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{
"data": {
"question": {
"questionId": "2352",
"questionFrontendId": "2241",
"categoryTitle": "Algorithms",
"boundTopicId": 1422461,
"title": "Design an ATM Machine",
"titleSlug": "design-an-atm-machine",
"content": "<p>There is an ATM machine that stores banknotes of <code>5</code> denominations: <code>20</code>, <code>50</code>, <code>100</code>, <code>200</code>, and <code>500</code> dollars. Initially the ATM is empty. The user can use the machine to deposit or withdraw any amount of money.</p>\n\n<p>When withdrawing, the machine prioritizes using banknotes of <strong>larger</strong> values.</p>\n\n<ul>\n\t<li>For example, if you want to withdraw <code>$300</code> and there are <code>2</code> <code>$50</code> banknotes, <code>1</code> <code>$100</code> banknote, and <code>1</code> <code>$200</code> banknote, then the machine will use the <code>$100</code> and <code>$200</code> banknotes.</li>\n\t<li>However, if you try to withdraw <code>$600</code> and there are <code>3</code> <code>$200</code> banknotes and <code>1</code> <code>$500</code> banknote, then the withdraw request will be rejected because the machine will first try to use the <code>$500</code> banknote and then be unable to use banknotes to complete the remaining <code>$100</code>. Note that the machine is <strong>not</strong> allowed to use the <code>$200</code> banknotes instead of the <code>$500</code> banknote.</li>\n</ul>\n\n<p>Implement the ATM class:</p>\n\n<ul>\n\t<li><code>ATM()</code> Initializes the ATM object.</li>\n\t<li><code>void deposit(int[] banknotesCount)</code> Deposits new banknotes in the order <code>$20</code>, <code>$50</code>, <code>$100</code>, <code>$200</code>, and <code>$500</code>.</li>\n\t<li><code>int[] withdraw(int amount)</code> Returns an array of length <code>5</code> of the number of banknotes that will be handed to the user in the order <code>$20</code>, <code>$50</code>, <code>$100</code>, <code>$200</code>, and <code>$500</code>, and update the number of banknotes in the ATM after withdrawing. Returns <code>[-1]</code> if it is not possible (do <strong>not</strong> withdraw any banknotes in this case).</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input</strong>\n[&quot;ATM&quot;, &quot;deposit&quot;, &quot;withdraw&quot;, &quot;deposit&quot;, &quot;withdraw&quot;, &quot;withdraw&quot;]\n[[], [[0,0,1,2,1]], [600], [[0,1,0,1,1]], [600], [550]]\n<strong>Output</strong>\n[null, null, [0,0,1,0,1], null, [-1], [0,1,0,0,1]]\n\n<strong>Explanation</strong>\nATM atm = new ATM();\natm.deposit([0,0,1,2,1]); // Deposits 1 $100 banknote, 2 $200 banknotes,\n // and 1 $500 banknote.\natm.withdraw(600); // Returns [0,0,1,0,1]. The machine uses 1 $100 banknote\n // and 1 $500 banknote. The banknotes left over in the\n // machine are [0,0,0,2,0].\natm.deposit([0,1,0,1,1]); // Deposits 1 $50, $200, and $500 banknote.\n // The banknotes in the machine are now [0,1,0,3,1].\natm.withdraw(600); // Returns [-1]. The machine will try to use a $500 banknote\n // and then be unable to complete the remaining $100,\n // so the withdraw request will be rejected.\n // Since the request is rejected, the number of banknotes\n // in the machine is not modified.\natm.withdraw(550); // Returns [0,1,0,0,1]. The machine uses 1 $50 banknote\n // and 1 $500 banknote.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>banknotesCount.length == 5</code></li>\n\t<li><code>0 &lt;= banknotesCount[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= amount &lt;= 10<sup>9</sup></code></li>\n\t<li>At most <code>5000</code> calls <strong>in total</strong> will be made to <code>withdraw</code> and <code>deposit</code>.</li>\n\t<li>At least <strong>one</strong> call will be made to each function <code>withdraw</code> and <code>deposit</code>.</li>\n\t<li>Sum of <code>banknotesCount[i]</code> in all deposits doesn&#39;t exceed <code>10<sup>9</sup></code></li>\n</ul>\n",
