mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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189 lines
27 KiB
JSON
189 lines
27 KiB
JSON
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"title": "High-Access Employees",
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"content": "<p>You are given a 2D <strong>0-indexed</strong> array of strings, <code>access_times</code>, with size <code>n</code>. For each <code>i</code> where <code>0 <= i <= n - 1</code>, <code>access_times[i][0]</code> represents the name of an employee, and <code>access_times[i][1]</code> represents the access time of that employee. All entries in <code>access_times</code> are within the same day.</p>\n\n<p>The access time is represented as <strong>four digits</strong> using a <strong>24-hour</strong> time format, for example, <code>"0800"</code> or <code>"2250"</code>.</p>\n\n<p>An employee is said to be <strong>high-access</strong> if he has accessed the system <strong>three or more</strong> times within a <strong>one-hour period</strong>.</p>\n\n<p>Times with exactly one hour of difference are <strong>not</strong> considered part of the same one-hour period. For example, <code>"0815"</code> and <code>"0915"</code> are not part of the same one-hour period.</p>\n\n<p>Access times at the start and end of the day are <strong>not</strong> counted within the same one-hour period. For example, <code>"0005"</code> and <code>"2350"</code> are not part of the same one-hour period.</p>\n\n<p>Return <em>a list that contains the names of <strong>high-access</strong> employees with any order you want.</em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> access_times = [["a","0549"],["b","0457"],["a","0532"],["a","0621"],["b","0540"]]\n<strong>Output:</strong> ["a"]\n<strong>Explanation:</strong> "a" has three access times in the one-hour period of [05:32, 06:31] which are 05:32, 05:49, and 06:21.\nBut "b" does not have more than two access times at all.\nSo the answer is ["a"].</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> access_times = [["d","0002"],["c","0808"],["c","0829"],["e","0215"],["d","1508"],["d","1444"],["d","1410"],["c","0809"]]\n<strong>Output:</strong> ["c","d"]\n<strong>Explanation:</strong> "c" has three access times in the one-hour period of [08:08, 09:07] which are 08:08, 08:09, and 08:29.\n"d" has also three access times in the one-hour period of [14:10, 15:09] which are 14:10, 14:44, and 15:08.\nHowever, "e" has just one access time, so it can not be in the answer and the final answer is ["c","d"].</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> access_times = [["cd","1025"],["ab","1025"],["cd","1046"],["cd","1055"],["ab","1124"],["ab","1120"]]\n<strong>Output:</strong> ["ab","cd"]\n<strong>Explanation:</strong> "ab" has three access times in the one-hour period of [10:25, 11:24] which are 10:25, 11:20, and 11:24.\n"cd" has also three access times in the one-hour period of [10:25, 11:24] which are 10:25, 10:46, and 10:55.\nSo the answer is ["ab","cd"].</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= access_times.length <= 100</code></li>\n\t<li><code>access_times[i].length == 2</code></li>\n\t<li><code>1 <= access_times[i][0].length <= 10</code></li>\n\t<li><code>access_times[i][0]</code> consists only of English small letters.</li>\n\t<li><code>access_times[i][1].length == 4</code></li>\n\t<li><code>access_times[i][1]</code> is in 24-hour time format.</li>\n\t<li><code>access_times[i][1]</code> consists only of <code>'0'</code> to <code>'9'</code>.</li>\n</ul>\n",
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"translatedTitle": "高访问员工",
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"translatedContent": "<p>给你一个长度为 <code>n</code> 、下标从 <strong>0</strong> 开始的二维字符串数组 <code>access_times</code> 。对于每个 <code>i</code>（<code>0 <= i <= n - 1</code> ），<code>access_times[i][0]</code> 表示某位员工的姓名，<code>access_times[i][1]</code> 表示该员工的访问时间。<code>access_times</code> 中的所有条目都发生在同一天内。</p>\n\n<p>访问时间用 <strong>四位</strong> 数字表示， 符合 <strong>24 小时制</strong> ，例如 <code>\"0800\"</code> 或 <code>\"2250\"</code> 。</p>\n\n<p>如果员工在 <strong>同一小时内</strong> 访问系统 <strong>三次或更多</strong> ，则称其为 <strong>高访问</strong> 员工。</p>\n\n<p>时间间隔正好相差一小时的时间 <strong>不</strong> 被视为同一小时内。例如，<code>\"0815\"</code> 和 <code>\"0915\"</code> 不属于同一小时内。</p>\n\n<p>一天开始和结束时的访问时间不被计算为同一小时内。例如，<code>\"0005\"</code> 和 <code>\"2350\"</code> 不属于同一小时内。</p>\n\n<p>以列表形式，按任意顺序，返回所有 <strong>高访问</strong> 员工的姓名。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>access_times = [[\"a\",\"0549\"],[\"b\",\"0457\"],[\"a\",\"0532\"],[\"a\",\"0621\"],[\"b\",\"0540\"]]\n<strong>输出：</strong>[\"a\"]\n<strong>解释：</strong>\"a\" 在时间段 [05:32, 06:31] 内有三条访问记录，时间分别为 05:32 、05:49 和 06:21 。\n但是 \"b\" 的访问记录只有两条。\n因此，答案是 [\"a\"] 。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>access_times = [[\"d\",\"0002\"],[\"c\",\"0808\"],[\"c\",\"0829\"],[\"e\",\"0215\"],[\"d\",\"1508\"],[\"d\",\"1444\"],[\"d\",\"1410\"],[\"c\",\"0809\"]]\n<strong>输出：</strong>[\"c\",\"d\"]\n<strong>解释：</strong>\"c\" 在时间段 [08:08, 09:07] 内有三条访问记录，时间分别为 08:08 、08:09 和 08:29 。\n\"d\" 在时间段 [14:10, 15:09] 内有三条访问记录，时间分别为 14:10 、14:44 和 15:08 。\n然而，\"e\" 只有一条访问记录，因此不能包含在答案中，最终答案是 [\"c\",\"d\"] 。</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>access_times = [[\"cd\",\"1025\"],[\"ab\",\"1025\"],[\"cd\",\"1046\"],[\"cd\",\"1055\"],[\"ab\",\"1124\"],[\"ab\",\"1120\"]]\n<strong>输出：</strong>[\"ab\",\"cd\"]\n<strong>解释：</strong>\"ab\"在时间段 [10:25, 11:24] 内有三条访问记录，时间分别为 10:25 、11:20 和 11:24 。\n\"cd\" 在时间段 [10:25, 11:24] 内有三条访问记录，时间分别为 10:25 、10:46 和 10:55 。\n因此，答案是 [\"ab\",\"cd\"] 。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= access_times.length <= 100</code></li>\n\t<li><code>access_times[i].length == 2</code></li>\n\t<li><code>1 <= access_times[i][0].length <= 10</code></li>\n\t<li><code>access_times[i][0]</code> 仅由小写英文字母组成。</li>\n\t<li><code>access_times[i][1].length == 4</code></li>\n\t<li><code>access_times[i][1]</code> 采用24小时制表示时间。</li>\n\t<li><code>access_times[i][1]</code> 仅由数字 <code>'0'</code> 到 <code>'9'</code> 组成。</li>\n</ul>\n",
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