leetcode-problemset/leetcode-cn/originData/maximum-number-of-eaten-apples.json

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            "title": "Maximum Number of Eaten Apples",
            "titleSlug": "maximum-number-of-eaten-apples",
            "content": "<p>There is a special kind of apple tree that grows apples every day for <code>n</code> days. On the <code>i<sup>th</sup></code> day, the tree grows <code>apples[i]</code> apples that will rot after <code>days[i]</code> days, that is on day <code>i + days[i]</code> the apples will be rotten and cannot be eaten. On some days, the apple tree does not grow any apples, which are denoted by <code>apples[i] == 0</code> and <code>days[i] == 0</code>.</p>\n\n<p>You decided to eat <strong>at most</strong> one apple a day (to keep the doctors away). Note that you can keep eating after the first <code>n</code> days.</p>\n\n<p>Given two integer arrays <code>days</code> and <code>apples</code> of length <code>n</code>, return <em>the maximum number of apples you can eat.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> apples = [1,2,3,5,2], days = [3,2,1,4,2]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> You can eat 7 apples:\n- On the first day, you eat an apple that grew on the first day.\n- On the second day, you eat an apple that grew on the second day.\n- On the third day, you eat an apple that grew on the second day. After this day, the apples that grew on the third day rot.\n- On the fourth to the seventh days, you eat apples that grew on the fourth day.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> You can eat 5 apples:\n- On the first to the third day you eat apples that grew on the first day.\n- Do nothing on the fouth and fifth days.\n- On the sixth and seventh days you eat apples that grew on the sixth day.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == apples.length == days.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= apples[i], days[i] &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>days[i] = 0</code> if and only if <code>apples[i] = 0</code>.</li>\n</ul>\n",
            "translatedTitle": "吃苹果的最大数目",
            "translatedContent": "<p>有一棵特殊的苹果树，一连 <code>n</code> 天，每天都可以长出若干个苹果。在第 <code>i</code> 天，树上会长出 <code>apples[i]</code> 个苹果，这些苹果将会在 <code>days[i]</code> 天后（也就是说，第 <code>i + days[i]</code> 天时）腐烂，变得无法食用。也可能有那么几天，树上不会长出新的苹果，此时用 <code>apples[i] == 0</code> 且 <code>days[i] == 0</code> 表示。</p>\n\n<p>你打算每天 <strong>最多</strong> 吃一个苹果来保证营养均衡。注意，你可以在这 <code>n</code> 天之后继续吃苹果。</p>\n\n<p>给你两个长度为 <code>n</code> 的整数数组 <code>days</code> 和 <code>apples</code> ，返回你可以吃掉的苹果的最大数目<em>。</em></p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>apples = [1,2,3,5,2], days = [3,2,1,4,2]\n<strong>输出：</strong>7\n<strong>解释：</strong>你可以吃掉 7 个苹果：\n- 第一天，你吃掉第一天长出来的苹果。\n- 第二天，你吃掉一个第二天长出来的苹果。\n- 第三天，你吃掉一个第二天长出来的苹果。过了这一天，第三天长出来的苹果就已经腐烂了。\n- 第四天到第七天，你吃的都是第四天长出来的苹果。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2]\n<strong>输出：</strong>5\n<strong>解释：</strong>你可以吃掉 5 个苹果：\n- 第一天到第三天，你吃的都是第一天长出来的苹果。\n- 第四天和第五天不吃苹果。\n- 第六天和第七天，你吃的都是第六天长出来的苹果。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>apples.length == n</code></li>\n\t<li><code>days.length == n</code></li>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= apples[i], days[i] &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li>只有在 <code>apples[i] = 0</code> 时，<code>days[i] = 0</code> 才成立</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int eatenApples(vector<int>& apples, vector<int>& days) {\n\n    }\n};",
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