leetcode-problemset/leetcode-cn/originData/merge-k-sorted-lists.json

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        "question": {
            "questionId": "23",
            "questionFrontendId": "23",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1087,
            "title": "Merge k Sorted Lists",
            "titleSlug": "merge-k-sorted-lists",
            "content": "<p>You are given an array of <code>k</code> linked-lists <code>lists</code>, each linked-list is sorted in ascending order.</p>\n\n<p><em>Merge all the linked-lists into one sorted linked-list and return it.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> lists = [[1,4,5],[1,3,4],[2,6]]\n<strong>Output:</strong> [1,1,2,3,4,4,5,6]\n<strong>Explanation:</strong> The linked-lists are:\n[\n  1-&gt;4-&gt;5,\n  1-&gt;3-&gt;4,\n  2-&gt;6\n]\nmerging them into one sorted list:\n1-&gt;1-&gt;2-&gt;3-&gt;4-&gt;4-&gt;5-&gt;6\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> lists = []\n<strong>Output:</strong> []\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> lists = [[]]\n<strong>Output:</strong> []\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>k == lists.length</code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= lists[i].length &lt;= 500</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= lists[i][j] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>lists[i]</code> is sorted in <strong>ascending order</strong>.</li>\n\t<li>The sum of <code>lists[i].length</code> will not exceed <code>10<sup>4</sup></code>.</li>\n</ul>\n",
            "translatedTitle": "合并 K 个升序链表",
            "translatedContent": "<p>给你一个链表数组，每个链表都已经按升序排列。</p>\n\n<p>请你将所有链表合并到一个升序链表中，返回合并后的链表。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>lists = [[1,4,5],[1,3,4],[2,6]]\n<strong>输出：</strong>[1,1,2,3,4,4,5,6]\n<strong>解释：</strong>链表数组如下：\n[\n  1-&gt;4-&gt;5,\n  1-&gt;3-&gt;4,\n  2-&gt;6\n]\n将它们合并到一个有序链表中得到。\n1-&gt;1-&gt;2-&gt;3-&gt;4-&gt;4-&gt;5-&gt;6\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>lists = []\n<strong>输出：</strong>[]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>lists = [[]]\n<strong>输出：</strong>[]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>k == lists.length</code></li>\n\t<li><code>0 &lt;= k &lt;= 10^4</code></li>\n\t<li><code>0 &lt;= lists[i].length &lt;= 500</code></li>\n\t<li><code>-10^4 &lt;= lists[i][j] &lt;= 10^4</code></li>\n\t<li><code>lists[i]</code> 按 <strong>升序</strong> 排列</li>\n\t<li><code>lists[i].length</code> 的总和不超过 <code>10^4</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    ListNode* mergeKLists(vector<ListNode*>& lists) {\n\n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public ListNode mergeKLists(ListNode[] lists) {\n\n    }\n}",
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                    "lang": "Python",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def mergeKLists(self, lists):\n        \"\"\"\n        :type lists: List[ListNode]\n        :rtype: ListNode\n        \"\"\"\n        ",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution:\n    def mergeKLists(self, lists: List[Optional[ListNode]]) -> Optional[ListNode]:",
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                    "lang": "C",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\nstruct ListNode* mergeKLists(struct ListNode** lists, int listsSize) {\n    \n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public ListNode MergeKLists(ListNode[] lists) {\n\n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode[]} lists\n * @return {ListNode}\n */\nvar mergeKLists = function(lists) {\n\n};",
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                    "lang": "TypeScript",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction mergeKLists(lists: Array<ListNode | null>): ListNode | null {\n    \n};",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val = 0, $next = null) {\n *         $this->val = $val;\n *         $this->next = $next;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param ListNode[] $lists\n     * @return ListNode\n     */\n    function mergeKLists($lists) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init() { self.val = 0; self.next = nil; }\n *     public init(_ val: Int) { self.val = val; self.next = nil; }\n *     public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n    func mergeKLists(_ lists: [ListNode?]) -> ListNode? {\n\n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n *     var next: ListNode? = null\n * }\n */\nclass Solution {\n    fun mergeKLists(lists: Array<ListNode?>): ListNode? {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *   int val;\n *   ListNode? next;\n *   ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n  ListNode? mergeKLists(List<ListNode?> lists) {\n    \n  }\n}",
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                    "lang": "Go",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc mergeKLists(lists []*ListNode) *ListNode {\n\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val = 0, _next = nil)\n#         @val = val\n#         @next = _next\n#     end\n# end\n# @param {ListNode[]} lists\n# @return {ListNode}\ndef merge_k_lists(lists)\n\nend",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n *   var next: ListNode = _next\n *   var x: Int = _x\n * }\n */\nobject Solution {\n    def mergeKLists(lists: Array[ListNode]): ListNode = {\n\n    }\n}",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn merge_k_lists(lists: Vec<Option<Box<ListNode>>>) -> Option<Box<ListNode>> {\n\n    }\n}",
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                    "lang": "Racket",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (merge-k-lists lists)\n  (-> (listof (or/c list-node? #f)) (or/c list-node? #f))\n  )",
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                    "lang": "Erlang",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec merge_k_lists(Lists :: [#list_node{} | null]) -> #list_node{} | null.\nmerge_k_lists(Lists) ->\n  .",
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                    "lang": "Elixir",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec merge_k_lists(lists :: [ListNode.t | nil]) :: ListNode.t | nil\n  def merge_k_lists(lists) do\n    \n  end\nend",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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