code>0</code> in the subarray to <code>1</code>, and every <code>1</code> in the subarray to <code>0</code>.</p>\n\n<p>Return <em>the minimum number of <strong>k-bit flips</strong> required so that there is no </em><code>0</code><em> in the array</em>. If it is not possible, return <code>-1</code>.</p>\n\n<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,1,0], k = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Flip nums[0], then flip nums[2].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,0], k = 2\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> No matter how we flip subarrays of size 2, we cannot make the array become [1,1,1].\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,0,0,1,0,1,1,0], k = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> \nFlip nums[0],nums[1],nums[2]: nums becomes [1,1,1,1,0,1,1,0]\nFlip nums[4],nums[5],nums[6]: nums becomes [1,1,1,1,1,0,0,0]\nFlip nums[5],nums[6],nums[7]: nums becomes [1,1,1,1,1,1,1,1]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
            "translatedTitle": "K 连续位的最小翻转次数",
            "translatedContent": "<p>给定一个二进制数组 <code>nums</code> 和一个整数 <code>k</code> 。</p>\n\n<p><strong>k位翻转</strong> 就是从 <code>nums</code> 中选择一个长度为 <code>k</code> 的 <strong>子数组</strong> ，同时把子数组中的每一个 <code>0</code> 都改成 <code>1</code> ，把子数组中的每一个 <code>1</code> 都改成 <code>0</code> 。</p>\n\n<p>返回数组中不存在 <code>0</code> 所需的最小 <strong>k位翻转</strong> 次数。如果不可能，则返回&nbsp;<code>-1</code>&nbsp;。</p>\n\n<p><strong>子数组</strong> 是数组的 <strong>连续</strong> 部分。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,1,0], K = 1\n<strong>输出：</strong>2\n<strong>解释：</strong>先翻转 A[0]，然后翻转 A[2]。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,0], K = 2\n<strong>输出：</strong>-1\n<strong>解释：</strong>无论我们怎样翻转大小为 2 的子数组，我们都不能使数组变为 [1,1,1]。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0,0,0,1,0,1,1,0], K = 3\n<strong>输出：</strong>3\n<strong>解释：</strong>\n翻转 A[0],A[1],A[2]:&nbsp;A变成 [1,1,1,1,0,1,1,0]\n翻转 A[4],A[5],A[6]:&nbsp;A变成 [1,1,1,1,1,0,0,0]\n翻转 A[5],A[6],A[7]:&nbsp;A变成 [1,1,1,1,1,1,1,1]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
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