leetcode-problemset/leetcode-cn/originData/er-cha-shu-de-shen-du-lcof.json

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        "question": {
            "questionId": "100319",
            "questionFrontendId": "LCR 175",
            "categoryTitle": "Algorithms",
            "boundTopicId": 87533,
            "title": "计算二叉树的深度",
            "titleSlug": "er-cha-shu-de-shen-du-lcof",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\r\n",
            "translatedTitle": "计算二叉树的深度",
            "translatedContent": "<p>某公司架构以二叉树形式记录，请返回该公司的层级数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://pic.leetcode.cn/1695101942-FSrxqu-image.png\" /></p>\n\n<pre>\n<strong>输入：</strong>root = [1, 2, 2, 3, null, null, 5, 4, null, null, 4]\n<strong>输出: </strong>4\n<strong>解释: </strong>上面示例中的二叉树的最大深度是 4，沿着路径 1 -&gt; 2 -&gt; 3 -&gt; 4 或 1 -&gt; 2 -&gt; 5 -&gt; 4 到达叶节点的最长路径上有 4 个节点。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>节点总数 &lt;= 10000</code></li>\n</ul>\n\n<p>注意：本题与主站 104&nbsp;题相同：<a href=\"https://leetcode-cn.com/problems/maximum-depth-of-binary-tree/\">https://leetcode-cn.com/problems/maximum-depth-of-binary-tree/</a></p>\n\n<p>&nbsp;</p>\n",
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                {
                    "name": "Tree",
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                    "translatedName": "树",
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                    "slug": "depth-first-search",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n    int calculateDepth(TreeNode* root) {\n\n    }\n};",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode(object):\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution(object):\n    def calculateDepth(self, root):\n        \"\"\"\n        :type root: Optional[TreeNode]\n        :rtype: int\n        \"\"\"",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     struct TreeNode *left;\n *     struct TreeNode *right;\n * };\n */\nint calculateDepth(struct TreeNode* root) {\n    \n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.left = (left===undefined ? null : left)\n *     this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number}\n */\nvar calculateDepth = function(root) {\n\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction calculateDepth(root: TreeNode | null): number {\n    \n};",
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                    "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           left: TreeNode.t() | nil,\n#           right: TreeNode.t() | nil\n#         }\n#   defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n  @spec calculate_depth(root :: TreeNode.t | nil) :: integer\n  def calculate_depth(root) do\n    \n  end\nend",
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