leetcode-problemset/leetcode-cn/originData/distinct-prime-factors-of-product-of-array.json

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            "title": "Distinct Prime Factors of Product of Array",
            "titleSlug": "distinct-prime-factors-of-product-of-array",
            "content": "<p>Given an array of positive integers <code>nums</code>, return <em>the number of <strong>distinct prime factors</strong> in the product of the elements of</em> <code>nums</code>.</p>\n\n<p><strong>Note</strong> that:</p>\n\n<ul>\n\t<li>A number greater than <code>1</code> is called <strong>prime</strong> if it is divisible by only <code>1</code> and itself.</li>\n\t<li>An integer <code>val1</code> is a factor of another integer <code>val2</code> if <code>val2 / val1</code> is an integer.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,4,3,7,10,6]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>\nThe product of all the elements in nums is: 2 * 4 * 3 * 7 * 10 * 6 = 10080 = 2<sup>5</sup> * 3<sup>2</sup> * 5 * 7.\nThere are 4 distinct prime factors so we return 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,4,8,16]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nThe product of all the elements in nums is: 2 * 4 * 8 * 16 = 1024 = 2<sup>10</sup>.\nThere is 1 distinct prime factor so we return 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>2 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "数组乘积中的不同质因数数目",
            "translatedContent": "<p>给你一个正整数数组 <code>nums</code> ，对 <code>nums</code> 所有元素求积之后，找出并返回乘积中 <strong>不同质因数</strong> 的数目。</p>\n\n<p><strong>注意：</strong></p>\n\n<ul>\n\t<li><strong>质数</strong> 是指大于 <code>1</code> 且仅能被 <code>1</code> 及自身整除的数字。</li>\n\t<li>如果 <code>val2 / val1</code> 是一个整数，则整数 <code>val1</code> 是另一个整数 <code>val2</code> 的一个因数。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [2,4,3,7,10,6]\n<strong>输出：</strong>4\n<strong>解释：</strong>\nnums 中所有元素的乘积是：2 * 4 * 3 * 7 * 10 * 6 = 10080 = 2<sup>5</sup> * 3<sup>2</sup> * 5 * 7 。\n共有 4 个不同的质因数，所以返回 4 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [2,4,8,16]\n<strong>输出：</strong>1\n<strong>解释：</strong>\nnums 中所有元素的乘积是：2 * 4 * 8 * 16 = 1024 = 2<sup>10</sup> 。\n共有 1 个不同的质因数，所以返回 1 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>2 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
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                "Do not multiply all the numbers together, as the product is too big to store.",
                "Think about how each individual number's prime factors contribute to the prime factors of the product of the entire array.",
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