"translatedTitle": "设计一个 ATM 机器",
"translatedContent": "<p>一个 ATM 机器,存有&nbsp;<code>5</code>&nbsp;种面值的钞票:<code>20</code>&nbsp;<code>50</code>&nbsp;<code>100</code>&nbsp;<code>200</code>&nbsp;和&nbsp;<code>500</code>&nbsp;美元。初始时ATM 机是空的。用户可以用它存或者取任意数目的钱。</p>\n\n<p>取款时,机器会优先取 <b>较大</b>&nbsp;数额的钱。</p>\n\n<ul>\n\t<li>比方说,你想取&nbsp;<code>$300</code>&nbsp;,并且机器里有&nbsp;<code>2</code>&nbsp;张 <code>$50</code>&nbsp;的钞票,<code>1</code>&nbsp;张&nbsp;<code>$100</code>&nbsp;的钞票和<code>1</code>&nbsp;张&nbsp;<code>$200</code>&nbsp;的钞票,那么机器会取出&nbsp;<code>$100</code> 和&nbsp;<code>$200</code>&nbsp;的钞票。</li>\n\t<li>但是,如果你想取&nbsp;<code>$600</code>&nbsp;,机器里有&nbsp;<code>3</code>&nbsp;张&nbsp;<code>$200</code>&nbsp;的钞票和<code>1</code>&nbsp;张&nbsp;<code>$500</code>&nbsp;的钞票,那么取款请求会被拒绝,因为机器会先取出&nbsp;<code>$500</code>&nbsp;的钞票,然后无法取出剩余的&nbsp;<code>$100</code>&nbsp;。注意,因为有&nbsp;<code>$500</code>&nbsp;钞票的存在,机器&nbsp;<strong>不能</strong>&nbsp;取&nbsp;<code>$200</code>&nbsp;的钞票。</li>\n</ul>\n\n<p>请你实现 ATM 类:</p>\n\n<ul>\n\t<li><code>ATM()</code>&nbsp;初始化 ATM 对象。</li>\n\t<li><code>void deposit(int[] banknotesCount)</code>&nbsp;分别存入&nbsp;<code>$20</code>&nbsp;<code>$50</code><code>$100</code><code>$200</code>&nbsp;和&nbsp;<code>$500</code>&nbsp;钞票的数目。</li>\n\t<li><code>int[] withdraw(int amount)</code>&nbsp;返回一个长度为&nbsp;<code>5</code>&nbsp;的数组,分别表示&nbsp;<code>$20</code>&nbsp;<code>$50</code><code>$100</code>&nbsp;<code>$200</code>&nbsp;和&nbsp;<code>$500</code>&nbsp;钞票的数目,并且更新 ATM 机里取款后钞票的剩余数量。如果无法取出指定数额的钱,请返回&nbsp;<code>[-1]</code>&nbsp;(这种情况下 <strong>不</strong>&nbsp;取出任何钞票)。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>\n[\"ATM\", \"deposit\", \"withdraw\", \"deposit\", \"withdraw\", \"withdraw\"]\n[[], [[0,0,1,2,1]], [600], [[0,1,0,1,1]], [600], [550]]\n<strong>输出:</strong>\n[null, null, [0,0,1,0,1], null, [-1], [0,1,0,0,1]]\n\n<strong>解释:</strong>\nATM atm = new ATM();\natm.deposit([0,0,1,2,1]); // 存入 1 张 $100 2 张 $200 和 1 张 $500 的钞票。\natm.withdraw(600); // 返回 [0,0,1,0,1] 。机器返回 1 张 $100 和 1 张 $500 的钞票。机器里剩余钞票的数量为 [0,0,0,2,0] 。\natm.deposit([0,1,0,1,1]); // 存入 1 张 $50 1 张 $200 和 1 张 $500 的钞票。\n // 机器中剩余钞票数量为 [0,1,0,3,1] 。\natm.withdraw(600); // 返回 [-1] 。机器会尝试取出 $500 的钞票,然后无法得到剩余的 $100 ,所以取款请求会被拒绝。\n // 由于请求被拒绝,机器中钞票的数量不会发生改变。\natm.withdraw(550); // 返回 [0,1,0,0,1] ,机器会返回 1 张 $50 的钞票和 1 张 $500 的钞票。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>banknotesCount.length == 5</code></li>\n\t<li><code>0 &lt;= banknotesCount[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= amount &lt;= 10<sup>9</sup></code></li>\n\t<li><strong>总共</strong>&nbsp;最多有&nbsp;<code>5000</code>&nbsp;次&nbsp;<code>withdraw</code> 和&nbsp;<code>deposit</code>&nbsp;的调用。</li>\n\t<li><span style=\"\">函数 </span><code>withdraw</code> 和&nbsp;<code>deposit</code>&nbsp;至少各有 <strong>一次&nbsp;</strong>调用。</li>\n</ul>\n",
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"lang": "C++",
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"code": "class ATM {\npublic:\n ATM() {\n\n }\n \n void deposit(vector<int> banknotesCount) {\n\n }\n \n vector<int> withdraw(int amount) {\n\n }\n};\n\n/**\n * Your ATM object will be instantiated and called as such:\n * ATM* obj = new ATM();\n * obj->deposit(banknotesCount);\n * vector<int> param_2 = obj->withdraw(amount);\n */",
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"code": "class ATM {\n\n public ATM() {\n\n }\n \n public void deposit(int[] banknotesCount) {\n\n }\n \n public int[] withdraw(int amount) {\n\n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * ATM obj = new ATM();\n * obj.deposit(banknotesCount);\n * int[] param_2 = obj.withdraw(amount);\n */",
