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leetcode-problemset/leetcode-cn/originData/ju-qing-hong-fa-shi-jian.json
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"question": {
"questionId": "1000057",
"questionFrontendId": "LCP 08",
"categoryTitle": "Algorithms",
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"title": "剧情触发时间",
"titleSlug": "ju-qing-hong-fa-shi-jian",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "剧情触发时间",
"translatedContent": "<p>在战略游戏中,玩家往往需要发展自己的势力来触发各种新的剧情。一个势力的主要属性有三种,分别是文明等级(<code>C</code>),资源储备(<code>R</code>)以及人口数量(<code>H</code>)。在游戏开始时(第 0 天),三种属性的值均为 0。</p>\n\n<p>随着游戏进程的进行,每一天玩家的三种属性都会对应<strong>增加</strong>,我们用一个二维数组 <code>increase</code> 来表示每天的增加情况。这个二维数组的每个元素是一个长度为 3 的一维数组,例如 <code>[[1,2,1],[3,4,2]]</code> 表示第一天三种属性分别增加 <code>1,2,1</code> 而第二天分别增加 <code>3,4,2</code>。</p>\n\n<p>所有剧情的触发条件也用一个二维数组 <code>requirements</code> 表示。这个二维数组的每个元素是一个长度为 3 的一维数组,对于某个剧情的触发条件 <code>c[i], r[i], h[i]</code>,如果当前 <code>C &gt;= c[i]</code> 且 <code>R &gt;= r[i]</code> 且 <code>H &gt;= h[i]</code> ,则剧情会被触发。</p>\n\n<p>根据所给信息,请计算每个剧情的触发时间,并以一个数组返回。如果某个剧情不会被触发,则该剧情对应的触发时间为 -1 。</p>\n\n<p><strong>示例 1</strong></p>\n\n<blockquote>\n<p>输入: <code>increase = [[2,8,4],[2,5,0],[10,9,8]]</code> <code>requirements = [[2,11,3],[15,10,7],[9,17,12],[8,1,14]]</code></p>\n\n<p>输出: <code>[2,-1,3,-1]</code></p>\n\n<p>解释:</p>\n\n<p>初始时C = 0R = 0H = 0</p>\n\n<p>第 1 天C = 2R = 8H = 4</p>\n\n<p>第 2 天C = 4R = 13H = 4此时触发剧情 0</p>\n\n<p>第 3 天C = 14R = 22H = 12此时触发剧情 2</p>\n\n<p>剧情 1 和 3 无法触发。</p>\n</blockquote>\n\n<p><strong>示例 2</strong></p>\n\n<blockquote>\n<p>输入: <code>increase = [[0,4,5],[4,8,8],[8,6,1],[10,10,0]]</code> <code>requirements = [[12,11,16],[20,2,6],[9,2,6],[10,18,3],[8,14,9]]</code></p>\n\n<p>输出: <code>[-1,4,3,3,3]</code></p>\n</blockquote>\n\n<p><strong>示例 3</strong></p>\n\n<blockquote>\n<p>输入: <code>increase = [[1,1,1]]</code> <code>requirements = [[0,0,0]]</code></p>\n\n<p>输出: <code>[0]</code></p>\n</blockquote>\n\n<p><strong>限制:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= increase.length &lt;= 10000</code></li>\n\t<li><code>1 &lt;= requirements.length &lt;= 100000</code></li>\n\t<li><code>0 &lt;= increase[i] &lt;= 10</code></li>\n\t<li><code>0 &lt;= requirements[i] &lt;= 100000</code></li>\n</ul>\n",
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