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"questionId": "3391",
"questionFrontendId": "3148",
"categoryTitle": "Algorithms",
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"title": "Maximum Difference Score in a Grid",
"titleSlug": "maximum-difference-score-in-a-grid",
"content": "<p>You are given an <code>m x n</code> matrix <code>grid</code> consisting of <strong>positive</strong> integers. You can move from a cell in the matrix to <strong>any</strong> other cell that is either to the bottom or to the right (not necessarily adjacent). The score of a move from a cell with the value <code>c1</code> to a cell with the value <code>c2</code> is <code>c2 - c1</code>.<!-- notionvc: 8819ca04-8606-4ecf-815b-fb77bc63b851 --></p>\n\n<p>You can start at <strong>any</strong> cell, and you have to make <strong>at least</strong> one move.</p>\n\n<p>Return the <strong>maximum</strong> total score you can achieve.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/03/14/grid1.png\" style=\"width: 240px; height: 240px;\" />\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">grid = [[9,5,7,3],[8,9,6,1],[6,7,14,3],[2,5,3,1]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">9</span></p>\n\n<p><strong>Explanation:</strong> We start at the cell <code>(0, 1)</code>, and we perform the following moves:<br />\n- Move from the cell <code>(0, 1)</code> to <code>(2, 1)</code> with a score of <code>7 - 5 = 2</code>.<br />\n- Move from the cell <code>(2, 1)</code> to <code>(2, 2)</code> with a score of <code>14 - 7 = 7</code>.<br />\nThe total score is <code>2 + 7 = 9</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/04/08/moregridsdrawio-1.png\" style=\"width: 180px; height: 116px;\" /></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">grid = [[4,3,2],[3,2,1]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>Explanation:</strong> We start at the cell <code>(0, 0)</code>, and we perform one move: <code>(0, 0)</code> to <code>(0, 1)</code>. The score is <code>3 - 4 = -1</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>4 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= grid[i][j] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
"translatedTitle": "矩阵中的最大得分",
"translatedContent": "<p>给你一个由 <strong>正整数</strong> 组成、大小为 <code>m x n</code> 的矩阵 <code>grid</code>。你可以从矩阵中的任一单元格移动到另一个位于正下方或正右侧的任意单元格(不必相邻)。从值为 <code>c1</code> 的单元格移动到值为 <code>c2</code> 的单元格的得分为 <code>c2 - c1</code> 。</p>\n\n<p>你可以从<strong> 任一</strong> 单元格开始,并且必须至少移动一次。</p>\n\n<p>返回你能得到的 <strong>最大 </strong>总得分。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/03/14/grid1.png\" style=\"width: 240px; height: 240px;\" />\n<div class=\"example-block\">\n<p><strong>输入:</strong><span class=\"example-io\">grid = [[9,5,7,3],[8,9,6,1],[6,7,14,3],[2,5,3,1]]</span></p>\n\n<p><strong>输出:</strong><span class=\"example-io\">9</span></p>\n\n<p><strong>解释:</strong>从单元格 <code>(0, 1)</code> 开始,并执行以下移动:<br />\n- 从单元格 <code>(0, 1)</code> 移动到 <code>(2, 1)</code>,得分为 <code>7 - 5 = 2</code> 。<br />\n- 从单元格 <code>(2, 1)</code> 移动到 <code>(2, 2)</code>,得分为 <code>14 - 7 = 7</code> 。<br />\n总得分为 <code>2 + 7 = 9</code> 。</p>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/04/08/moregridsdrawio-1.png\" style=\"width: 180px; height: 116px;\" /></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong><span class=\"example-io\">grid = [[4,3,2],[3,2,1]]</span></p>\n\n<p><strong>输出:</strong><span class=\"example-io\">-1</span></p>\n\n<p><strong>解释:</strong>从单元格 <code>(0, 0)</code> 开始,执行一次移动:从 <code>(0, 0)</code> 到 <code>(0, 1)</code> 。得分为 <code>3 - 4 = -1</code> 。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>4 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= grid[i][j] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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"Lets say we fix the starting cell <code>(x1, y1)</code>, how to the find a cell <code>(x2, y2)</code> such that the value <code>grid[x2][y2] - grid[x1][y1]</code> is the maximum possible?"
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