leetcode-problemset/leetcode-cn/originData/count-nodes-equal-to-average-of-subtree.json

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        "question": {
            "questionId": "2347",
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            "categoryTitle": "Algorithms",
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            "title": "Count Nodes Equal to Average of Subtree",
            "titleSlug": "count-nodes-equal-to-average-of-subtree",
            "content": "<p>Given the <code>root</code> of a binary tree, return <em>the number of nodes where the value of the node is equal to the <strong>average</strong> of the values in its <strong>subtree</strong></em>.</p>\n\n<p><strong>Note:</strong></p>\n\n<ul>\n\t<li>The <strong>average</strong> of <code>n</code> elements is the <strong>sum</strong> of the <code>n</code> elements divided by <code>n</code> and <strong>rounded down</strong> to the nearest integer.</li>\n\t<li>A <strong>subtree</strong> of <code>root</code> is a tree consisting of <code>root</code> and all of its descendants.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/03/15/image-20220315203925-1.png\" style=\"width: 300px; height: 212px;\" />\n<pre>\n<strong>Input:</strong> root = [4,8,5,0,1,null,6]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> \nFor the node with value 4: The average of its subtree is (4 + 8 + 5 + 0 + 1 + 6) / 6 = 24 / 6 = 4.\nFor the node with value 5: The average of its subtree is (5 + 6) / 2 = 11 / 2 = 5.\nFor the node with value 0: The average of its subtree is 0 / 1 = 0.\nFor the node with value 1: The average of its subtree is 1 / 1 = 1.\nFor the node with value 6: The average of its subtree is 6 / 1 = 6.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/03/26/image-20220326133920-1.png\" style=\"width: 80px; height: 76px;\" />\n<pre>\n<strong>Input:</strong> root = [1]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> For the node with value 1: The average of its subtree is 1 / 1 = 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 1000]</code>.</li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "统计值等于子树平均值的节点数",
            "translatedContent": "<p>给你一棵二叉树的根节点 <code>root</code> ，找出并返回满足要求的节点数，要求节点的值等于其 <strong>子树</strong> 中值的 <strong>平均值</strong> 。</p>\n\n<p><strong>注意：</strong></p>\n\n<ul>\n\t<li><code>n</code> 个元素的平均值可以由 <code>n</code> 个元素 <strong>求和</strong> 然后再除以 <code>n</code> ，并 <strong>向下舍入</strong> 到最近的整数。</li>\n\t<li><code>root</code> 的 <strong>子树</strong> 由 <code>root</code> 和它的所有后代组成。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/03/15/image-20220315203925-1.png\" style=\"width: 300px; height: 212px;\">\n<pre><strong>输入：</strong>root = [4,8,5,0,1,null,6]\n<strong>输出：</strong>5\n<strong>解释：</strong>\n对值为 4 的节点：子树的平均值 (4 + 8 + 5 + 0 + 1 + 6) / 6 = 24 / 6 = 4 。\n对值为 5 的节点：子树的平均值 (5 + 6) / 2 = 11 / 2 = 5 。\n对值为 0 的节点：子树的平均值 0 / 1 = 0 。\n对值为 1 的节点：子树的平均值 1 / 1 = 1 。\n对值为 6 的节点：子树的平均值 6 / 1 = 6 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/03/26/image-20220326133920-1.png\" style=\"width: 80px; height: 76px;\">\n<pre><strong>输入：</strong>root = [1]\n<strong>输出：</strong>1\n<strong>解释：</strong>对值为 1 的节点：子树的平均值 1 / 1 = 1。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目在范围 <code>[1, 1000]</code> 内</li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     struct TreeNode *left;\n *     struct TreeNode *right;\n * };\n */\nint averageOfSubtree(struct TreeNode* root) {\n    \n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\nfunc averageOfSubtree(root *TreeNode) int {\n    \n}",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode\n#     attr_accessor :val, :left, :right\n#     def initialize(val = 0, left = nil, right = nil)\n#         @val = val\n#         @left = left\n#         @right = right\n#     end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef average_of_subtree(root)\n    \nend",
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                    "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n//   pub val: i32,\n//   pub left: Option<Rc<RefCell<TreeNode>>>,\n//   pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n//   #[inline]\n//   pub fn new(val: i32) -> Self {\n//     TreeNode {\n//       val,\n//       left: None,\n//       right: None\n//     }\n//   }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n    pub fn average_of_subtree(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {\n        \n    }\n}",
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                    "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n  (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n  (tree-node val #f #f))\n\n|#\n\n(define/contract (average-of-subtree root)\n  (-> (or/c tree-node? #f) exact-integer?)\n  )",
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                "What information do we need to calculate the average? We need the sum of the values and the number of values.",
                "Create a recursive function that returns the size of a node’s subtree, and the sum of the values of its subtree."
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