mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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150 lines
30 KiB
JSON
150 lines
30 KiB
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"title": "Construct Quad Tree",
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"content": "<p>Given a <code>n * n</code> matrix <code>grid</code> of <code>0's</code> and <code>1's</code> only. We want to represent <code>grid</code> with a Quad-Tree.</p>\n\n<p>Return <em>the root of the Quad-Tree representing </em><code>grid</code>.</p>\n\n<p>A Quad-Tree is a tree data structure in which each internal node has exactly four children. Besides, each node has two attributes:</p>\n\n<ul>\n\t<li><code>val</code>: True if the node represents a grid of 1's or False if the node represents a grid of 0's. Notice that you can assign the <code>val</code> to True or False when <code>isLeaf</code> is False, and both are accepted in the answer.</li>\n\t<li><code>isLeaf</code>: True if the node is a leaf node on the tree or False if the node has four children.</li>\n</ul>\n\n<pre>\nclass Node {\n public boolean val;\n public boolean isLeaf;\n public Node topLeft;\n public Node topRight;\n public Node bottomLeft;\n public Node bottomRight;\n}</pre>\n\n<p>We can construct a Quad-Tree from a two-dimensional area using the following steps:</p>\n\n<ol>\n\t<li>If the current grid has the same value (i.e all <code>1's</code> or all <code>0's</code>) set <code>isLeaf</code> True and set <code>val</code> to the value of the grid and set the four children to Null and stop.</li>\n\t<li>If the current grid has different values, set <code>isLeaf</code> to False and set <code>val</code> to any value and divide the current grid into four sub-grids as shown in the photo.</li>\n\t<li>Recurse for each of the children with the proper sub-grid.</li>\n</ol>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/11/new_top.png\" style=\"width: 777px; height: 181px;\" />\n<p>If you want to know more about the Quad-Tree, you can refer to the <a href=\"https://en.wikipedia.org/wiki/Quadtree\">wiki</a>.</p>\n\n<p><strong>Quad-Tree format:</strong></p>\n\n<p>You don't need to read this section for solving the problem. This is only if you want to understand the output format here. The output represents the serialized format of a Quad-Tree using level order traversal, where <code>null</code> signifies a path terminator where no node exists below.</p>\n\n<p>It is very similar to the serialization of the binary tree. The only difference is that the node is represented as a list <code>[isLeaf, val]</code>.</p>\n\n<p>If the value of <code>isLeaf</code> or <code>val</code> is True we represent it as <strong>1</strong> in the list <code>[isLeaf, val]</code> and if the value of <code>isLeaf</code> or <code>val</code> is False we represent it as <strong>0</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/11/grid1.png\" style=\"width: 777px; height: 99px;\" />\n<pre>\n<strong>Input:</strong> grid = [[0,1],[1,0]]\n<strong>Output:</strong> [[0,1],[1,0],[1,1],[1,1],[1,0]]\n<strong>Explanation:</strong> The explanation of this example is shown below:\nNotice that 0 represents False and 1 represents True in the photo representing the Quad-Tree.\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/e1tree.png\" style=\"width: 777px; height: 186px;\" />\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/e2mat.png\" style=\"width: 777px; height: 343px;\" /></p>\n\n<pre>\n<strong>Input:</strong> grid = [[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,1,1,1,1],[1,1,1,1,1,1,1,1],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0]]\n<strong>Output:</strong> [[0,1],[1,1],[0,1],[1,1],[1,0],null,null,null,null,[1,0],[1,0],[1,1],[1,1]]\n<strong>Explanation:</strong> All values in the grid are not the same. We divide the grid into four sub-grids.