mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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178 lines
30 KiB
JSON
178 lines
30 KiB
JSON
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"question": {
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"questionId": "2060",
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"questionFrontendId": "1932",
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"categoryTitle": "Algorithms",
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"boundTopicId": 863111,
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"title": "Merge BSTs to Create Single BST",
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"titleSlug": "merge-bsts-to-create-single-bst",
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"content": "<p>You are given <code>n</code> <strong>BST (binary search tree) root nodes</strong> for <code>n</code> separate BSTs stored in an array <code>trees</code> (<strong>0-indexed</strong>). Each BST in <code>trees</code> has <strong>at most 3 nodes</strong>, and no two roots have the same value. In one operation, you can:</p>\n\n<ul>\n\t<li>Select two <strong>distinct</strong> indices <code>i</code> and <code>j</code> such that the value stored at one of the <strong>leaves </strong>of <code>trees[i]</code> is equal to the <strong>root value</strong> of <code>trees[j]</code>.</li>\n\t<li>Replace the leaf node in <code>trees[i]</code> with <code>trees[j]</code>.</li>\n\t<li>Remove <code>trees[j]</code> from <code>trees</code>.</li>\n</ul>\n\n<p>Return<em> the <strong>root</strong> of the resulting BST if it is possible to form a valid BST after performing </em><code>n - 1</code><em> operations, or</em><em> </em><code>null</code> <i>if it is impossible to create a valid BST</i>.</p>\n\n<p>A BST (binary search tree) is a binary tree where each node satisfies the following property:</p>\n\n<ul>\n\t<li>Every node in the node's left subtree has a value <strong>strictly less</strong> than the node's value.</li>\n\t<li>Every node in the node's right subtree has a value <strong>strictly greater</strong> than the node's value.</li>\n</ul>\n\n<p>A leaf is a node that has no children.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/08/d1.png\" style=\"width: 450px; height: 163px;\" />\n<pre>\n<strong>Input:</strong> trees = [[2,1],[3,2,5],[5,4]]\n<strong>Output:</strong> [3,2,5,1,null,4]\n<strong>Explanation:</strong>\nIn the first operation, pick i=1 and j=0, and merge trees[0] into trees[1].\nDelete trees[0], so trees = [[3,2,5,1],[5,4]].\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/24/diagram.png\" style=\"width: 450px; height: 181px;\" />\nIn the second operation, pick i=0 and j=1, and merge trees[1] into trees[0].\nDelete trees[1], so trees = [[3,2,5,1,null,4]].\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/24/diagram-2.png\" style=\"width: 220px; height: 165px;\" />\nThe resulting tree, shown above, is a valid BST, so return its root.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/08/d2.png\" style=\"width: 450px; height: 171px;\" />\n<pre>\n<strong>Input:</strong> trees = [[5,3,8],[3,2,6]]\n<strong>Output:</strong> []\n<strong>Explanation:</strong>\nPick i=0 and j=1 and merge trees[1] into trees[0].\nDelete trees[1], so trees = [[5,3,8,2,6]].\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/24/diagram-3.png\" style=\"width: 240px; height: 196px;\" />\nThe resulting tree is shown above. This is the only valid operation that can be performed, but the resulting tree is not a valid BST, so return null.