leetcode-problemset/leetcode-cn/originData/maximize-the-confusion-of-an-exam.json

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            "categoryTitle": "Algorithms",
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            "title": "Maximize the Confusion of an Exam",
            "titleSlug": "maximize-the-confusion-of-an-exam",
            "content": "<p>A teacher is writing a test with <code>n</code> true/false questions, with <code>&#39;T&#39;</code> denoting true and <code>&#39;F&#39;</code> denoting false. He wants to confuse the students by <strong>maximizing</strong> the number of <strong>consecutive</strong> questions with the <strong>same</strong> answer (multiple trues or multiple falses in a row).</p>\n\n<p>You are given a string <code>answerKey</code>, where <code>answerKey[i]</code> is the original answer to the <code>i<sup>th</sup></code> question. In addition, you are given an integer <code>k</code>, the maximum number of times you may perform the following operation:</p>\n\n<ul>\n\t<li>Change the answer key for any question to <code>&#39;T&#39;</code> or <code>&#39;F&#39;</code> (i.e., set <code>answerKey[i]</code> to <code>&#39;T&#39;</code> or <code>&#39;F&#39;</code>).</li>\n</ul>\n\n<p>Return <em>the <strong>maximum</strong> number of consecutive</em> <code>&#39;T&#39;</code>s or <code>&#39;F&#39;</code>s <em>in the answer key after performing the operation at most</em> <code>k</code> <em>times</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> answerKey = &quot;TTFF&quot;, k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> We can replace both the &#39;F&#39;s with &#39;T&#39;s to make answerKey = &quot;<u>TTTT</u>&quot;.\nThere are four consecutive &#39;T&#39;s.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> answerKey = &quot;TFFT&quot;, k = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can replace the first &#39;T&#39; with an &#39;F&#39; to make answerKey = &quot;<u>FFF</u>T&quot;.\nAlternatively, we can replace the second &#39;T&#39; with an &#39;F&#39; to make answerKey = &quot;T<u>FFF</u>&quot;.\nIn both cases, there are three consecutive &#39;F&#39;s.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> answerKey = &quot;TTFTTFTT&quot;, k = 1\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> We can replace the first &#39;F&#39; to make answerKey = &quot;<u>TTTTT</u>FTT&quot;\nAlternatively, we can replace the second &#39;F&#39; to make answerKey = &quot;TTF<u>TTTTT</u>&quot;. \nIn both cases, there are five consecutive &#39;T&#39;s.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == answerKey.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>answerKey[i]</code> is either <code>&#39;T&#39;</code> or <code>&#39;F&#39;</code></li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
            "translatedTitle": "考试的最大困扰度",
            "translatedContent": "<p>一位老师正在出一场由 <code>n</code>&nbsp;道判断题构成的考试，每道题的答案为 true （用 <code><span style=\"\">'T'</span></code> 表示）或者 false （用 <code>'F'</code>&nbsp;表示）。老师想增加学生对自己做出答案的不确定性，方法是&nbsp;<strong>最大化&nbsp;</strong>有 <strong>连续相同</strong>&nbsp;结果的题数。（也就是连续出现 true 或者连续出现 false）。</p>\n\n<p>给你一个字符串&nbsp;<code>answerKey</code>&nbsp;，其中&nbsp;<code>answerKey[i]</code>&nbsp;是第 <code>i</code>&nbsp;个问题的正确结果。除此以外，还给你一个整数 <code>k</code>&nbsp;，表示你能进行以下操作的最多次数：</p>\n\n<ul>\n\t<li>每次操作中，将问题的正确答案改为&nbsp;<code>'T'</code> 或者&nbsp;<code>'F'</code>&nbsp;（也就是将 <code>answerKey[i]</code> 改为&nbsp;<code>'T'</code>&nbsp;或者&nbsp;<code>'F'</code>&nbsp;）。</li>\n</ul>\n\n<p>请你返回在不超过 <code>k</code>&nbsp;次操作的情况下，<strong>最大</strong>&nbsp;连续 <code>'T'</code>&nbsp;或者 <code>'F'</code>&nbsp;的数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>answerKey = \"TTFF\", k = 2\n<b>输出：</b>4\n<b>解释：</b>我们可以将两个 'F' 都变为 'T' ，得到 answerKey = \"<em><strong>TTTT</strong></em>\" 。\n总共有四个连续的 'T' 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>answerKey = \"TFFT\", k = 1\n<b>输出：</b>3\n<b>解释：</b>我们可以将最前面的 'T' 换成 'F' ，得到 answerKey = \"<em><strong>FFF</strong></em>T\" 。\n或者，我们可以将第二个 'T' 换成 'F' ，得到 answerKey = \"T<em><strong>FFF</strong></em>\" 。\n两种情况下，都有三个连续的 'F' 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>answerKey = \"TTFTTFTT\", k = 1\n<b>输出：</b>5\n<b>解释：</b>我们可以将第一个 'F' 换成 'T' ，得到 answerKey = \"<em><strong>TTTTT</strong></em>FTT\" 。\n或者我们可以将第二个 'F' 换成 'T' ，得到 answerKey = \"TTF<em><strong>TTTTT</strong></em>\" 。\n两种情况下，都有五个连续的 'T' 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == answerKey.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>answerKey[i]</code>&nbsp;要么是&nbsp;<code>'T'</code> ，要么是&nbsp;<code>'F'</code></li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
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            "hints": [
                "Can we use the maximum length at the previous position to help us find the answer for the current position?",
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