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{
"data": {
"question": {
"questionId": "1140",
"questionFrontendId": "1054",
"categoryTitle": "Algorithms",
"boundTopicId": 5999,
"title": "Distant Barcodes",
"titleSlug": "distant-barcodes",
"content": "<p>In a warehouse, there is a row of barcodes, where the <code>i<sup>th</sup></code> barcode is <code>barcodes[i]</code>.</p>\n\n<p>Rearrange the barcodes so that no two adjacent barcodes are equal. You may return any answer, and it is guaranteed an answer exists.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> barcodes = [1,1,1,2,2,2]\n<strong>Output:</strong> [2,1,2,1,2,1]\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> barcodes = [1,1,1,1,2,2,3,3]\n<strong>Output:</strong> [1,3,1,3,1,2,1,2]\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= barcodes.length &lt;= 10000</code></li>\n\t<li><code>1 &lt;= barcodes[i] &lt;= 10000</code></li>\n</ul>\n",
"translatedTitle": "距离相等的条形码",
"translatedContent": "<p>在一个仓库里,有一排条形码,其中第 <code>i</code> 个条形码为&nbsp;<code>barcodes[i]</code>。</p>\n\n<p>请你重新排列这些条形码,使其中任意两个相邻的条形码不能相等。 你可以返回任何满足该要求的答案,此题保证存在答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>barcodes = [1,1,1,2,2,2]\n<strong>输出:</strong>[2,1,2,1,2,1]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>barcodes = [1,1,1,1,2,2,3,3]\n<strong>输出:</strong>[1,3,1,3,2,1,2,1]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= barcodes.length &lt;= 10000</code></li>\n\t<li><code>1 &lt;= barcodes[i] &lt;= 10000</code></li>\n</ul>\n",
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"lang": "C++",
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"code": "class Solution {\npublic:\n vector<int> rearrangeBarcodes(vector<int>& barcodes) {\n\n }\n};",
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"lang": "Python",
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"code": "class Solution(object):\n def rearrangeBarcodes(self, barcodes):\n \"\"\"\n :type barcodes: List[int]\n :rtype: List[int]\n \"\"\"",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* rearrangeBarcodes(int* barcodes, int barcodesSize, int* returnSize) {\n \n}",
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"code": "public class Solution {\n public int[] RearrangeBarcodes(int[] barcodes) {\n\n }\n}",
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"code": "/**\n * @param {number[]} barcodes\n * @return {number[]}\n */\nvar rearrangeBarcodes = function(barcodes) {\n\n};",
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"code": "class Solution {\n\n /**\n * @param Integer[] $barcodes\n * @return Integer[]\n */\n function rearrangeBarcodes($barcodes) {\n\n }\n}",
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"code": "impl Solution {\n pub fn rearrange_barcodes(barcodes: Vec<i32>) -> Vec<i32> {\n\n }\n}",
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"code": "defmodule Solution do\n @spec rearrange_barcodes(barcodes :: [integer]) :: [integer]\n def rearrange_barcodes(barcodes) do\n \n end\nend",
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"hints": [
"We want to always choose the most common or second most common element to write next. What data structure allows us to query this effectively?"
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