mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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198 lines
29 KiB
JSON
198 lines
29 KiB
JSON
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"categoryTitle": "Algorithms",
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"title": "Maximum Binary Tree",
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"content": "<p>You are given an integer array <code>nums</code> with no duplicates. A <strong>maximum binary tree</strong> can be built recursively from <code>nums</code> using the following algorithm:</p>\n\n<ol>\n\t<li>Create a root node whose value is the maximum value in <code>nums</code>.</li>\n\t<li>Recursively build the left subtree on the <strong>subarray prefix</strong> to the <strong>left</strong> of the maximum value.</li>\n\t<li>Recursively build the right subtree on the <strong>subarray suffix</strong> to the <strong>right</strong> of the maximum value.</li>\n</ol>\n\n<p>Return <em>the <strong>maximum binary tree</strong> built from </em><code>nums</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/tree1.jpg\" style=\"width: 302px; height: 421px;\" />\n<pre>\n<strong>Input:</strong> nums = [3,2,1,6,0,5]\n<strong>Output:</strong> [6,3,5,null,2,0,null,null,1]\n<strong>Explanation:</strong> The recursive calls are as follow:\n- The largest value in [3,2,1,6,0,5] is 6. Left prefix is [3,2,1] and right suffix is [0,5].\n - The largest value in [3,2,1] is 3. Left prefix is [] and right suffix is [2,1].\n - Empty array, so no child.\n - The largest value in [2,1] is 2. Left prefix is [] and right suffix is [1].\n - Empty array, so no child.\n - Only one element, so child is a node with value 1.\n - The largest value in [0,5] is 5. Left prefix is [0] and right suffix is [].\n - Only one element, so child is a node with value 0.\n - Empty array, so no child.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/tree2.jpg\" style=\"width: 182px; height: 301px;\" />\n<pre>\n<strong>Input:</strong> nums = [3,2,1]\n<strong>Output:</strong> [3,null,2,null,1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 1000</code></li>\n\t<li><code>0 <= nums[i] <= 1000</code></li>\n\t<li>All integers in <code>nums</code> are <strong>unique</strong>.</li>\n</ul>\n",
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"translatedTitle": "最大二叉树",
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"translatedContent": "<p>给定一个不重复的整数数组 <code>nums</code> 。 <strong>最大二叉树</strong> 可以用下面的算法从 <code>nums</code> 递归地构建:</p>\n\n<ol>\n\t<li>创建一个根节点，其值为 <code>nums</code> 中的最大值。</li>\n\t<li>递归地在最大值 <strong>左边</strong> 的 <strong>子数组前缀上</strong> 构建左子树。</li>\n\t<li>递归地在最大值 <strong>右边</strong> 的 <strong>子数组后缀上</strong> 构建右子树。</li>\n</ol>\n\n<p>返回 <em><code>nums</code> 构建的 </em><strong><em>最大二叉树</em> </strong>。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/tree1.jpg\" />\n<pre>\n<strong>输入：</strong>nums = [3,2,1,6,0,5]\n<strong>输出：</strong>[6,3,5,null,2,0,null,null,1]\n<strong>解释：</strong>递归调用如下所示：\n- [3,2,1,6,0,5] 中的最大值是 6 ，左边部分是 [3,2,1] ，右边部分是 [0,5] 。\n - [3,2,1] 中的最大值是 3 ，左边部分是 [] ，右边部分是 [2,1] 。\n - 空数组，无子节点。\n - [2,1] 中的最大值是 2 ，左边部分是 [] ，右边部分是 [1] 。\n - 空数组，无子节点。\n - 只有一个元素，所以子节点是一个值为 1 的节点。\n - [0,5] 中的最大值是 5 ，左边部分是 [0] ，右边部分是 [] 。\n - 只有一个元素，所以子节点是一个值为 0 的节点。\n - 空数组，无子节点。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/tree2.jpg\" />\n<pre>\n<strong>输入：</strong>nums = [3,2,1]\n<strong>输出：</strong>[3,null,2,null,1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 1000</code></li>\n\t<li><code>0 <= nums[i] <= 1000</code></li>\n\t<li><code>nums</code> 中的所有整数 <strong>互不相同</strong></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* constructMaximumBinaryTree(vector<int>& nums) {\n\n }\n};",
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