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/08/d3.png\" style=\"width: 430px; height: 168px;\" />\n<pre>\n<strong>Input:</strong> trees = [[5,4],[3]]\n<strong>Output:</strong> []\n<strong>Explanation:</strong> It is impossible to perform any operations.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == trees.length</code></li>\n\t<li><code>1 <= n <= 5 * 10<sup>4</sup></code></li>\n\t<li>The number of nodes in each tree is in the range <code>[1, 3]</code>.</li>\n\t<li>Each node in the input may have children but no grandchildren.</li>\n\t<li>No two roots of <code>trees</code> have the same value.</li>\n\t<li>All the trees in the input are <strong>valid BSTs</strong>.</li>\n\t<li><code>1 <= TreeNode.val <= 5 * 10<sup>4</sup></code>.</li>\n</ul>\n",
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"translatedTitle": "合并多棵二叉搜索树",
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"translatedContent": "<p>给你 <code>n</code> 个 <strong>二叉搜索树的根节点</strong> ，存储在数组 <code>trees</code> 中（<strong>下标从 0 开始</strong>），对应 <code>n</code> 棵不同的二叉搜索树。<code>trees</code> 中的每棵二叉搜索树 <strong>最多有 3 个节点</strong> ，且不存在值相同的两个根节点。在一步操作中，将会完成下述步骤：</p>\n\n<ul>\n\t<li>选择两个 <strong>不同的</strong> 下标 <code>i</code> 和 <code>j</code> ，要求满足在 <code>trees[i]</code> 中的某个 <strong>叶节点</strong> 的值等于 <code>trees[j]</code> 的 <strong>根节点的值</strong> 。</li>\n\t<li>用 <code>trees[j]</code> 替换 <code>trees[i]</code> 中的那个叶节点。</li>\n\t<li>从 <code>trees</code> 中移除 <code>trees[j]</code> 。</li>\n</ul>\n\n<p>如果在执行 <code>n - 1</code> 次操作后，能形成一棵有效的二叉搜索树，则返回结果二叉树的 <strong>根节点</strong> ；如果无法构造一棵有效的二叉搜索树<em>，</em>返回<em> </em><code>null</code> 。</p>\n\n<p>二叉搜索树是一种二叉树，且树中每个节点均满足下述属性：</p>\n\n<ul>\n\t<li>任意节点的左子树中的值都 <strong>严格小于</strong> 此节点的值。</li>\n\t<li>任意节点的右子树中的值都 <strong>严格大于</strong> 此节点的值。</li>\n</ul>\n\n<p>叶节点是不含子节点的节点。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/08/d1.png\" />\n<pre>\n<strong>输入：</strong>trees = [[2,1],[3,2,5],[5,4]]\n<strong>输出：</strong>[3,2,5,1,null,4]\n<strong>解释：</strong>\n第一步操作中，选出 i=1 和 j=0 ，并将 trees[0] 合并到 trees[1] 中。\n删除 trees[0] ，trees = [[3,2,5,1],[5,4]] 。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/24/diagram.png\" />\n在第二步操作中，选出 i=0 和 j=1 ，将 trees[1] 合并到 trees[0] 中。\n删除 trees[1] ，trees = [[3,2,5,1,null,4]] 。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/24/diagram-2.png\" />\n结果树如上图所示，为一棵有效的二叉搜索树，所以返回该树的根节点。</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/08/d2.png\" />\n<pre>\n<strong>输入：</strong>trees = [[5,3,8],[3,2,6]]\n<strong>输出：</strong>[]\n<strong>解释：</strong>\n选出 i=0 和 j=1 ，然后将 trees[1] 合并到 trees[0] 中。\n删除 trees[1] ，trees = [[5,3,8,2,6]] 。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/24/diagram-3.png\" />\n结果树如上图所示。仅能执行一次有效的操作，但结果树不是一棵有效的二叉搜索树，所以返回 null 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/08/d3.png\" />\n<pre>\n<strong>输入：</strong>trees = [[5,4],[3]]\n<strong>输出：</strong>[]\n<strong>解释：</strong>无法执行任何操作。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == trees.length</code></li>\n\t<li><code>1 <= n <= 5 * 10<sup>4</sup></code></li>\n\t<li>每棵树中节点数目在范围 <code>[1, 3]</code> 内。</li>\n\t<li>输入数据的每个节点可能有子节点但不存在子节点的子节点</li>\n\t<li><code>trees</code> 中不存在两棵树根节点值相同的情况。</li>\n\t<li>输入中的所有树都是 <strong>有效的二叉树搜索树</strong> 。</li>\n\t<li><code>1 <= TreeNode.val <= 5 * 10<sup>4</sup></code>.</li>\n</ul>\n",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun canMerge(trees: List<TreeNode?>): TreeNode? {\n \n }\n}",
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