mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
191 lines
26 KiB
JSON
191 lines
26 KiB
JSON
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"title": "Escape the Spreading Fire",
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"content": "<p>You are given a <strong>0-indexed</strong> 2D integer array <code>grid</code> of size <code>m x n</code> which represents a field. Each cell has one of three values:</p>\n\n<ul>\n\t<li><code>0</code> represents grass,</li>\n\t<li><code>1</code> represents fire,</li>\n\t<li><code>2</code> represents a wall that you and fire cannot pass through.</li>\n</ul>\n\n<p>You are situated in the top-left cell, <code>(0, 0)</code>, and you want to travel to the safehouse at the bottom-right cell, <code>(m - 1, n - 1)</code>. Every minute, you may move to an <strong>adjacent</strong> grass cell. <strong>After</strong> your move, every fire cell will spread to all <strong>adjacent</strong> cells that are not walls.</p>\n\n<p>Return <em>the <strong>maximum</strong> number of minutes that you can stay in your initial position before moving while still safely reaching the safehouse</em>. If this is impossible, return <code>-1</code>. If you can <strong>always</strong> reach the safehouse regardless of the minutes stayed, return <code>10<sup>9</sup></code>.</p>\n\n<p>Note that even if the fire spreads to the safehouse immediately after you have reached it, it will be counted as safely reaching the safehouse.</p>\n\n<p>A cell is <strong>adjacent</strong> to another cell if the former is directly north, east, south, or west of the latter (i.e., their sides are touching).</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/10/ex1new.jpg\" style=\"width: 650px; height: 404px;\" />\n<pre>\n<strong>Input:</strong> grid = [[0,2,0,0,0,0,0],[0,0,0,2,2,1,0],[0,2,0,0,1,2,0],[0,0,2,2,2,0,2],[0,0,0,0,0,0,0]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The figure above shows the scenario where you stay in the initial position for 3 minutes.\nYou will still be able to safely reach the safehouse.\nStaying for more than 3 minutes will not allow you to safely reach the safehouse.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/10/ex2new2.jpg\" style=\"width: 515px; height: 150px;\" />\n<pre>\n<strong>Input:</strong> grid = [[0,0,0,0],[0,1,2,0],[0,2,0,0]]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> The figure above shows the scenario where you immediately move towards the safehouse.\nFire will spread to any cell you move towards and it is impossible to safely reach the safehouse.\nThus, -1 is returned.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/10/ex3new.jpg\" style=\"width: 174px; height: 150px;\" />\n<pre>\n<strong>Input:</strong> grid = [[0,0,0],[2,2,0],[1,2,0]]\n<strong>Output:</strong> 1000000000\n<strong>Explanation:</strong> The figure above shows the initial grid.\nNotice that the fire is contained by walls and you will always be able to safely reach the safehouse.\nThus, 10<sup>9</sup> is returned.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 <= m, n <= 300</code></li>\n\t<li><code>4 <= m * n <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>grid[i][j]</code> is either <code>0</code>, <code>1</code>, or <code>2</code>.</li>\n\t<li><code>grid[0][0] == grid[m - 1][n - 1] == 0</code></li>\n</ul>\n",
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"translatedTitle": "逃离火灾",
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"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始大小为 <code>m x n</code> 的二维整数数组 <code>grid</code> ，它表示一个网格图。每个格子为下面 3 个值之一：</p>\n\n<ul>\n\t<li><code>0</code> 表示草地。</li>\n\t<li><code>1</code> 表示着火的格子。</li>\n\t<li><code>2</code> 表示一座墙，你跟火都不能通过这个格子。</li>\n</ul>\n\n<p>一开始你在最左上角的格子 <code>(0, 0)</code> ，你想要到达最右下角的安全屋格子 <code>(m - 1, n - 1)</code> 。每一分钟，你可以移动到 <strong>相邻</strong> 的草地格子。每次你移动 <strong>之后</strong> ，着火的格子会扩散到所有不是墙的 <strong>相邻</strong> 格子。</p>\n\n<p>请你返回你在初始位置可以停留的 <strong>最多 </strong>分钟数，且停留完这段时间后你还能安全到达安全屋。如果无法实现，请你返回 <code>-1</code> 。如果不管你在初始位置停留多久，你 <strong>总是</strong> 能到达安全屋，请你返回 <code>10<sup>9</sup></code> 。</p>\n\n<p>注意，如果你到达安全屋后，火马上到了安全屋，这视为你能够安全到达安全屋。</p>\n\n<p>如果两个格子有共同边，那么它们为 <strong>相邻</strong> 格子。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/10/ex1new.jpg\" style=\"width: 650px; height: 404px;\"></p>\n\n<pre><b>输入：</b>grid = [[0,2,0,0,0,0,0],[0,0,0,2,2,1,0],[0,2,0,0,1,2,0],[0,0,2,2,2,0,2],[0,0,0,0,0,0,0]]\n<b>输出：</b>3\n<b>解释：</b>上图展示了你在初始位置停留 3 分钟后的情形。\n你仍然可以安全到达安全屋。\n停留超过 3 分钟会让你无法安全到达安全屋。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/10/ex2new2.jpg\" style=\"width: 515px; height: 150px;\"></p>\n\n<pre><b>输入：</b>grid = [[0,0,0,0],[0,1,2,0],[0,2,0,0]]\n<b>输出：</b>-1\n<b>解释：</b>上图展示了你马上开始朝安全屋移动的情形。\n火会蔓延到你可以移动的所有格子，所以无法安全到达安全屋。\n所以返回 -1 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/10/ex3new.jpg\" style=\"width: 174px; height: 150px;\"></p>\n\n<pre><b>输入：</b>grid = [[0,0,0],[2,2,0],[1,2,0]]\n<b>输出：</b>1000000000\n<b>解释：</b>上图展示了初始网格图。\n注意，由于火被墙围了起来，所以无论如何你都能安全到达安全屋。\n所以返回 10<sup>9</sup> 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 <= m, n <= 300</code></li>\n\t<li><code>4 <= m * n <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>grid[i][j]</code> 是 <code>0</code> ，<code>1</code> 或者 <code>2</code> 。</li>\n\t<li><code>grid[0][0] == grid[m - 1][n - 1] == 0</code></li>\n</ul>\n",
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"For some tile (x, y), how can we determine when, if ever, the fire will reach it?",
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"We can use multi-source BFS to find the earliest time the fire will reach each cell.",
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"Then, starting with a given t minutes of staying in the initial position, we can check if there is a safe path to the safehouse using the obtained information about the fire.",
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