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"code": "class ATM(object):\n\n def __init__(self):\n\n\n def deposit(self, banknotesCount):\n \"\"\"\n :type banknotesCount: List[int]\n :rtype: None\n \"\"\"\n\n\n def withdraw(self, amount):\n \"\"\"\n :type amount: int\n :rtype: List[int]\n \"\"\"\n\n\n\n# Your ATM object will be instantiated and called as such:\n# obj = ATM()\n# obj.deposit(banknotesCount)\n# param_2 = obj.withdraw(amount)",
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"code": "class ATM:\n\n def __init__(self):\n\n\n def deposit(self, banknotesCount: List[int]) -> None:\n\n\n def withdraw(self, amount: int) -> List[int]:\n\n\n\n# Your ATM object will be instantiated and called as such:\n# obj = ATM()\n# obj.deposit(banknotesCount)\n# param_2 = obj.withdraw(amount)",
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"code": "\n\n\ntypedef struct {\n \n} ATM;\n\n\nATM* aTMCreate() {\n \n}\n\nvoid aTMDeposit(ATM* obj, int* banknotesCount, int banknotesCountSize) {\n \n}\n\nint* aTMWithdraw(ATM* obj, int amount, int* retSize) {\n \n}\n\nvoid aTMFree(ATM* obj) {\n \n}\n\n/**\n * Your ATM struct will be instantiated and called as such:\n * ATM* obj = aTMCreate();\n * aTMDeposit(obj, banknotesCount, banknotesCountSize);\n \n * int* param_2 = aTMWithdraw(obj, amount, retSize);\n \n * aTMFree(obj);\n*/",
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"code": "public class ATM {\n\n public ATM() {\n\n }\n \n public void Deposit(int[] banknotesCount) {\n\n }\n \n public int[] Withdraw(int amount) {\n\n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * ATM obj = new ATM();\n * obj.Deposit(banknotesCount);\n * int[] param_2 = obj.Withdraw(amount);\n */",
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"lang": "JavaScript",
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"code": "\nvar ATM = function() {\n\n};\n\n/** \n * @param {number[]} banknotesCount\n * @return {void}\n */\nATM.prototype.deposit = function(banknotesCount) {\n\n};\n\n/** \n * @param {number} amount\n * @return {number[]}\n */\nATM.prototype.withdraw = function(amount) {\n\n};\n\n/**\n * Your ATM object will be instantiated and called as such:\n * var obj = new ATM()\n * obj.deposit(banknotesCount)\n * var param_2 = obj.withdraw(amount)\n */",
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"code": "class ATM {\n constructor() {\n \n }\n\n deposit(banknotesCount: number[]): void {\n \n }\n\n withdraw(amount: number): number[] {\n \n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * var obj = new ATM()\n * obj.deposit(banknotesCount)\n * var param_2 = obj.withdraw(amount)\n */",
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"lang": "PHP",
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"code": "class ATM {\n /**\n */\n function __construct() {\n\n }\n\n /**\n * @param Integer[] $banknotesCount\n * @return NULL\n */\n function deposit($banknotesCount) {\n\n }\n\n /**\n * @param Integer $amount\n * @return Integer[]\n */\n function withdraw($amount) {\n\n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * $obj = ATM();\n * $obj->deposit($banknotesCount);\n * $ret_2 = $obj->withdraw($amount);\n */",
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"lang": "Swift",
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"code": "\nclass ATM {\n\n init() {\n\n }\n \n func deposit(_ banknotesCount: [Int]) {\n\n }\n \n func withdraw(_ amount: Int) -> [Int] {\n\n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * let obj = ATM()\n * obj.deposit(banknotesCount)\n * let ret_2: [Int] = obj.withdraw(amount)\n */",
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"lang": "Kotlin",
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"code": "class ATM() {\n\n fun deposit(banknotesCount: IntArray) {\n\n }\n\n fun withdraw(amount: Int): IntArray {\n\n }\n\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * var obj = ATM()\n * obj.deposit(banknotesCount)\n * var param_2 = obj.withdraw(amount)\n */",