\nThe topLeft, bottomLeft and bottomRight each has the same value.\nThe topRight have different values so we divide it into 4 sub-grids where each has the same value.\nExplanation is shown in the photo below:\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/e2tree.png\" style=\"width: 777px; height: 328px;\" />\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == grid.length == grid[i].length</code></li>\n\t<li><code>n == 2<sup>x</sup></code> where <code>0 <= x <= 6</code></li>\n</ul>\n",
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"translatedTitle": "建立四叉树",
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"translatedContent": "<p>给你一个 <code>n * n</code> 矩阵 <code>grid</code> ,矩阵由若干 <code>0</code> 和 <code>1</code> 组成。请你用四叉树表示该矩阵 <code>grid</code> 。</p>\n\n<p>你需要返回能表示矩阵 <code>grid</code> 的 四叉树 的根结点。</p>\n\n<p>四叉树数据结构中,每个内部节点只有四个子节点。此外,每个节点都有两个属性:</p>\n\n<ul>\n\t<li><code>val</code>:储存叶子结点所代表的区域的值。1 对应 <strong>True</strong>,0 对应 <strong>False</strong>。注意,当 <code>isLeaf</code> 为 <strong>False </strong>时,你可以把 <strong>True</strong> 或者 <strong>False</strong> 赋值给节点,两种值都会被判题机制 <strong>接受</strong> 。</li>\n\t<li><code>isLeaf</code>: 当这个节点是一个叶子结点时为 <strong>True</strong>,如果它有 4 个子节点则为 <strong>False</strong> 。</li>\n</ul>\n\n<pre>\nclass Node {\n public boolean val;\n public boolean isLeaf;\n public Node topLeft;\n public Node topRight;\n public Node bottomLeft;\n public Node bottomRight;\n}</pre>\n\n<p>我们可以按以下步骤为二维区域构建四叉树:</p>\n\n<ol>\n\t<li>如果当前网格的值相同(即,全为 <code>0</code> 或者全为 <code>1</code>),将 <code>isLeaf</code> 设为 True ,将 <code>val</code> 设为网格相应的值,并将四个子节点都设为 Null 然后停止。</li>\n\t<li>如果当前网格的值不同,将 <code>isLeaf</code> 设为 False, 将 <code>val</code> 设为任意值,然后如下图所示,将当前网格划分为四个子网格。</li>\n\t<li>使用适当的子网格递归每个子节点。</li>\n</ol>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/11/new_top.png\" style=\"height: 181px; width: 777px;\" /></p>\n\n<p>如果你想了解更多关于四叉树的内容,可以参考 <a href=\"https://en.wikipedia.org/wiki/Quadtree\">wiki</a> 。</p>\n\n<p><strong>四叉树格式:</strong></p>\n\n<p>你不需要阅读本节来解决这个问题。只有当你想了解输出格式时才会这样做。输出为使用层序遍历后四叉树的序列化形式,其中 <code>null</code> 表示路径终止符,其下面不存在节点。</p>\n\n<p>它与二叉树的序列化非常相似。唯一的区别是节点以列表形式表示 <code>[isLeaf, val]</code> 。</p>\n\n<p>如果 <code>isLeaf</code> 或者 <code>val</code> 的值为 True ,则表示它在列表 <code>[isLeaf, val]</code> 中的值为 <strong>1</strong> ;如果 <code>isLeaf</code> 或者 <code>val</code> 的值为 False ,则表示值为 <strong>0 </strong>。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/11/grid1.png\" style=\"height: 99px; width: 777px;\" /></p>\n\n<pre>\n<strong>输入:</strong>grid = [[0,1],[1,0]]\n<strong>输出:</strong>[[0,1],[1,0],[1,1],[1,1],[1,0]]\n<strong>解释:</strong>此示例的解释如下:\n请注意,在下面四叉树的图示中,0 表示 false,1 表示 True 。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/e1tree.png\" style=\"height: 186px; width: 777px;\" />\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/e2mat.png\" style=\"height: 343px; width: 777px;\" /></p>\n\n<pre>\n<strong>输入:</strong>grid = [[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,1,1,1,1],[1,1,1,1,1,1,1,1],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0],[1,1,1,1,0,0,0,0]]\n<strong>输出:</strong>[[0,1],[1,1],[0,1],[1,1],[1,0],null,null,null,null,[1,0],[1,0],[1,1],[1,1]]\n<strong>解释:</strong>网格中的所有值都不相同。我们将网格划分为四个子网格。\ntopLeft,bottomLeft 和 bottomRight 均具有相同的值。\ntopRight 具有不同的值,因此我们将其再分为 4 个子网格,这样每个子网格都具有相同的值。\n解释如下图所示:\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/e2tree.png\" style=\"height: 328px; width: 777px;\" />\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ol>\n\t<li><code>n == grid.length == grid[i].length</code></li>\n\t<li><code>n == 2<sup>x</sup></code> 其中 <code>0 <= x <= 6</code></li>\n</ol>\n",
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