leetcode-problemset/leetcode-cn/originData/loud-and-rich.json

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            "title": "Loud and Rich",
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            "content": "<p>There is a group of <code>n</code> people labeled from <code>0</code> to <code>n - 1</code> where each person has a different amount of money and a different level of quietness.</p>\n\n<p>You are given an array <code>richer</code> where <code>richer[i] = [a<sub>i</sub>, b<sub>i</sub>]</code> indicates that <code>a<sub>i</sub></code> has more money than <code>b<sub>i</sub></code> and an integer array <code>quiet</code> where <code>quiet[i]</code> is the quietness of the <code>i<sup>th</sup></code> person. All the given data in richer are <strong>logically correct</strong> (i.e., the data will not lead you to a situation where <code>x</code> is richer than <code>y</code> and <code>y</code> is richer than <code>x</code> at the same time).</p>\n\n<p>Return <em>an integer array </em><code>answer</code><em> where </em><code>answer[x] = y</code><em> if </em><code>y</code><em> is the least quiet person (that is, the person </em><code>y</code><em> with the smallest value of </em><code>quiet[y]</code><em>) among all people who definitely have equal to or more money than the person </em><code>x</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0]\n<strong>Output:</strong> [5,5,2,5,4,5,6,7]\n<strong>Explanation:</strong> \nanswer[0] = 5.\nPerson 5 has more money than 3, which has more money than 1, which has more money than 0.\nThe only person who is quieter (has lower quiet[x]) is person 7, but it is not clear if they have more money than person 0.\nanswer[7] = 7.\nAmong all people that definitely have equal to or more money than person 7 (which could be persons 3, 4, 5, 6, or 7), the person who is the quietest (has lower quiet[x]) is person 7.\nThe other answers can be filled out with similar reasoning.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> richer = [], quiet = [0]\n<strong>Output:</strong> [0]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == quiet.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 500</code></li>\n\t<li><code>0 &lt;= quiet[i] &lt; n</code></li>\n\t<li>All the values of <code>quiet</code> are <strong>unique</strong>.</li>\n\t<li><code>0 &lt;= richer.length &lt;= n * (n - 1) / 2</code></li>\n\t<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt; n</code></li>\n\t<li><code>a<sub>i </sub>!= b<sub>i</sub></code></li>\n\t<li>All the pairs of <code>richer</code> are <strong>unique</strong>.</li>\n\t<li>The observations in <code>richer</code> are all logically consistent.</li>\n</ul>\n",
            "translatedTitle": "喧闹和富有",
            "translatedContent": "<p>有一组 <code>n</code> 个人作为实验对象，从 <code>0</code> 到 <code>n - 1</code> 编号，其中每个人都有不同数目的钱，以及不同程度的安静值（quietness）。为了方便起见，我们将编号为&nbsp;<code>x</code>&nbsp;的人简称为 \"person&nbsp;<code>x</code>&nbsp;\"。</p>\n\n<p>给你一个数组 <code>richer</code> ，其中 <code>richer[i] = [a<sub>i</sub>, b<sub>i</sub>]</code> 表示 person&nbsp;<code>a<sub>i</sub></code>&nbsp;比 person&nbsp;<code>b<sub>i</sub></code>&nbsp;更有钱。另给你一个整数数组 <code>quiet</code> ，其中&nbsp;<code>quiet[i]</code> 是 person <code>i</code> 的安静值。<code>richer</code> 中所给出的数据 <strong>逻辑自洽</strong>（也就是说，在 person <code>x</code> 比 person <code>y</code> 更有钱的同时，不会出现 person <code>y</code> 比 person <code>x</code> 更有钱的情况 ）。</p>\n\n<p>现在，返回一个整数数组 <code>answer</code> 作为答案，其中&nbsp;<code>answer[x] = y</code>&nbsp;的前提是，在所有拥有的钱肯定不少于&nbsp;person&nbsp;<code>x</code>&nbsp;的人中，person&nbsp;<code>y</code>&nbsp;是最安静的人（也就是安静值&nbsp;<code>quiet[y]</code>&nbsp;最小的人）。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0]\n<strong>输出：</strong>[5,5,2,5,4,5,6,7]\n<strong>解释： </strong>\nanswer[0] = 5，\nperson 5 比 person 3 有更多的钱，person 3 比 person 1 有更多的钱，person 1 比 person 0 有更多的钱。\n唯一较为安静（有较低的安静值 quiet[x]）的人是 person 7，\n但是目前还不清楚他是否比 person 0 更有钱。\nanswer[7] = 7，\n在所有拥有的钱肯定不少于 person 7 的人中（这可能包括 person 3，4，5，6 以及 7），\n最安静（有较低安静值 quiet[x]）的人是 person 7。\n其他的答案也可以用类似的推理来解释。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>richer = [], quiet = [0]\n<strong>输出：</strong>[0]\n</pre>\n&nbsp;\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == quiet.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 500</code></li>\n\t<li><code>0 &lt;= quiet[i] &lt; n</code></li>\n\t<li><code>quiet</code> 的所有值 <strong>互不相同</strong></li>\n\t<li><code>0 &lt;= richer.length &lt;= n * (n - 1) / 2</code></li>\n\t<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt; n</code></li>\n\t<li><code>a<sub>i </sub>!= b<sub>i</sub></code></li>\n\t<li><code>richer</code> 中的所有数对 <strong>互不相同</strong></li>\n\t<li>对<strong> </strong><code>richer</code> 的观察在逻辑上是一致的</li>\n</ul>\n",
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