leetcode-problemset/leetcode-cn/originData/apply-operations-to-maximize-frequency-score.json

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            "questionId": "3196",
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            "categoryTitle": "Algorithms",
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            "title": "Apply Operations to Maximize Frequency Score",
            "titleSlug": "apply-operations-to-maximize-frequency-score",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>You can perform the following operation on the array <strong>at most</strong> <code>k</code> times:</p>\n\n<ul>\n\t<li>Choose any index <code>i</code> from the array and <strong>increase</strong> or <strong>decrease</strong> <code>nums[i]</code> by <code>1</code>.</li>\n</ul>\n\n<p>The score of the final array is the <strong>frequency</strong> of the most frequent element in the array.</p>\n\n<p>Return <em>the <strong>maximum</strong> score you can achieve</em>.</p>\n\n<p>The frequency of an element is the number of occurences of that element in the array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,6,4], k = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can do the following operations on the array:\n- Choose i = 0, and increase the value of nums[0] by 1. The resulting array is [2,2,6,4].\n- Choose i = 3, and decrease the value of nums[3] by 1. The resulting array is [2,2,6,3].\n- Choose i = 3, and decrease the value of nums[3] by 1. The resulting array is [2,2,6,2].\nThe element 2 is the most frequent in the final array so our score is 3.\nIt can be shown that we cannot achieve a better score.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4,4,2,4], k = 0\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We cannot apply any operations so our score will be the frequency of the most frequent element in the original array, which is 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>14</sup></code></li>\n</ul>\n",
            "translatedTitle": "执行操作使频率分数最大",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;和一个整数&nbsp;<code>k</code>&nbsp;。</p>\n\n<p>你可以对数组执行 <strong>至多</strong>&nbsp;<code>k</code>&nbsp;次操作：</p>\n\n<ul>\n\t<li>从数组中选择一个下标 <code>i</code>&nbsp;，将&nbsp;<code>nums[i]</code> <strong>增加</strong>&nbsp;或者&nbsp;<strong>减少</strong>&nbsp;<code>1</code>&nbsp;。</li>\n</ul>\n\n<p>最终数组的频率分数定义为数组中众数的 <strong>频率</strong>&nbsp;。</p>\n\n<p>请你返回你可以得到的 <strong>最大</strong>&nbsp;频率分数。</p>\n\n<p>众数指的是数组中出现次数最多的数。一个元素的频率指的是数组中这个元素的出现次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,2,6,4], k = 3\n<b>输出：</b>3\n<b>解释：</b>我们可以对数组执行以下操作：\n- 选择 i = 0 ，将 nums[0] 增加 1 。得到数组 [2,2,6,4] 。\n- 选择 i = 3 ，将 nums[3] 减少 1 ，得到数组 [2,2,6,3] 。\n- 选择 i = 3 ，将 nums[3] 减少 1 ，得到数组 [2,2,6,2] 。\n元素 2 是最终数组中的众数，出现了 3 次，所以频率分数为 3 。\n3 是所有可行方案里的最大频率分数。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,4,4,2,4], k = 0\n<b>输出：</b>3\n<b>解释：</b>我们无法执行任何操作，所以得到的频率分数是原数组中众数的频率 3 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>14</sup></code></li>\n</ul>\n",
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                "If you sort the original array, it is optimal to apply the operations on one subarray such that all the elements of that subarray become equal.",
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