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leetcode-problemset/leetcode-cn/originData/maximum-sum-of-two-non-overlapping-subarrays.json
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"question": {
"questionId": "1096",
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"categoryTitle": "Algorithms",
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"title": "Maximum Sum of Two Non-Overlapping Subarrays",
"titleSlug": "maximum-sum-of-two-non-overlapping-subarrays",
"content": "<p>Given an integer array <code>nums</code> and two integers <code>firstLen</code> and <code>secondLen</code>, return <em>the maximum sum of elements in two non-overlapping <strong>subarrays</strong> with lengths </em><code>firstLen</code><em> and </em><code>secondLen</code>.</p>\n\n<p>The array with length <code>firstLen</code> could occur before or after the array with length <code>secondLen</code>, but they have to be non-overlapping.</p>\n\n<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,6,5,2,2,5,1,9,4], firstLen = 1, secondLen = 2\n<strong>Output:</strong> 20\n<strong>Explanation:</strong> One choice of subarrays is [9] with length 1, and [6,5] with length 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,8,1,3,2,1,8,9,0], firstLen = 3, secondLen = 2\n<strong>Output:</strong> 29\n<strong>Explanation:</strong> One choice of subarrays is [3,8,1] with length 3, and [8,9] with length 2.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,5,6,0,9,5,0,3,8], firstLen = 4, secondLen = 3\n<strong>Output:</strong> 31\n<strong>Explanation:</strong> One choice of subarrays is [5,6,0,9] with length 4, and [0,3,8] with length 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= firstLen, secondLen &lt;= 1000</code></li>\n\t<li><code>2 &lt;= firstLen + secondLen &lt;= 1000</code></li>\n\t<li><code>firstLen + secondLen &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
"translatedTitle": "两个非重叠子数组的最大和",
"translatedContent": "<p>给你一个整数数组 <code>nums</code> 和两个整数 <code>firstLen</code> 和 <code>secondLen</code>,请你找出并返回两个非重叠<strong> 子数组 </strong>中元素的最大和<em></em>长度分别为 <code>firstLen</code> 和 <code>secondLen</code> 。</p>\n\n<p>长度为 <code>firstLen</code> 的子数组可以出现在长为 <code>secondLen</code> 的子数组之前或之后,但二者必须是不重叠的。</p>\n\n<p>子数组是数组的一个 <strong>连续</strong> 部分。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [0,6,5,2,2,5,1,9,4], firstLen = 1, secondLen = 2\n<strong>输出:</strong>20\n<strong>解释:</strong>子数组的一种选择中,[9] 长度为 1[6,5] 长度为 2。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [3,8,1,3,2,1,8,9,0], firstLen = 3, secondLen = 2\n<strong>输出:</strong>29\n<strong>解释:</strong>子数组的一种选择中,[3,8,1] 长度为 3[8,9] 长度为 2。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [2,1,5,6,0,9,5,0,3,8], firstLen = 4, secondLen = 3\n<strong>输出:</strong>31\n<strong>解释:</strong>子数组的一种选择中,[5,6,0,9] 长度为 4[0,3,8] 长度为 3。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= firstLen, secondLen &lt;= 1000</code></li>\n\t<li><code>2 &lt;= firstLen + secondLen &lt;= 1000</code></li>\n\t<li><code>firstLen + secondLen &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
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"We can use prefix sums to calculate any subarray sum quickly.\r\nFor each L length subarray, find the best possible M length subarray that occurs before and after it."
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