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"code": "class ATM {\n\n ATM() {\n \n }\n \n void deposit(List<int> banknotesCount) {\n \n }\n \n List<int> withdraw(int amount) {\n \n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * ATM obj = ATM();\n * obj.deposit(banknotesCount);\n * List<int> param2 = obj.withdraw(amount);\n */",
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"lang": "Go",
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"code": "type ATM struct {\n\n}\n\n\nfunc Constructor() ATM {\n\n}\n\n\nfunc (this *ATM) Deposit(banknotesCount []int) {\n\n}\n\n\nfunc (this *ATM) Withdraw(amount int) []int {\n\n}\n\n\n/**\n * Your ATM object will be instantiated and called as such:\n * obj := Constructor();\n * obj.Deposit(banknotesCount);\n * param_2 := obj.Withdraw(amount);\n */",
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"lang": "Ruby",
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"code": "class ATM\n def initialize()\n\n end\n\n\n=begin\n :type banknotes_count: Integer[]\n :rtype: Void\n=end\n def deposit(banknotes_count)\n\n end\n\n\n=begin\n :type amount: Integer\n :rtype: Integer[]\n=end\n def withdraw(amount)\n\n end\n\n\nend\n\n# Your ATM object will be instantiated and called as such:\n# obj = ATM.new()\n# obj.deposit(banknotes_count)\n# param_2 = obj.withdraw(amount)",
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"code": "class ATM() {\n\n def deposit(banknotesCount: Array[Int]) {\n\n }\n\n def withdraw(amount: Int): Array[Int] = {\n\n }\n\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * var obj = new ATM()\n * obj.deposit(banknotesCount)\n * var param_2 = obj.withdraw(amount)\n */",
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"code": "struct ATM {\n\n}\n\n\n/**\n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl ATM {\n\n fn new() -> Self {\n\n }\n \n fn deposit(&self, banknotes_count: Vec<i32>) {\n\n }\n \n fn withdraw(&self, amount: i32) -> Vec<i32> {\n\n }\n}\n\n/**\n * Your ATM object will be instantiated and called as such:\n * let obj = ATM::new();\n * obj.deposit(banknotesCount);\n * let ret_2: Vec<i32> = obj.withdraw(amount);\n */",
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"code": "(define atm%\n (class object%\n (super-new)\n \n (init-field)\n \n ; deposit : (listof exact-integer?) -> void?\n (define/public (deposit banknotes-count)\n )\n ; withdraw : exact-integer? -> (listof exact-integer?)\n (define/public (withdraw amount)\n )))\n\n;; Your atm% object will be instantiated and called as such:\n;; (define obj (new atm%))\n;; (send obj deposit banknotes-count)\n;; (define param_2 (send obj withdraw amount))",
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"code": "-spec atm_init_() -> any().\natm_init_() ->\n .\n\n-spec atm_deposit(BanknotesCount :: [integer()]) -> any().\natm_deposit(BanknotesCount) ->\n .\n\n-spec atm_withdraw(Amount :: integer()) -> [integer()].\natm_withdraw(Amount) ->\n .\n\n\n%% Your functions will be called as such:\n%% atm_init_(),\n%% atm_deposit(BanknotesCount),\n%% Param_2 = atm_withdraw(Amount),\n\n%% atm_init_ will be called before every test case, in which you can do some necessary initializations.",
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"code": "defmodule ATM do\n @spec init_() :: any\n def init_() do\n \n end\n\n @spec deposit(banknotes_count :: [integer]) :: any\n def deposit(banknotes_count) do\n \n end\n\n @spec withdraw(amount :: integer) :: [integer]\n def withdraw(amount) do\n \n end\nend\n\n# Your functions will be called as such:\n# ATM.init_()\n# ATM.deposit(banknotes_count)\n# param_2 = ATM.withdraw(amount)\n\n# ATM.init_ will be called before every test case, in which you can do some necessary initializations.",
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"hints": [
"Store the number of banknotes of each denomination.",
"Can you use math to quickly evaluate a withdrawal request?"
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