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leetcode-problemset/leetcode-cn/originData/matrix-block-sum.json
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{
"data": {
"question": {
"questionId": "1242",
"questionFrontendId": "1314",
"categoryTitle": "Algorithms",
"boundTopicId": 70152,
"title": "Matrix Block Sum",
"titleSlug": "matrix-block-sum",
"content": "<p>Given a <code>m x n</code> matrix <code>mat</code> and an integer <code>k</code>, return <em>a matrix</em> <code>answer</code> <em>where each</em> <code>answer[i][j]</code> <em>is the sum of all elements</em> <code>mat[r][c]</code> <em>for</em>:</p>\n\n<ul>\n\t<li><code>i - k &lt;= r &lt;= i + k,</code></li>\n\t<li><code>j - k &lt;= c &lt;= j + k</code>, and</li>\n\t<li><code>(r, c)</code> is a valid position in the matrix.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[1,2,3],[4,5,6],[7,8,9]], k = 1\n<strong>Output:</strong> [[12,21,16],[27,45,33],[24,39,28]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[1,2,3],[4,5,6],[7,8,9]], k = 2\n<strong>Output:</strong> [[45,45,45],[45,45,45],[45,45,45]]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m ==&nbsp;mat.length</code></li>\n\t<li><code>n ==&nbsp;mat[i].length</code></li>\n\t<li><code>1 &lt;= m, n, k &lt;= 100</code></li>\n\t<li><code>1 &lt;= mat[i][j] &lt;= 100</code></li>\n</ul>\n",
"translatedTitle": "矩阵区域和",
"translatedContent": "<p>给你一个 <code>m x n</code> 的矩阵 <code>mat</code> 和一个整数 <code>k</code> ,请你返回一个矩阵 <code>answer</code> ,其中每个 <code>answer[i][j]</code> 是所有满足下述条件的元素 <code>mat[r][c]</code> 的和: </p>\n\n<ul>\n\t<li><code>i - k <= r <= i + k, </code></li>\n\t<li><code>j - k <= c <= j + k</code> 且</li>\n\t<li><code>(r, c)</code> 在矩阵内。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>mat = [[1,2,3],[4,5,6],[7,8,9]], k = 1\n<strong>输出:</strong>[[12,21,16],[27,45,33],[24,39,28]]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>mat = [[1,2,3],[4,5,6],[7,8,9]], k = 2\n<strong>输出:</strong>[[45,45,45],[45,45,45],[45,45,45]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 <= m, n, k <= 100</code></li>\n\t<li><code>1 <= mat[i][j] <= 100</code></li>\n</ul>\n",
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"translatedName": "数组",
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"translatedName": "矩阵",
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"code": "class Solution {\npublic:\n vector<vector<int>> matrixBlockSum(vector<vector<int>>& mat, int k) {\n\n }\n};",
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"code": "class Solution(object):\n def matrixBlockSum(self, mat, k):\n \"\"\"\n :type mat: List[List[int]]\n :type k: int\n :rtype: List[List[int]]\n \"\"\"",
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"lang": "Racket",
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"code": "defmodule Solution do\n @spec matrix_block_sum(mat :: [[integer]], k :: integer) :: [[integer]]\n def matrix_block_sum(mat, k) do\n \n end\nend",
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"hints": [
"How to calculate the required sum for a cell (i,j) fast ?",
"Use the concept of cumulative sum array.",
"Create a cumulative sum matrix where dp[i][j] is the sum of all cells in the rectangle from (0,0) to (i,j), use inclusion-exclusion idea."
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